A solution is made containing \(20.8 \mathrm{~g}\) phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\) in \(425 \mathrm{~g}\) ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O} \mathrm{H}\right) .\) Calculate (a) the mole fraction of phenol, (b) the mass percent of phenol, (c) the molality of phenol.

Short Answer

Expert verified
(a) Mole fraction of phenol = 0.017 (b) Mass percent of phenol = 4.67 % (c) Molality of phenol = 0.479 \(mol/kg\)

Step by step solution

01

(Step 1: Calculate the number of moles for each substance)

Given masses of phenol and ethanol are \(20.8 \mathrm{~g}\) and \(425 \mathrm{~g}\), respectively. To get the number of moles for each substance, we need to divide the given mass by the molar mass of each substance. The molar masses of phenol \(\left(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{OH}\right)\) and ethanol \(\left(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH}\right)\) are \(94.11 \mathrm{~g/mol}\) and \(46.07 \mathrm{~g/mol}\), respectively. Thus, Moles of phenol = \(\frac{20.8}{94.11}\) Moles of ethanol = \(\frac{425}{46.07}\)
02

(Step 2: Calculate the mole fraction of phenol)

Mole fraction is the ratio of the moles of a particular component to the total moles of the system. Mole fraction of phenol = \(\frac{\text{Moles of phenol}}{\text{Total moles}}\) Total moles = Moles of phenol + Moles of ethanol Calculate the mole fraction of phenol from the above formula.
03

(Step 3: Calculate the mass percent of phenol)

Mass percent is the ratio of the mass of a particular component to the total mass of the system multiplied by 100 to get the percentage. Mass percent of phenol = \(\frac{\text{Mass of phenol}}{\text{Total mass}} \times 100\) Total mass = Mass of phenol + Mass of ethanol = \(20.8 \mathrm{~g}\) + \(425 \mathrm{~g}\) Calculate the mass percent of phenol using the formula above.
04

(Step 4: Calculate the molality of phenol)

Molality is defined as the number of moles of solute per kilogram of solvent. Molality of phenol = \(\frac{\text{Moles of phenol}}{\text{Mass of ethanol in kg}}\) The mass of ethanol should be converted to kilograms by dividing it by 1000. Calculate the molality of phenol using the formula above. Now, we have calculated all the required parameters: mole fraction, mass percent, and molality of phenol in the given solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose you had a balloon made of some highly flexible semipermeable membrane. The balloon is filled completely with a \(0.2 \mathrm{M}\) solution of some solute and is submerged in a \(0.1 \mathrm{M}\) solution of the same solute:

Explain how (a) a soap such as sodium stearate stabilizes a colloidal dispersion of oil droplets in water; (b) milk curdles upon addition of an acid.

The osmotic pressure of a \(0.010 \mathrm{M}\) aqueous solution of \(\mathrm{CaCl}_{2}\) is found to be 0.674 atm at \(25^{\circ}\) C. (a) Calculate the van't Hoff factor, \(i\), for the solution. (b) How would you expect the value of \(i\) to change as the solution becomes more concentrated? Explain.

At ordinary body temperature \(\left(37^{\circ} \mathrm{C}\right)\) the solubility of \(\mathrm{N}_{2}\) in water in contact with air at ordinary atmospheric pressure \((1.0 \mathrm{~atm})\) is \(0.015 \mathrm{~g} / \mathrm{L}\). Air is approximately \(78 \mathrm{~mol} \% \mathrm{~N}_{2}\). Calculate the number of moles of \(\mathrm{N}_{2}\) dissolved per liter of blood, which is essentially an aqueous solution. At a depth of \(100 \mathrm{ft}\) in water, the pressure is \(4.0 \mathrm{~atm}\). What is the solubility of \(\mathrm{N}_{2}\) from air in blood at this pressure? If a scuba diver suddenly surfaces from this depth, how many milliliters of \(\mathrm{N}_{2}\) gas, in the form of tiny bubbles, are released into the bloodstream from each liter of blood?

Explain why pressure substantially affects the solubility of \(\mathrm{O}_{2}\) in water but has little effect on the solubility of \(\mathrm{NaCl}\) in water.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free