Consider two reactions. Reaction (1) has a constant half-life, whereas reaction (2) has a half-life that gets longer as the reaction proceeds. What can you conclude about the rate laws of these reactions from these observations?

Short Answer

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From the information about the half-lives of reactions, we can infer that reaction (1) is a first-order reaction because it has a constant half-life. Thus, the rate law is formulated as \(rate = k_1[A_1]\), where \(k_1\) is the rate constant and \([A_1]\) is the concentration of the reactant. Conversely, reaction (2) is not a first-order reaction since its half-life increases as the reaction proceeds. The rate law form of reaction (2) could be either zeroth-order, second-order, or higher-order, not in the form \(rate = k_2[A_2]\). However, without further experimental data, we can't arrive at a precise conclusion about its order.

Step by step solution

01

Understanding half-lives and rate laws

Half-life is the time it takes for the concentration of a reactant to decrease by half. The rate law is an equation that describes the relationship between the reaction rate and the concentrations of the reactants. The order of the reaction is determined by the exponents of the concentration terms in the rate law equation. For first-order reactions, the rate law equation is: \(rate = k[A]\), where k is the rate constant, and [A] is the concentration of the reactant A. For first-order reactions, the half-life is constant and independent of the initial reactant concentration. In other words, it takes the same time to go from 100% to 50% of the reactant as it does to go from 50% to 25%. For other reaction orders, the half-life depends on the initial concentration of the reactants.
02

Identifying the rate law for reaction (1)

Since reaction (1) has a constant half-life, it is indicative of a first-order reaction. Therefore, the rate law for reaction (1) can be represented as: \(rate = k_1[A_1]\), where k_1 is the rate constant for reaction (1) and [A_1] is the concentration of reactant A for reaction (1).
03

Identifying the rate law for reaction (2)

As the half-life for reaction (2) gets longer as the reaction proceeds, it suggests that the reaction is not first-order; otherwise, the half-life would be constant. Therefore, we can conclude that the rate law for reaction (2) is not of the form \(rate = k_2[A_2]\), where k_2 is the rate constant for reaction (2) and [A_2] is the concentration of reactant A for reaction (2). This reaction could be a second-order or a higher-order reaction, depending on the experimental data. In general, a zeroth-order reaction and a second-order reaction have a half-life that depends on the initial concentration of the reactants, but given the information we have, we cannot say for sure which order it is. We can only conclude that reaction (2) is not a first-order reaction.
04

Conclusion

From the given information about the half-lives of the reactions, we can conclude that: 1. Reaction (1) is a first-order reaction with a rate law of the form \(rate = k_1[A_1]\). 2. Reaction (2) is not a first-order reaction, and its rate law must be of a different form, which could be either zeroth-order, second-order, or a higher-order. The exact form depends on the experimental data.

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Most popular questions from this chapter

(a) What are the units usually used to express the rates of reactions occurring in solution? (b) From your everyday experience, give two examples of the effects of temperature on the rates of reactions. (c) What is the difference between average rate and instantaneous rate?

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The reaction \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2}\) has the rate constant \(k=0.63 \mathrm{M}^{-1} \mathrm{~s}^{-1}\). Based on the units for \(k\), is the reaction first or second order in \(\mathrm{NO}_{2}\) ? If the initial concentration of \(\mathrm{NO}_{2}\) is \(0.100 \mathrm{M}\), how would you determine how long it would take for the concentration to decrease to \(0.025 \mathrm{M}\) ?

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The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at 30.0 min. Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

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