(a) The reaction \(\mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\frac{1}{2} \mathrm{O}_{2}(g)\) is first order. Near room temperature, the rate constant equals \(7.0 \times 10^{-4} \mathrm{~s}^{-1} .\) Calculate the half-life at this temperature. (b) At \(415^{\circ} \mathrm{C},\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}\) decomposes in the gas phase, \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}(g) \longrightarrow \mathrm{CH}_{4}(g)+\mathrm{CO}(g) .\) If the reaction is first order with a half-life of 56.3 min at this temperature, calculate the rate constant in \(\mathrm{s}^{-1}\).

Short Answer

Expert verified
(a) The half-life of the reaction at room temperature is \(t_{1/2} = 990\) seconds. (b) The rate constant for the reaction at 415°C is \(k = 2.05 × 10^{-4} s^{-1}\).

Step by step solution

01

Identify the given information

We are given that the reaction is a first-order reaction and the rate constant \(k = 7.0 × 10^{-4} s^{-1}\).
02

Apply the half-life formula

Now, we can plug the rate constant into the half-life formula for a first-order reaction: \[t_{1/2} = \frac{0.693}{7.0 × 10^{-4} s^{-1}}\]
03

Calculate the result

Dividing 0.693 by the rate constant, we get: \[t_{1/2} = 990 s\] So, the half-life of the reaction at room temperature is 990 seconds. (b) Calculate the rate constant at 415°C.
04

Identify the given information

We are given that the reaction is a first-order reaction with a half-life of \(t_{1/2} = 56.3\) minutes at 415°C.
05

Convert the half-life to seconds

Since the rate constant will be given in \(s^{-1}\), we need to convert the half-life to seconds: 56.3 minutes × 60 s/minute = 3378 s So, \(t_{1/2} = 3378 s\).
06

Apply the half-life formula

Now, we can use the half-life formula for a first-order reaction to find the rate constant: \[k = \frac{0.693}{t_{1/2}}\]
07

Calculate the result

Plugging in the half-life, we get: \[k = \frac{0.693}{3378 s}\] \[k = 2.05 × 10^{-4} s^{-1}\] So, the rate constant for the reaction at 415°C is \(2.05 × 10^{-4} s^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-life Calculation
Half-life, commonly represented by the symbol \(t_{1/2}\), is a critical concept in chemical kinetics that signifies the time required for the concentration of a reactant to decrease by half. In a first-order reaction, the half-life is independent of the initial concentration and can be calculated using the formula:

\[t_{1/2} = \frac{0.693}{k}\]
Here, \(k\) is the rate constant of the reaction. The constant 0.693 is derived from the natural logarithm of 2, due to the relationship between half-life and exponential decay in first-order kinetics. The simplicity of this formula is especially useful, as it provides a quick means of understanding the reaction's behavior over time.
For instance, in the given exercise, by substituting the rate constant value \(7.0 \times 10^{-4} s^{-1}\), we calculated the half-life of the decomposition of \(\mathrm{H}_2\mathrm{O}_2\) at room temperature. This highlights half-life as a convenient and intuitive characteristic for comparing the speed of different first-order reactions.
Rate Constant Determination
Determining the rate constant, typically denoted as \(k\), is crucial for quantifying the speed of a chemical reaction. It is an intrinsic part of the rate law, which for a first-order reaction, takes the form:

\[\text{rate} = k[\text{A}]\]
In this expression, \([\text{A}]\) represents the concentration of the reactant. The rate constant can be deduced from experimental data, such as concentration measurements over time. Alternatively, if the half-life of the reaction is known, as in the second part of the exercise dealing with the decomposition of \(\mathrm{(CH_2)_2 O}\), the rate constant can be calculated using the correlation:

\[k = \frac{0.693}{t_{1/2}}\]
By converting the half-life into seconds and applying the formula, we determined the rate constant at 415°C. The calculation of \(k\) enables us to predict the rate of the reaction at different concentrations and to compare the reactivity under various conditions.
Chemical Kinetics
Chemical kinetics is the area of chemistry that deals with the speed or rate of a chemical reaction and the mechanism by which the reaction occurs. A fundamental understanding of kinetics enables chemists to manipulate conditions to control the rate and predict the outcome of reactions.

The study of kinetics often involves various order reactions with first-order kinetics being one of the most common. A first-order reaction is characterized by its rate being directly proportional to the concentration of a single reactant. This means that as the reactant is consumed, the rate of the reaction decreases linearly with its concentration. The mathematical representation of a first-order rate law is:

\[ \text{rate} = k[\text{A}]^1 \]
Determining reaction order is vital as it influences how the rate reacts to changes in concentration and how the rate constant \(k\) is used to infer various dynamic aspects of the reaction. Kinetics also informs the stability and shelf-life of substances, crucial in disciplines like pharmaceuticals, food chemistry, and environmental science. In educational settings and in the field, understanding kinetics is pivotal for predicting and controlling the complex nature of chemical reactions.

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Most popular questions from this chapter

The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at 30.0 min. Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

The \(\mathrm{NO}_{x}\) waste stream from automobile exhaust includes species such as \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\). Catalysts that convert these species to \(\mathrm{N}_{2}\) are desirable to reduce air pollution. (a) Draw the Lewis dot and VSEPR structures of \(\mathrm{NO}, \mathrm{NO}_{2},\) and \(\mathrm{N}_{2} .(\mathbf{b})\) Using a resource such as Table 8.4 , look up the energies of the bonds in these molecules. In what region of the electromagnetic spectrum are these energies? (c) Design a spectroscopic experiment to monitor the conversion of \(\mathrm{NO}_{x}\) into \(\mathrm{N}_{2}\), describing what wavelengths of light need to be monitored as a function of time.

(a) A certain first-order reaction has a rate constant of \(2.75 \times 10^{-2} \mathrm{~s}^{-1}\) at \(20^{\circ} \mathrm{C}\). What is the value of \(k\) at \(60^{\circ} \mathrm{C}\) if \(E_{a}=75.5 \mathrm{~kJ} / \mathrm{mol} ?(\mathbf{b})\) Another first-order reaction also has a rate constant of \(2.75 \times 10^{-2} \mathrm{~s}^{-1}\) at \(20^{\circ} \mathrm{C}\). What is the value of \(k\) at \(60^{\circ} \mathrm{C}\) if \(E_{a}=125 \mathrm{~kJ} / \mathrm{mol} ?(\mathrm{c})\) What assumptions do you need to make in order to calculate answers for parts (a) and (b)?

Americium-241 is used in smoke detectors. It has a first order rate constant for radioactive decay of \(k=1.6 \times 10^{-3} \mathrm{yr}^{-1}\). By contrast, iodine- \(125,\) which is used to test for thyroid functioning, has a rate constant for radioactive decay of \(k=0.011\) day \(^{-1}\). (a) What are the halflives of these two isotopes? (b) Which one decays at a faster rate? (c) How much of a 1.00 -mg sample of each isotope remains after 3 half-lives? (d) How much of a 1.00 -mg sample of each isotope remains after 4 days?

(a) What factors determine whether a collision between two molecules will lead to a chemical reaction? (b) According to the collision model, why does temperature affect the value of the rate constant? (c) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature?

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