The \(\mathrm{NO}_{x}\) waste stream from automobile exhaust includes species such as \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\). Catalysts that convert these species to \(\mathrm{N}_{2}\) are desirable to reduce air pollution. (a) Draw the Lewis dot and VSEPR structures of \(\mathrm{NO}, \mathrm{NO}_{2},\) and \(\mathrm{N}_{2} .(\mathbf{b})\) Using a resource such as Table 8.4 , look up the energies of the bonds in these molecules. In what region of the electromagnetic spectrum are these energies? (c) Design a spectroscopic experiment to monitor the conversion of \(\mathrm{NO}_{x}\) into \(\mathrm{N}_{2}\), describing what wavelengths of light need to be monitored as a function of time.

Short Answer

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In summary, the Lewis dot and VSEPR structures for the molecules are: NO - linear, NO2 - bent, and N2 - linear. The bond energies corresponding to these molecules fall in the ultraviolet region of the electromagnetic spectrum at wavelengths of approximately 198 nm for N≡N, 299 nm for N≡O, and 330 nm for N=O. A spectroscopic experiment to monitor the conversion of NOx into N2 would involve absorption or emission spectroscopy in the ultraviolet region, monitoring wavelengths of 198 nm, 299 nm, and 330 nm over time as the catalyst is added under controlled reaction conditions. The changes in absorbance or emission intensity at these wavelengths will help track the formation and consumption of NO, NO2, and N2 molecules during the catalytic conversion process.

Step by step solution

01

Drawing the Lewis dot and VSEPR structures

To approach this part of the problem, we will first calculate the total valence electrons for each molecule, then we will draw the Lewis dot structures and finally determine the VSEPR shapes. - For NO: N has 5 valence electrons and O has 6 valence electrons, thus there are a total of 5+6 = 11 valence electrons. Lewis structure: N (triple bond) O • VSEPR structure: Linear - For NO2: N has 5 valence electrons and each O has 6 valence electrons, thus there are a total of 5+6+6 = 17 valence electrons. Lewis structure: N (double bond) O - O • VSEPR structure: Bent - For N2: N has 5 valence electrons, so there are a total of 5+5 = 10 valence electrons. Lewis structure: N (triple bond) N VSEPR structure: Linear
02

Finding the bond energies and identifying the electromagnetic spectrum region

Using Table 8.4 or a similar resource, we can find the bond energies for the molecules: - N≡N bond energy: 941 kJ/mol - N≡O bond energy: 632 kJ/mol - N=O bond energy: 542 kJ/mol Now, we can use this information to identify in what region of the electromagnetic spectrum these energies are. Bond energies are related to the energies of photons by the equation: Energy = h * frequency where h is Planck's constant (6.626 x 10^(-34) Js) and frequency can be related to the wavelength using the speed of light (c = 3 x 10^8 m/s): frequency = c / wavelength Thus, we can calculate the minimum wavelength of light corresponding to each bond energy: - For N≡N bond energy: wavelength = (6.626 x 10^(-34) * 3 x 10^8) / (941 x 10^3 * 6.022 x 10^23) ≈ 198 nm (Ultraviolet) - For N≡O bond energy: wavelength = (6.626 x 10^(-34) * 3 x 10^8) / (632 x 10^3 * 6.022 x 10^23) ≈ 299 nm (Ultraviolet) - For N=O bond energy: wavelength = (6.626 x 10^(-34) * 3 x 10^8) / (542 x 10^3 * 6.022 x 10^23) ≈ 330 nm (Ultraviolet) Therefore, the relevant bond energies are in the ultraviolet region of the electromagnetic spectrum.
03

Designing a spectroscopic experiment

To monitor the conversion of NOx molecules into N2, we can use absorption or emission spectroscopy in the ultraviolet region. This is because we need to detect the presence of nitrogen and oxygen bonds, which we found to have energies in the UV region, in order to track the reactions. In the experiment, we can monitor the absorbance or emission of light at wavelengths corresponding to the bond energies of relevant species (198 nm for N≡N, 299 nm for N≡O, and 330 nm for N=O), while providing the catalyst and controlling the reaction conditions such as temperature and pressure. By recording the changes in absorbance or emission intensity at these wavelengths over time, it will be possible to track the formation and consumption of NO, NO2, and N2 molecules. The corresponding time-dependence of the signals can be used to determine the progress of the catalytic conversion of NOx into N2.

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Most popular questions from this chapter

Consider the following hypothetical aqueous reaction: \(\mathrm{A}(a q) \longrightarrow \mathrm{B}(a q)\). A flask is charged with \(0.065 \mathrm{~mol}\) of \(\mathrm{A}\) in a total volume of \(100.0 \mathrm{~mL}\). The following data are collected: $$ \begin{array}{lccccc} \hline \text { Time (min) } & 0 & 10 & 20 & 30 & 40 \\ \hline \text { Moles of A } & 0.065 & 0.051 & 0.042 & 0.036 & 0.031 \\ \hline \end{array} $$ (a) Calculate the number of moles of \(\mathrm{B}\) at each time in the table, assuming that there are no molecules of \(\mathrm{B}\) at time zero, and that \(A\) cleanly converts to \(B\) with no intermediates. (b) Calculate the average rate of disappearance of \(\mathrm{A}\) for each 10 -min interval in units of \(M / \mathrm{s}\). (c) Between \(t=10 \mathrm{~min}\) and \(t=30 \mathrm{~min},\) what is the average rate of appearance of \(\mathrm{B}\) in units of \(M / s\) ? Assume that the volume of the solution is constant.

The gas-phase decomposition of \(\mathrm{NO}_{2}, 2 \mathrm{NO}_{2}(g) \longrightarrow\) \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g),\) is studied at \(383{ }^{\circ} \mathrm{C}\), giving the following data: $$ \begin{array}{rl} \hline \text { Time }(\mathbf{s}) & {\left[\mathrm{NO}_{2}\right](M)} \\ \hline 0.0 & 0.100 \\ 5.0 & 0.017 \\ 10.0 & 0.0090 \\ 15.0 & 0.0062 \\ 20.0 & 0.0047 \\ \hline \end{array} $$ (a) Is the reaction first order or second order with respect to the concentration of \(\mathrm{NO}_{2} ?\) (b) What is the rate constant? (c) If you used the method of initial rates to obtain the order for \(\mathrm{NO}_{2},\) predict what reaction rates you would measure in the beginning of the reaction for initial concentrations of \(0.200 \mathrm{M}, 0.100 \mathrm{M},\) and \(0.050 \mathrm{M} \mathrm{NO}_{2}\)

The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at 30.0 min. Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

Based on their activation energies and energy changes and assuming that all collision factors are the same, which of the following reactions would be fastest and which would be slowest? Explain your answer. (a) \(E_{a}=45 \mathrm{~kJ} / \mathrm{mol} ; \Delta E=-25 \mathrm{~kJ} / \mathrm{mol}\) (b) \(E_{a}=35 \mathrm{~kJ} / \mathrm{mol} ; \Delta E=-10 \mathrm{~kJ} / \mathrm{mol}\) (c) \(E_{a}=55 \mathrm{~kJ} / \mathrm{mol} ; \Delta E=10 \mathrm{~kJ} / \mathrm{mol}\)

The gas-phase reaction \(\mathrm{Cl}(g)+\mathrm{HBr}(g) \longrightarrow \mathrm{HCl}(g)+\mathrm{Br}(g)\) has an overall enthalpy change of \(-66 \mathrm{~kJ}\). The activation energy for the reaction is \(7 \mathrm{~kJ}\). (a) Sketch the energy profile for the reaction, and label \(E_{a}\) and \(\Delta E\). (b) What is the activation energy for the reverse reaction?

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