Consider the following reaction: $$ \mathrm{CH}_{3} \mathrm{Br}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{CH}_{3} \mathrm{OH}(a q)+\mathrm{Br}^{-}(a q) $$ The rate law for this reaction is first order in \(\mathrm{CH}_{3} \mathrm{Br}\) and first order in \(\mathrm{OH}^{-}\). When \(\left[\mathrm{CH}_{3} \mathrm{Br}\right]\) is \(5.0 \times 10^{-3} \mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]\) is \(0.050 \mathrm{M},\) the reaction rate at \(298 \mathrm{~K}\) is \(0.0432 \mathrm{M} / \mathrm{s}\). (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) What would happen to the rate if the concentration of \(\mathrm{OH}^{-}\) were tripled? (d) What would happen to the rate if the concentration of both reactants were tripled?

Short Answer

Expert verified
(a) The value of the rate constant, k, is approximately 17.28 M^-1s^-1. (b) The units of the rate constant, k, are M^-1s^-1. (c) If the concentration of OH- is tripled, the reaction rate becomes approximately 0.1296 M/s. (d) If the concentrations of both reactants are tripled, the reaction rate becomes approximately 0.3888 M/s.

Step by step solution

01

Write the rate law

The rate law is given as: Rate = k [CH3Br]^1 [OH-]^1, where k is the rate constant that we need to find, and [CH3Br] and [OH-] are the concentrations of the reactants CH3Br and OH-, respectively.
02

Find the value of the rate constant (k)

Given, the initial concentrations of the reactants are: [CH3Br] = 5.0 × 10^-5 M [OH-] = 0.050 M and the reaction rate is 0.0432 M/s. Substitute these values into the rate law equation: 0.0432 = k (5.0 × 10^-5) (0.050) Solve for k: k = 0.0432 / ((5.0 × 10^-5) × (0.050)) k ≈ 17.28 M^-1s^-1 The value of the rate constant, k, is approximately 17.28 M^-1s^-1.
03

Identify the units of the rate constant (k)

From the above calculation, we can see that the units of the rate constant, k, are M^-1s^-1.
04

Calculate the rate if the concentration of OH- is tripled

If the concentration of OH- is tripled, the new concentration will be 3 × 0.050 M = 0.150 M. Use the rate law equation with the new concentration: Rate_new = k [CH3Br] [OH-]_new Rate_new = 17.28 (5.0 × 10^-5) (0.150) Rate_new ≈ 0.1296 M/s If the concentration of OH- is tripled, the reaction rate becomes approximately 0.1296 M/s.
05

Calculate the rate if the concentrations of both reactants are tripled

If the concentrations of both reactants are tripled, the new concentrations will be: [CH3Br]_new = 3 × (5.0 × 10^-5) = 15.0 × 10^-5 M [OH-]_new = 3 × 0.050 = 0.150 M Use the rate law equation with the new concentrations: Rate_new = k [CH3Br]_new [OH-]_new Rate_new = 17.28 (15.0 × 10^-5) (0.150) Rate_new ≈ 0.3888 M/s If the concentrations of both reactants are tripled, the reaction rate becomes approximately 0.3888 M/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Rate
Understanding the speed at which chemical reactions take place is crucial for both students and scientists. The reaction rate is a measure of the change in concentration of reactants or products over time in a chemical reaction. Think of it as how fast or slow a reactant is consumed or a product is formed.

For example, in the given reaction of \( \mathrm{CH}_{3} \mathrm{Br} \) with \( \mathrm{OH}^{-} \), the reaction rate was given as \( 0.0432 \, \mathrm{M/s} \). This means that the concentration of either the reactants or products changes by this amount every second under the specified conditions.

Various factors can affect the reaction rate, such as temperature, concentration of reactants, surface area, and presence of catalysts. A crucial aspect for students to understand is that reaction rates are proportional to the concentration of reactants in many cases, which is reflected in the rate law for the reaction.
Rate Law
The rate law is a mathematical expression that links the reaction rate to the concentration of reactants. It allows us to predict the speed of a chemical reaction under different conditions. The rate law for a reaction is determined experimentally and cannot be deduced from the stoichiometry of the reaction alone.

For the reaction at hand, the rate law was expressed as Rate = k [CH3Br]^1 [OH-]^1. This tells us that the reaction is first order in \( \mathrm{CH}_{3} \mathrm{Br} \) and \( \mathrm{OH}^{-} \), meaning that the rate of reaction is directly proportional to the concentration of each reactant raised to the first power. If the concentration of \( \mathrm{CH}_{3} \mathrm{Br} \) or \( \mathrm{OH}^{-} \) is doubled, the reaction rate will also double.

It is essential to grasp that the rate law provides invaluable insights into the kinetic behavior of a reaction and helps in the study of reaction mechanisms.
Rate Constant
At the heart of the rate law is the rate constant, often symbolized by \( k \). This constant is a measure of the intrinsic speed of a chemical reaction, and it varies with temperature but is independent of the reactant concentrations. The rate constant plays a key role in determining how fast a reaction proceeds under certain conditions.

In the solved exercise, the calculated rate constant was \( 17.28 \, \mathrm{M}^{-1}\mathrm{s}^{-1} \). The units of the rate constant can vary depending on the overall order of the reaction. Since our reaction is second order (first order with respect to each reactant), the units for the rate constant are \( \mathrm{M}^{-1}\mathrm{s}^{-1} \), revealing the dependence on both concentration and time.

Understanding the rate constant is fundamental as it helps predict the effects of changing conditions on the reaction rate. For instance, tripling the concentration of \( \mathrm{OH}^{-} \) or both reactants significantly increases the reaction rate, as seen in the provided solution. Such knowledge is particularly valuable in chemical industries and research where controlling the reaction speed is often as critical as the reaction itself.

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Most popular questions from this chapter

When chemists are performing kinetics experiments, the general rule of thumb is to allow the reaction to proceed for 4 half-lives. (a) Explain how you would be able to tell that the reaction has proceeded for 4 half-lives. (b) Let us suppose a reaction \(\mathrm{A} \rightarrow \mathrm{B}\) takes 6 days to proceed for 4 half-lives and is first order in A. However, when your lab partner performs this reaction for the first time, he does not realize how long it takes, and he stops taking kinetic data, monitoring the loss of A, after only 2 hours. Your lab partner concludes the reaction is zero order in A based on the data. Sketch a graph of [A] versus time to convince your lab partner the two of you need to be in the lab for a few days to obtain the proper rate law for the reaction.

(a) Explain the importance of enzymes in biological systems. (b) What chemical transformations are catalyzed (i) by the enzyme catalase, \((i i)\) by nitrogenase? (c) Many enzymes follow this generic reaction mechanism, where \(\mathrm{E}\) is enzyme, \(\mathrm{S}\) is substrate, ES is the enzyme-substrate complex (where the substrate is bound to the enzyme's active site), and \(\mathrm{P}\) is the product: 1\. \(\mathrm{E}+\mathrm{S} \rightleftharpoons \mathrm{ES}\) 2\. \(\mathrm{ES} \longrightarrow \mathrm{E}+\mathrm{P}\) What assumptions are made in this model with regard to the rate of the bound substrate being chemically transformed into bound product in the active site?

The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at 30.0 min. Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

(a) If you were going to build a system to check the effectiveness of automobile catalytic converters on cars, what substances would you want to look for in the car exhaust? (b) Automobile catalytic converters have to work at high temperatures, as hot exhaust gases stream through them. In what ways could this be an advantage? In what ways a disadvantage? (c) Why is the rate of flow of exhaust gases over a catalytic converter important?

Hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{~S}\right)\) is a common and troublesome pollutant in industrial wastewaters. One way to remove \(\mathrm{H}_{2} \mathrm{~S}\) is to treat the water with chlorine, in which case the following reaction occurs: $$ \mathrm{H}_{2} \mathrm{~S}(a q)+\mathrm{Cl}_{2}(a q) \longrightarrow \mathrm{S}(s)+2 \mathrm{H}^{+}(a q)+2 \mathrm{Cl}^{-}(a q) $$ The rate of this reaction is first order in each reactant. The rate constant for the disappearance of \(\mathrm{H}_{2} \mathrm{~S}\) at \(28^{\circ} \mathrm{C}\) is \(3.5 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\). If at a given time the concentration of \(\mathrm{H}_{2} \mathrm{~S}\) is \(2.0 \times 10^{-4} \mathrm{M}\) and that of \(\mathrm{Cl}_{2}\) is \(0.025 \mathrm{M},\) what is the rate of formation of \(\mathrm{Cl}^{-} ?\)

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