Enzymes are often described as following the two-step mechanism:
$$
\begin{array}{l}
\mathrm{E}+\mathrm{S} \rightleftharpoons \mathrm{ES} \quad(\text { fast }) \\
\mathrm{ES} \longrightarrow \mathrm{E}+\mathrm{P} \quad(\text { slow })
\end{array}
$$
where \(\mathrm{E}=\) enzyme, \(\mathrm{S}=\) substrate, \(\mathrm{ES}=\) enzyme-
substrate complex, and \(\mathrm{P}=\) product.
(a) If an enzyme follows this mechanism, what rate law is expected for the
reaction? (b) Molecules that can bind to the active site of an enzyme but are
not converted into product are called enzyme inhibitors. Write an additional
elementary step to add into the preceding mechanism to account for the
reaction of \(\mathrm{E}\) with \(\mathrm{I}\), an inhibitor.