(a) A certain first-order reaction has a rate constant of \(2.75 \times 10^{-2} \mathrm{~s}^{-1}\) at \(20^{\circ} \mathrm{C}\). What is the value of \(k\) at \(60^{\circ} \mathrm{C}\) if \(E_{a}=75.5 \mathrm{~kJ} / \mathrm{mol} ?(\mathbf{b})\) Another first-order reaction also has a rate constant of \(2.75 \times 10^{-2} \mathrm{~s}^{-1}\) at \(20^{\circ} \mathrm{C}\). What is the value of \(k\) at \(60^{\circ} \mathrm{C}\) if \(E_{a}=125 \mathrm{~kJ} / \mathrm{mol} ?(\mathrm{c})\) What assumptions do you need to make in order to calculate answers for parts (a) and (b)?

Short Answer

Expert verified
For Reaction (a), the value of k at 60ºC is approximately \(4.76\times10^{-2} s^{-1}\). For Reaction (b), the value of k at 60ºC is approximately \(6.93\times10^{-3} s^{-1}\). The assumptions made in calculating the rate constants include the constant pre-exponential factor, constant activation energy within the temperature range, and linear dependence of reaction rates on reactant concentration for both first-order reactions.

Step by step solution

01

(Step 1: Convert temperatures to Kelvin)

To work with the Arrhenius equation, we need to convert our temperatures from Celsius to Kelvin. We do this by adding 273.15 to the temperature in Celsius: - T1 (20ºC) = 20 + 273.15 = 293.15 K - T2 (60ºC) = 60 + 273.15 = 333.15 K
02

(Step 2: Write the Arrhenius equation using the ratio of rate constants)

Since we want to find the rate constants at T2, we can write the Arrhenius equation as a ratio of k2 and k1: \(\frac{k_2}{k_1} = \frac{A e^{-\frac{E_a}{R T_2}}}{A e^{-\frac{E_a}{R T_1}}}\)
03

(Step 3: Calculate k for Reaction (a))

For Reaction (a), we already know k1, T1, T2, and Ea. We'll replace these values in the equation mentioned in Step 2: \(\frac{k_2}{2.75\times10^{-2}} = \frac{e^{-\frac{75.5\times10^{3}}{8.314 \times 333.15}}}{e^{-\frac{75.5\times10^{3}}{8.314 \times 293.15}}}\) Now, solve for k2: \(k_2 = 2.75\times10^{-2} \times \frac{e^{-\frac{75.5\times10^{3}}{8.314 \times 333.15}}}{e^{-\frac{75.5\times10^{3}}{8.314 \times 293.15}}}\) \(k_2 \approx 4.76\times10^{-2} s^{-1}\) So for Reaction (a), the value of k at 60ºC is approximately \(4.76\times10^{-2} s^{-1}\).
04

(Step 4: Calculate k for Reaction (b))

For Reaction (b), we already know k1, T1, T2, and Ea. We'll replace these values in the equation mentioned in Step 2: \(\frac{k_2}{2.75\times10^{-2}} = \frac{e^{-\frac{125\times10^{3}}{8.314 \times 333.15}}}{e^{-\frac{125\times10^{3}}{8.314 \times 293.15}}}\) Now, solve for k2: \(k_2 = 2.75\times10^{-2} \times \frac{e^{-\frac{125\times10^{3}}{8.314 \times 333.15}}}{e^{-\frac{125\times10^{3}}{8.314 \times 293.15}}}\) \(k_2 \approx 6.93\times10^{-3} s^{-1}\) So for Reaction (b), the value of k at 60ºC is approximately \(6.93\times10^{-3} s^{-1}\).
05

(Step 5: Discuss the assumptions made)

To calculate the rate constants for both reactions, we made a few assumptions: 1. The pre-exponential factor, A, remains constant within the temperature range considered (20ºC to 60ºC). 2. The activation energy, Ea, remains constant within the temperature range considered. 3. Both reactions are first-order, which means the reaction rates are linearly dependent on the concentration of reactants. These assumptions are necessary to make simplifications using the Arrhenius equation and calculate the rate constants at different temperatures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constants
Understanding the speed at which a reaction occurs is essential in chemistry, and this is where the concept of rate constants becomes relevant. A rate constant, represented by the symbol 'k', is a proportionality constant in the rate law that provides a quantitative measure of the speed of a chemical reaction. It varies with temperature, as described by the Arrhenius equation.

In a chemical reaction, the rate law expresses the relationship between the rate of the reaction and the concentration of the reactants. For a given reaction at a certain temperature, the rate constant is fixed and can be used to predict the reaction rate if the concentrations of the reactants are known. As the temperature changes, so does the rate constant.

The Arrhenius equation, which includes the rate constant, provides a way to calculate how 'k' changes with temperature, taking into account the activation energy and the temperature in Kelvin. This relationship is crucial because it allows chemists to understand and predict how the reaction speed will change under different temperature conditions. An increase in temperature typically leads to an increase in the rate constant, implying a faster reaction rate.
Activation Energy
Activation energy (Ea) is a key term in understanding chemical kinetics, which refers to the minimum energy required for a reaction to occur. It is the energy barrier that must be overcome by the reactants to transform into products. The concept of activation energy is critical when discussing reaction rates and how they are affected by temperature changes.

The Arrhenius equation includes the activation energy as a factor that influences the rate constant. A higher activation energy means that the reactants need more energy to react, making the reaction slower at the same temperature. Conversely, a lower activation energy equates to a faster reaction since less energy is required for the reactants to overcome the energy barrier.

This interplay between temperature and activation energy is why reaction rates can vary significantly even if other factors remain constant. When applying the Arrhenius equation, as shown in the textbook example, we see that different activation energies result in different rate constants at a given temperature, illustrating the sensitivity of reaction rate to even small changes in these parameters.
First-Order Reaction
In chemical kinetics, reactions can be categorized based on how their rate depends on the concentration of reactants. A first-order reaction is one where the reaction rate is directly proportional to the concentration of a single reactant. This means that if you were to double the concentration of the reactant, the rate of the reaction would also double.

First-order reactions are characterized by their linear relationship between the natural logarithm of reactant concentration and time. They have rate laws that can be written as: rate = k [A], where [A] is the concentration of the reactant, and k is the rate constant for the reaction.

The simplicity of first-order kinetics makes it easier to understand and calculate important variables using the Arrhenius equation. For example, in the exercise provided, the assumption that the reactions are first-order allows us to directly connect the rate constant to the reaction's temperature and activation energy without worrying about the concentration of reactants. It is assumed that the reaction rate is solely influenced by the changes in temperature and is not affected by any other potential variables such as reactant concentration or the presence of a catalyst.

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Most popular questions from this chapter

One of the many remarkable enzymes in the human body is carbonic anhydrase, which catalyzes the interconversion of carbon dioxide and water with bicarbonate ion and protons. If it were not for this enzyme, the body could not rid itself rapidly enough of the \(\mathrm{CO}_{2}\) accumulated by cell metabolism. The enzyme catalyzes the dehydration (release to air) of up to \(10^{7} \mathrm{CO}_{2}\) molecules per second. Which components of this description correspond to the terms enzyme, substrate, and turnover number?

A reaction \(A+B \longrightarrow C\) obeys the following rate law: Rate \(=k[\mathrm{~B}]^{2}\). (a) If \([\mathrm{A}]\) is doubled, how will the rate change? Will the rate constant change? Explain. (b) What are the reaction orders for \(\mathrm{A}\) and \(\mathrm{B}\) ? What is the overall reaction order? (c) What are the units of the rate constant?

(a) The reaction \(\mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\frac{1}{2} \mathrm{O}_{2}(g)\) is first order. Near room temperature, the rate constant equals \(7.0 \times 10^{-4} \mathrm{~s}^{-1} .\) Calculate the half-life at this temperature. (b) At \(415^{\circ} \mathrm{C},\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}\) decomposes in the gas phase, \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}(g) \longrightarrow \mathrm{CH}_{4}(g)+\mathrm{CO}(g) .\) If the reaction is first order with a half-life of 56.3 min at this temperature, calculate the rate constant in \(\mathrm{s}^{-1}\).

The decomposition of hydrogen peroxide is catalyzed by iodide ion. The catalyzed reaction is thought to proceed by a two-step mechanism: $$ \begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{I}^{-}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{IO}^{-}(a q) \\ \mathrm{IO}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)+\mathrm{I}^{-}(a q) \end{aligned} $$ (a) Write the chemical equation for the overall process. (b) Identify the intermediate, if any, in the mechanism. (c) Assuming that the first step of the mechanism is rate determining, predict the rate law for the overall process.

Consider the reaction of peroxydisulfate ion $\left(\mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}\right)\( with iodide ion \)\left(\mathrm{I}^{-}\right)$ in aqueous solution: $$ \mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}(a q)+3 \mathrm{I}^{-}(a q) \longrightarrow 2 \mathrm{SO}_{4}^{2-}(a q)+\mathrm{I}_{3}^{-}(a q) $$ At a particular temperature, the initial rate of disappearance of \(\mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}\) varies with reactant concentrations in the following manner: $$ \begin{array}{lccc} \hline \text { Experiment } & {\left[\mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}\right](M)} & {\left[\mathrm{I}^{-}\right](M)} & \text { Initial Rate }(\mathrm{M} / \mathrm{s}) \\ \hline 1 & 0.018 & 0.036 & 2.6 \times 10^{-6} \\ 2 & 0.027 & 0.036 & 3.9 \times 10^{-6} \\ 3 & 0.036 & 0.054 & 7.8 \times 10^{-6} \\ 4 & 0.050 & 0.072 & 1.4 \times 10^{-5} \\ \hline \end{array} $$ (a) Determine the rate law for the reaction and state the units of the rate constant. (b) What is the average value of the rate constant for the disappearance of \(\mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}\) based on the four sets of data? (c) How is the rate of disappearance of $\mathrm{S}_{2} \mathrm{O}_{8}^{2-}\( related to the rate of disappearance of \)\mathrm{I}^{-} ?(\mathbf{d})\( What is the rate of disappearance of \)\mathrm{I}^{-}$ when \(\left[\mathrm{S}_{2} \mathrm{O}_{8}{ }^{2-}\right]=0.025 \mathrm{M}\) and \(\left[\mathrm{I}^{-}\right]=0.050 \mathrm{M} ?\)

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