Calculate the concentration of an aqueous solution of \(\mathrm{Ca}(\mathrm{OH})_{2}\) that has a \(\mathrm{pH}\) of \(10.05 .\)

Short Answer

Expert verified
The concentration of the aqueous solution of Ca(OH)₂ with a pH of 10.05 is approximately \( 5.6 \times 10^{-5} \) M.

Step by step solution

01

Determine pOH from pH

To find the concentration of OH⁻ ions in the solution, it is necessary to convert the given pH value into the pOH value. This can be done using the following relationship: pH + pOH = 14 Substitute the given pH value: 10.05 + pOH = 14 Now, solve for pOH: pOH = 14 - 10.05 pOH = 3.95
02

Calculate the concentration of OH⁻ ions

The pOH value represents the negative base-10 logarithm of the concentration of OH⁻ ions. To find the concentration of OH⁻ ions, use the following equation: pOH = -logₓ[OH⁻] We can convert the pOH value to the concentration of OH⁻ ions using the following formula: [OH⁻] = 10^{-pOH} Now, substitute the pOH value: [OH⁻] = 10^{-3.95} [OH⁻] ≈ 1.12 × 10^-4 M
03

Calculate the concentration of Ca(OH)₂

Since each calcium hydroxide (Ca(OH)₂) dissociates into two hydroxide ions (OH⁻), the stoichiometry of the reaction is as follows: Ca(OH)₂ → Ca²⁺ + 2OH⁻ So, for every one Ca(OH)₂ dissolved, two OH⁻ ions are produced. To find the concentration of Ca(OH)₂, divide the concentration of OH⁻ by the stoichiometric coefficient (2): [Ca(OH)₂] = [OH⁻]/2 Now, substitute the concentration of OH⁻ ions: [Ca(OH)₂] = (1.12 × 10^-4 M)/2 [Ca(OH)₂] ≈ 5.6 × 10^-5 M The concentration of the aqueous solution of Ca(OH)₂ with a pH of 10.05 is approximately 5.6 × 10⁻⁵ M.

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