For solutions of a weak acid, a graph of \(\mathrm{pH}\) versus the logarithm of the initial acid concentration should be a straight line. What is the magnitude of the slope of that line?

Short Answer

Expert verified
The magnitude of the slope of the graph of pH versus the logarithm of the initial acid concentration for solutions of weak acids is \( \frac{1}{2} \).

Step by step solution

01

Write the ionization equation for a weak acid

Let's denote the weak acid as "HA". The ionization of a weak acid in water can be represented as: \[HA + H_2O \rightleftharpoons H_3O^+ + A^-\]
02

Write the expression for the ionization constant

The ionization constant, Ka, represents the equilibrium concentrations of the ions, which can be calculated as: \[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
03

Simplify the expression for the concentrations

If we denote 'x' as the concentration of \(H_3O^+\), then \(A^-\) is also 'x' (since one HA produces one \(H_3O^+\) and one \(A^-\)). Thus, the concentration of HA remaining will be ([HA_initial] - x). Now we can rewrite the ionization constant expression as: \[K_a = \frac{x^2}{[HA_{initial}] - x}\]
04

Find the H3O+ concentration, x, in terms of Ka and the initial concentration of HA

Since the acid is weak, its ionization is small, and therefore we can assume that "x" is significantly smaller than the initial concentration of "HA": \[K_a = \frac{x^2}{[HA_{initial}]}\] Now we can solve for x: \[x = [H_3O^+] = \sqrt{K_a[HA_{initial}]}\]
05

Write the expression for pH and take the logarithm of both sides

The pH is related to the concentrations of the ions by the equation: \[ pH = -\log{[H_3O^+]}\] Substituting the expression we derived for x: \[pH = -\log{(\sqrt{K_a[HA_{initial}]})}\] Taking the logarithm of both sides, we get: \[\log{(pH)} = \log{(-(1/2))} \cdot (\log{(K_a)}) + (\log{([HA_{initial}] - \log{K_a})})\]
06

Find the magnitude of the slope

In the last expression, we can observe that the coefficient, '-(1/2)', is the slope of the graph. So, the magnitude of the slope is: \[ Slope = |- (\frac{1}{2})| = \frac{1}{2}\] Thus, the magnitude of the slope of the graph of pH versus the logarithm of the initial acid concentration for solutions of weak acids is 1/2.

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