An unknown salt is either \(\mathrm{KBr}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{KCN},\) or \(\mathrm{K}_{2} \mathrm{CO}_{3} .\) If a \(0.100 \mathrm{M}\) solution of the salt is neutral, what is the identity of the salt?

Short Answer

Expert verified
The unknown salt is KBr (potassium bromide), as it forms a neutral solution. This is because the K⁺ ion does not affect the pH, and the Br⁻ ion does not significantly change the pH either.

Step by step solution

01

List the possible salts and their ions

First, let's list the given salts and their respective ions: 1. KBr: K⁺ (potassium ion), Br⁻ (bromide ion) 2. NH₄Cl: NH4⁺ (ammonium ion), Cl⁻ (chloride ion) 3. KCN: K⁺ (potassium ion), CN⁻ (cyanide ion) 4. K₂CO₃: 2 K⁺ (potassium ions), CO₃²⁻ (carbonate ion)
02

Analyze the acidic or basic properties of the ions

Now we will analyze the acidic or basic properties of each ion: - K⁺: Since potassium belongs to Group 1 of the periodic table, it forms neutral solutions as cations of this group do not hydrolyze. - NH4⁺: The ammonium ion behaves as a weak acid, releasing a H⁺ ion in solution: \(\mathrm{NH_4^+} \rightleftharpoons \mathrm{NH_3} + \mathrm{H^+}\) - Br⁻, Cl⁻: Both bromide and chloride are conjugate bases of strong acids (HBr and HCl). Therefore, they are weak bases and will cause a negligible change to the pH of the solution. - CN⁻: The cyanide ion is the conjugate base of the weak acid, HCN. So, it behaves as a weak base by accepting a H⁺ ion from water: \(\mathrm{CN^-} + \mathrm{H_2O} \rightleftharpoons \mathrm{HCN} + \mathrm{OH^-}\) - CO₃²⁻: The carbonate ion is a weak base. It accepts a H⁺ ion from water, yielding bicarbonate: \(\mathrm{CO_3^{2-}} + \mathrm{H_2O} \rightleftharpoons \mathrm{HCO_3^-} + \mathrm{OH^-}\)
03

Determine which salt would produce a neutral solution

Based on our analysis in Step 2, let us examine each salt to see which one would produce a neutral solution: 1. KBr: K⁺ does not impact pH, and Br⁻ does not significantly change the pH. So, a KBr solution would be neutral. 2. NH₄Cl: NH4⁺ acts as a weak acid and Cl⁻ does not significantly change the pH. This combination would result in a slightly acidic solution. 3. KCN: K⁺ does not affect the pH, but CN⁻ acts as a weak base. The solution of KCN would be slightly basic. 4. K₂CO₃: K⁺ does not affect the pH, but CO₃²⁻ acts as a weak base. The solution of K₂CO₃ would be slightly basic. Since we are looking for a salt that forms a neutral solution, the only suitable candidate is KBr (potassium bromide). So, the identity of the unknown salt is KBr.

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Most popular questions from this chapter

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the equation: (a) \(\mathrm{NH}_{4}{ }^{+}(a q)+\mathrm{OH}^{-}(a q) \rightleftharpoons\) (b) \(\mathrm{CH}_{3} \mathrm{COO}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q) \rightleftharpoons\) (c) \(\mathrm{HCO}_{3}^{-}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons\)

Indicate whether each of the following statements is true or false. For each statement that is false, correct the statement to make it true. (a) In general, the acidity of binary acids increases from left to right in a given row of the periodic table. (b) In a series of acids that have the same central atom, acid strength increases with the number of hydrogen atoms bonded to the central atom. (c) Hydrotelluric acid \(\left(\mathrm{H}_{2} \mathrm{Te}\right)\) is a stronger acid than \(\mathrm{H}_{2} \mathrm{~S}\) because Te is more electronegative than \(\mathrm{S}\).

Predict which member of each pair produces the more acidic aqueous solution: (a) \(\mathrm{K}^{+}\) or \(\mathrm{Cu}^{2+},(\mathrm{b}) \mathrm{Fe}^{2+}\) or \(\mathrm{Fe}^{3+},(\mathrm{c}) \mathrm{Al}^{3+}\) or \(\mathrm{Ga}^{3+} .\) Explain.

Calculate the \(\mathrm{pH}\) of each of the following strong acid solutions: (a) \(8.5 \times 10^{-3} \mathrm{MHBr}\), (b) \(1.52 \mathrm{~g}\) of \(\mathrm{HNO}_{3}\) in \(575 \mathrm{~mL}\) of solution, (c) \(5.00 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{HClO}_{4}\) diluted to \(50.0 \mathrm{~mL}\), (d) a solution formed by mixing \(10.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{HBr}\) with \(20.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HCl}\)

The active ingredient in aspirin is acetylsalicylic acid \(\left(\mathrm{HC}_{9} \mathrm{H}_{7} \mathrm{O}_{4}\right),\) a monoprotic acid with \(K_{a}=3.3 \times 10^{-4}\) at \(25^{\circ} \mathrm{C}\). What is the \(\mathrm{pH}\) of a solution obtained by dissolving two extra-strength aspirin tablets, containing \(500 \mathrm{mg}\) of acetylsalicylic acid each, in \(250 \mathrm{~mL}\) of water?

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