Ferrous sulfate \(\left(\mathrm{FeSO}_{4}\right)\) is often used as a coagulant in water purification. The iron(II) salt is dissolved in the water to be purified, then oxidized to the iron(III) state by dissolved oxygen, at which time gelatinous \(\mathrm{Fe}(\mathrm{OH})_{3}\) forms, assuming the \(\mathrm{pH}\) is above approximately \(6 .\) Write balanced chemical equations for the oxidation of \(\mathrm{Fe}^{2+}\) to \(\mathrm{Fe}^{3+}\) by dissolved oxygen and for the formation of \(\mathrm{Fe}(\mathrm{OH})_{3}(s)\) by reaction of \(\mathrm{Fe}^{3+}(a q)\) with \(\mathrm{HCO}_{3}^{-}(a q)\).

Short Answer

Expert verified
The balanced chemical equations for the water purification process using ferrous sulfate are: 1. The oxidation of iron(II) ions to iron(III) ions by dissolved oxygen: \(4 \ Fe^{2+} (aq) + O_{2} (aq) + 4 \ H^{+} (aq) \rightarrow 4 \ Fe^{3+} (aq) + 2 \ H_{2}O (l)\) 2. The formation of gelatinous iron(III) hydroxide precipitate by the reaction of iron(III) ions with bicarbonate ions: \(Fe^{3+} (aq) + 3 \ HCO_{3}^{-} (aq) \rightarrow Fe(OH)_{3} (s) + 3 \ CO_{2} \ (g) + 3 \ H^{+} (aq)\)

Step by step solution

01

Oxidation of Fe²⁺ to Fe³⁺ by Dissolved Oxygen

First, we have to write a balanced equation for the oxidation of iron(II), which is represented as Fe²⁺, to iron(III), represented as Fe³⁺, by dissolved oxygen (O₂). In this process, the iron ions will lose one electron (e⁻) due to oxidation. To balance the equation, we must ensure that there are the same number of atoms of each element on both sides of the equation. Here is the balanced equation for the oxidation of Fe²⁺ to Fe³⁺ by dissolved oxygen: \(4 \ Fe^{2+} (aq) + O_{2} (aq) + 4 \ H^{+} (aq) \rightarrow 4 \ Fe^{3+} (aq) + 2 \ H_{2}O (l)\)
02

Formation of Fe(OH)₃ by the Reaction of Fe³⁺ with HCO₃⁻

Now we need to write a balanced chemical equation for the formation of gelatinous Fe(OH)₃(s) from the reaction of Fe³⁺ with bicarbonate ions (HCO₃⁻). This dissolved iron(III) will react with the bicarbonate ions to form the precipitate Fe(OH)₃(s) and the gaseous carbon dioxide (CO₂). Here is the balanced equation for the formation of Fe(OH)₃(s) by the reaction of Fe³⁺ with HCO₃⁻: \(Fe^{3+} (aq) + 3 \ HCO_{3}^{-} (aq) \rightarrow Fe(OH)_{3} (s) + 3 \ CO_{2} \ (g) + 3 \ H^{+} (aq)\) In summary, the balanced equations for the water purification process using ferrous sulfate are: 1. The oxidation of iron(II) ions to iron(III) ions by dissolved oxygen: \(4 \ Fe^{2+} (aq) + O_{2} (aq) + 4 \ H^{+} (aq) \rightarrow 4 \ Fe^{3+} (aq) + 2 \ H_{2}O (l)\) 2. The formation of gelatinous iron(III) hydroxide precipitate by the reaction of iron(III) ions with bicarbonate ions: \(Fe^{3+} (aq) + 3 \ HCO_{3}^{-} (aq) \rightarrow Fe(OH)_{3} (s) + 3 \ CO_{2} \ (g) + 3 \ H^{+} (aq)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) How are the boundaries between the regions of the atmosphere determined? (b) Explain why the stratosphere, which is more than 20 miles thick, has a smaller total mass than the troposphere, which is less than 10 miles thick.

Do the reactions involved in ozone depletion involve changes in oxidation state of the O atoms? Explain.

What properties make a substance a good coagulant for water purification?

The average daily mass of \(\mathrm{O}_{2}\) taken up by sewage discharged in the United States is \(59 \mathrm{~g}\) per person. How many liters of water at \(9 \mathrm{ppm} \mathrm{O}_{2}\) are totally depleted of oxygen in 1 day by a population of 1,200,000 people?

The hydroxyl radical, \(\mathrm{OH}\), is formed at low altitudes via the reaction of excited oxygen atoms with water: $$ \mathrm{O}^{*}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{OH}(g) $$ (a) Write the Lewis structure for the hydroxyl radical. (Hint: It has one unpaired electron.) Once produced, the hydroxyl radical is very reactive. Explain why each of the following series of reactions affects the pollution in the troposphere: (b) \(\mathrm{OH}+\mathrm{NO}_{2} \longrightarrow \mathrm{HNO}_{3}\) (c) \(\mathrm{OH}+\mathrm{CO}+\mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+\mathrm{OOH}\) \(\mathrm{OOH}+\mathrm{NO} \longrightarrow \mathrm{OH}+\mathrm{NO}_{2}\) (d) \(\mathrm{OH}+\mathrm{CH}_{4} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{CH}_{3}\) \(\mathrm{CH}_{3}+\mathrm{O}_{2} \longrightarrow \mathrm{OOCH}_{3}\) \(\mathrm{OOCH}_{3}+\mathrm{NO} \longrightarrow \mathrm{OCH}_{3}+\mathrm{NO}_{2}\) (e) The concentration of hydroxyl radicals in the troposphere is approximately \(2 \times 10^{6}\) radicals per \(\mathrm{cm}^{3}\). This estimate is based on a method called long path absorption spectroscopy (LPAS), similar in principle to the Beer's law measurement discussed in the Closer Look essay on p. 564 , except that the path length in the LPAS measurement is \(20 \mathrm{~km}\). Why must the path length be so large?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free