(a) What is the difference between a state and a microstate of a system? (b) As a system goes from state A to state B, its entropy decreases. What can you say about the number of microstates corresponding to each state? (c) In a particular spontaneous process, the number of microstates available to the system decreases. What can you conclude about the sign of \(\Delta S_{\text {surr }}\) ?

Short Answer

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(a) A state of a system refers to a set of macroscopic properties, while a microstate refers to a specific arrangement of particles exhibiting those macroscopic properties. (b) As entropy decreases, the number of microstates available to the system also decreases, meaning state A has more microstates than state B. (c) If the number of microstates decreases in a spontaneous process, then the entropy change of the system is negative, and the change in entropy of the surroundings must be positive to maintain spontaneity, making \(\Delta S_{\text{total}} \geq 0\).

Step by step solution

01

(a) State and Microstate:

A state of a system refers to a specific set of macroscopic properties such as temperature, pressure, or volume. In contrast, a microstate refers to a specific arrangement of particles in a system, describing the position and momentum of each particle, such that the system exhibits the given macroscopic properties.
02

(b) Entropy and Number of Microstates:

As the system goes from state A to state B, with its entropy decreasing, it means the number of microstates available to the system is decreasing. In other words, state A has a higher number of possible microstates compared to state B since a higher entropy implies more possible microscopic arrangements.
03

(c) Change in Surroundings' Entropy:

In a particular spontaneous process, if the number of microstates available to the system decreases, it implies that the entropy change of the system, \(\Delta S_{\text{sys}}\), is negative. However, since the process is spontaneous, it is only possible if the change in entropy of the surroundings, \(\Delta S_{\text{surr}}\), compensates for this decrease. Thus, \(\Delta S_{\text{surr}}\) must be positive, making the total change in entropy, \(\Delta S_{\text{total}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}}\), greater than or equal to zero.

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Most popular questions from this chapter

(a) For a process that occurs at constant temperature, express the change in Gibbs free energy in terms of changes in the enthalpy and entropy of the system. (b) For a certain process that occurs at constant \(T\) and \(P,\) the value of \(\Delta G\) is positive. What can you conclude? (c) What is the relationship between \(\Delta G\) for a process and the rate at which it occurs?

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