Elements in the same group of the periodic table often form oxyanions with the same general formula. The anions are also named in a similar fashion. Based on these observations, suggest a chemical formula or name, as appropriate, for each of (b) \(\mathrm{SeO}_{3}^{2-}\) the following ions: (a) \(\mathrm{BrO}_{4}^{-}\), (c) arsenate ion, (d) hydrogen tellurate ion.

Short Answer

Expert verified
The chemical formulas for the given ions are: (a) \(\mathrm{BrO}_{4}^{-}\) (as already given), (c) arsenate ion - \(\mathrm{AsO}_{4}^{3-}\), and (d) hydrogen tellurate ion - \(\mathrm{HTeO}_{3}^{-}\).

Step by step solution

01

Finding the pattern for oxyanions

We can use the given oxyanion, \(\mathrm{SeO}_{3}^{2-}\) (selenite ion) as the reference point for our pattern. Selenite ion contains selenium (Se) which belongs to the same group as tellurium (Te), arsenic (As), and bromine (Br). Now we can find the chemical formulas for the other ions.
02

Finding the chemical formula for (a) \(\mathrm{BrO}_{4}^{-}\)

Since bromine (Br) is right above selenium (Se) in the periodic table, we can expect that bromine would form a similar oxyanion as the selenium (Se) - just with one more oxygen atom and a higher oxidation state. Thus, the chemical formula for bromine-containing oxyanion is already given as \(\mathrm{BrO}_{4}^{-}\).
03

Finding the chemical formula for (c) arsenate ion

Arsenic (As) is right above selenium (Se) in the periodic table as well. Selenite ion has the chemical formula \(\mathrm{SeO}_{3}^{2-}\), so based on the same pattern as before for bromine, arsenic is likely to form an oxyanion with the same number of oxygens and similar charge. Thus, the chemical formula for the arsenate ion, which is As-containing oxyanion, should be \(\mathrm{AsO}_{4}^{3-}\).
04

Finding the chemical formula for (d) hydrogen tellurate ion

Tellurium (Te) is right below selenium (Se) in the periodic table, and as before, we can deduce that Te oxyanion should have the same number of oxygen atoms as the Se oxyanion. So the oxyanion should have a formula of \(\mathrm{TeO}_{3}^{2-}\). Now, we need to form the hydrogen tellurate ion, which has one hydrogen (H) atom added to neutralize one negative charge. With that in mind, we can write the chemical formula for hydrogen tellurate ion as \(\mathrm{HTeO}_{3}^{-}\).

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