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Chapter 2: Problem 45

How many hydrogen atoms are in each of the following: (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH},\) (b) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2},\) (c) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} ?\)

Short Answer

Expert verified
In the given compounds: (a) \(C_{2}H_{5}OH\) has 6 hydrogen atoms. (b) \(Ca(CH_{3}COO)_{2}\) has 6 hydrogen atoms. (c) \((NH_{4})_{3}PO_{4}\) has 12 hydrogen atoms.

Step by step solution

01

Analyze molecular formulas

First, let's analyze each molecular formula and identify the parts that contain hydrogen atoms. (a) C2H5OH There is one part containing hydrogen atoms: H5 and OH. (b) Ca(CH3COO)2 In this compound, Ca does not contain hydrogen atoms. We need to analyze the part inside the parentheses: (CH3COO)2. We can see H3 inside. (c) (NH4)3PO4 In this compound, the part containing hydrogen atoms is inside the parentheses: NH4. There is no hydrogen atom in PO4.
02

Count hydrogen atoms in each part

Now that we have identified the parts containing hydrogen atoms in each formula, we can count them up to find the total number of hydrogen atoms. (a) C2H5OH H5 has 5 hydrogen atoms. OH has 1 hydrogen atom. 5 hydrogen atoms in H5 + 1 hydrogen atom in OH = 6 hydrogen atoms (b) Ca(CH3COO)2 The compound inside the parentheses, CH3COO, has 3 hydrogen atoms in CH3, and the subscript 2 indicates that there are two of these compounds. So, we have to multiply the hydrogen count by 2. 3 hydrogen atoms in CH3 x 2 = 6 hydrogen atoms (c) (NH4)3PO4 NH4 has 4 hydrogen atoms, and the subscript 3 represents that there are three NH4 in the compound. 4 hydrogen atoms in NH4 x 3 = 12 hydrogen atoms
03

Write down the answer

Now that we have calculated the total number of hydrogen atoms in each compound, let us write down the answer. (a) C2H5OH has 6 hydrogen atoms. (b) Ca(CH3COO)2 has 6 hydrogen atoms. (c) (NH4)3PO4 has 12 hydrogen atoms.

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Most popular questions from this chapter

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