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Chapter 2: Problem 62

Selenium, an element required nutritionally in trace quantities, forms compounds analogous to sulfur. Name the following ions: (a) \(\mathrm{SeO}_{4}^{2-},(\mathbf{b}) \mathrm{Se}^{2-}\) (c) \(\mathrm{HSe}^{-}\), (d) \(\mathrm{HSeO}_{3}^{-}\).

Short Answer

Expert verified
The ions are named as follows: (a) SeO4^2- is selenate, (b) Se^2- is selenide, (c) HSe^- is hydrogen selenide, and (d) HSeO3^- is hydrogen selenite.

Step by step solution

01

Ion (a): SeO4^2-

Using the analogy with sulfur, we observe that the equivalent sulfur ion is SO4^2-, which is named sulfate. Therefore, the name of the SeO4^2- ion is selenate.
02

Ion (b): Se^2-

Based on the analogy with sulfur, we see that the equivalent sulfur ion is S^2-, which is named sulfide. Consequently, the name of the Se^2- ion is selenide.
03

Ion (c): HSe^-

For this ion, the sulfur counterpart is HS^-, which is named hydrogen sulfide. As a result, the name of the HSe^- ion is hydrogen selenide.
04

Ion (d): HSeO3^-

The analogous sulfur ion for this compound is HSO3^-, which we know as hydrogen sulfite. Therefore, the name of the HSeO3^- ion is hydrogen selenite.

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Most popular questions from this chapter

The element lead (Pb) consists of four naturally occurring isotopes with atomic masses 203.97302,205.97444,206.97587 , and 207.97663 amu. The relative abundances of these four isotopes are 1.4,24.1,22.1 , and \(52.4 \%\), respectively. From these data, calculate the atomic weight of lead.

How many of the indicated atoms are represented by each chemical formula: (a) carbon atoms in \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COOCH}_{3}\), (b) oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{4}\right)_{2}\), (c) hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4} ?\)

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