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Chapter 2: Problem 86

Identify the element represented by each of the following symbols and give the number of protons and neutrons in each: (a) \(33^{7} X\), (b) \(\frac{127}{53} \mathrm{X}\), (c) \(\frac{152}{63} \mathrm{X}\) (d) \({ }_{83}^{209} \mathrm{X}\).

Short Answer

Expert verified
(a) The element is nitrogen (N) with 7 protons and 26 neutrons. (b) The element is iodine (I) with 53 protons and 74 neutrons. (c) The element is europium (Eu) with 63 protons and 89 neutrons. (d) The element is bismuth (Bi) with 83 protons and 126 neutrons.

Step by step solution

01

(a) Identify the element and number of protons and neutrons for \(^{33}_7 X\)

First, we need to find out which element has the atomic number 7. Looking at the periodic table, we can see that the element with atomic number 7 is nitrogen (N). Now, let's find the number of neutrons: Neutrons = Mass number - Atomic number Neutrons = \(33 - 7 = 26\) Thus, the element is nitrogen (N), and it has 7 protons and 26 neutrons.
02

(b) Identify the element and number of protons and neutrons for \(\frac{127}{53} \mathrm{X}\)

Next, we need to find out which element has the atomic number 53. From the periodic table, the element with atomic number 53 is iodine (I). Now, let's find the number of neutrons: Neutrons = Mass number - Atomic number Neutrons = \(127 - 53 = 74\) The element is iodine (I), and it has 53 protons and 74 neutrons.
03

(c) Identify the element and number of protons and neutrons for \(\frac{152}{63} \mathrm{X}\)

Now, let's find the element with the atomic number 63. Looking at the periodic table, the element with atomic number 63 is europium (Eu). Let's find the number of neutrons: Neutrons = Mass number - Atomic number Neutrons = \(152 - 63 = 89\) The element is europium (Eu), and it has 63 protons and 89 neutrons.
04

(d) Identify the element and number of protons and neutrons for \(^{209}_{83} \mathrm{X}\)

Finally, we need to find out which element has the atomic number 83. From the periodic table, the element with atomic number 83 is bismuth (Bi). Now, let's find the number of neutrons: Neutrons = Mass number - Atomic number Neutrons = \(209 - 83 = 126\) The element is bismuth (Bi), and it has 83 protons and 126 neutrons.

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Most popular questions from this chapter

Name each of the following oxides. Assuming that the compounds are ionic, what charge is associated with the metallic element in each case? (a) \(\mathrm{NiO},(\mathbf{b}) \mathrm{MnO}_{2},\) (c) \(\mathrm{Cr}_{2} \mathrm{O}_{3},(\mathrm{~d}) \mathrm{MoO}_{3}\).

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