Use Coulomb's law, \(F=k Q_{1} Q_{2} / d^{2},\) to calculate the electric force on an electron \(\left(Q=-1.6 \times 10^{-19} \mathrm{C}\right)\) exerted by a single proton if the particles are \(0.53 \times 10^{-10} \mathrm{~m}\) apart. The constant \(k\) in Coulomb's law is \(9.0 \times 10^{9} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2}\). (The unit abbreviated \(\mathrm{N}\) is the newton, the SI unit of force.)

Short Answer

Expert verified
The electric force exerted by a single proton on an electron, when the particles are \(0.53 \times 10^{-10} m\) apart, is approximately \(5.12 \times 10^{-9} N\).

Step by step solution

01

Identify given information

We are given the following information: - Charge of an electron: \(Q_1 = -1.6 \times 10^{-19} C\) - Charge of a proton: \(Q_2 = 1.6 \times 10^{-19} C\) (we know the magnitude of the charge is equal to the charge of an electron, but with the opposite sign) - Distance between the electron and proton: \(d = 0.53 \times 10^{-10} m \) - Coulomb's constant: \(k = 9.0 \times 10^9 N \cdot m^2 / C^2\)
02

Apply Coulomb's Law formula

Using the given charges, distance, and Coulomb's constant, we can now find the electric force between the electron and the proton by applying Coulomb's Law: \[ F = \frac{k \cdot Q_1 \cdot Q_2}{d^2} \]
03

Substitute the given values

Now substitute the values in the formula: \[ F = \frac{(9.0 \times 10^9 N \cdot m^2 / C^2)(-1.6 \times 10^{-19} C)(1.6 \times 10^{-19} C)}{(0.53 \times 10^{-10} m)^2} \]
04

Solve for the electric force

Simplify the expression and solve for the electric force: \[ F = \frac{(9.0 \times 10^9)(16 \times 10^{-38})}{2.809 \times 10^{-20}} \] \[ F = \frac{14.4 \times 10^{-28}}{2.809 \times 10^{-20}} \] \[ F = 5.12 \times 10^{-9} N \] The electric force exerted by a single proton on an electron, when the particles are \(0.53 \times 10^{-10} m\) apart, is approximately \(5.12 \times 10^{-9} N\).

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