(a) Based on standard reduction potentials, would you expect copper metal to oxidize under standard conditions in the presence of oxygen and hydrogen ions? (b) When the Statue of Liberty was refurbished, Teflon spacers were placed between the iron skeleton and the copper metal on the surface of the statue. What role do these spacers play?

Short Answer

Expert verified
(a) Yes, copper metal would oxidize under standard conditions in the presence of oxygen and hydrogen ions, based on the standard reduction potentials. Specifically, copper will oxidize in the presence of oxygen more so than in the presence of hydrogen ions, as the reaction process has a positive cell potential of 0.89V. (b) Teflon spacers play an essential role in preventing galvanic corrosion between the iron skeleton and the copper surface of the Statue of Liberty. By placing Teflon spacers between the iron and copper, an insulating barrier is created to prevent electrical contact. This barrier protects the iron skeleton from corroding in the presence of the more noble copper metal.

Step by step solution

01

(Step 1: Obtain the standard reduction potentials)

(Look up the standard reduction potentials for oxygen, hydrogen, and copper. You can find these in a reference material or online.) For oxygen and hydrogen, the reactions are as follows: \(O_2(g) + 4H^+ + 4e^- \rightarrow 2H_2O(l)\) \(E^{\circ} = 1.23V\) \(2H^+ + 2e^- \rightarrow H_2(g)\) \(E^{\circ} = 0V\) For copper: \(Cu^{2+} + 2e^- \rightarrow Cu(s)\) \(E^{\circ} = 0.34V\) We will use these reduction potentials to determine the feasibility of reactions involving copper and the given substances.
02

(Step 2: Analyze the reaction between copper, oxygen, and hydrogen ions)

(Based on the reduction potentials, we can now analyze if copper metal would oxidize in the presence of oxygen and hydrogen ions.) If copper metal were to oxidize, the reaction should be: \(Cu(s) \rightarrow Cu^{2+} + 2e^-\) To find the feasibility of this reaction, we need to pair it with another half-reaction involving either oxygen or hydrogen ions. The most favorable pair would be the one with the highest positive value for the overall cell potential (calculated as the difference between the reduction potentials of the two half-reactions). When pairing with oxygen reduction: \(E^{\circ}_{cell} = E^{\circ}_{(O_2/H_2O)} - E^{\circ}_{(Cu^{2+}/Cu)} = 1.23 - 0.34 = 0.89V\) When pairing with hydrogen reduction: \(E^{\circ}_{cell} = E^{\circ}_{(H^+/H_2)} - E^{\circ}_{(Cu^{2+}/Cu)} = 0 - 0.34 = -0.34V\) As per the first pair, the cell's potential is positive (0.89 V), which means the reaction involving copper oxidation and oxygen reduction is feasible.
03

(Part a: Answer for Part a)

(Now we can answer Part a of the exercise.) Yes, copper metal would oxidize under standard conditions in the presence of oxygen and hydrogen ions, based on the standard reduction potentials. Specifically, copper will oxidize in the presence of oxygen more so than in the presence of hydrogen ions, as the reaction process has a positive cell potential of 0.89V.
04

(Step 3: Analyze the role of Teflon spacers in the refurbishment of the Statue of Liberty)

(To answer this question, we need to consider the electrochemical properties of iron and copper.) When two different metals come into contact with each other, galvanic corrosion can occur. Galvanic corrosion is an electrochemical process where one metal corrodes more readily when in electrical contact with a more noble metal. In the case of the Statue of Liberty, the iron skeleton (less noble metal) could corrode in the presence of copper (more noble metal) and the surrounding humid and saline environment.
05

(Part b: Answer for Part b)

(Now, let's answer Part b of the exercise referring to the role of Teflon spacers.) Teflon spacers play an essential role in preventing galvanic corrosion between the iron skeleton and the copper surface of the Statue of Liberty. By placing Teflon spacers between the iron and copper, an insulating barrier is created to prevent electrical contact. This barrier protects the iron skeleton from corroding in the presence of the more noble copper metal.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the equilibrium constant for a two-electron redox reaction at \(298 \mathrm{~K}\) is \(1.5 \times 10^{-4},\) calculate the corresponding \(\Delta G^{\circ}\) and \(E_{\text {red }}^{\circ}\).

A disproportionation reaction is an oxidation-reduction reaction in which the same substance is oxidized and reduced. Complete and balance the following disproportionation reactions: (a) \(\mathrm{Ni}^{+}(a q) \longrightarrow \mathrm{Ni}^{2+}(a q)+\mathrm{Ni}(s) \quad\) (acidic solution) (b) \(\mathrm{MnO}_{4}^{2-}(a q) \longrightarrow \mathrm{MnO}_{4}^{-}(a q)+\mathrm{MnO}_{2}(s)\) (acidic solution) (c) \(\mathrm{H}_{2} \mathrm{SO}_{3}(a q) \longrightarrow \mathrm{S}(s)+\mathrm{HSO}_{4}^{-}(a q) \quad\) (acidic solution) (d) \(\mathrm{Cl}_{2}(a q) \longrightarrow \mathrm{Cl}^{-}(a q)+\mathrm{ClO}^{-}(a q)\) (basic solution)

Consider the half-reaction \(\mathrm{Ag}^{+}(a q)+\mathrm{e}^{-} \longrightarrow \mathrm{Ag}(s)\). Which of the lines in the following diagram indicates how the reduction potential varies with the concentration of \(\mathrm{Ag}^{+} ?(\mathrm{~b})\) What is the value of \(E_{\mathrm{red}}\) when \(\log \left[\mathrm{Ag}^{+}\right]=0 ?\) [Section \(\left.20.6\right]\)

(a) A voltaic cell is constructed with all reactants and products in their standard states. Will this condition hold as the cell operates? Explain. (b) Can the Nernst equation be used at temperatures other than room temperature? Explain. (c) What happens to the emf of a cell if the concentrations of the products are increased?

(a) What happens to the emf of a battery as it is used? Why does this happen? (b) The AA-size and D-size alkaline batteries are both \(1.5-\mathrm{V}\) batteries that are based on the same electrode reactions. What is the major difference between the two batteries? What performance feature is most affected by this difference?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free