Select the more acidic member of each of the following pairs: (a) \(\mathrm{Mn}_{2} \mathrm{O}_{7}\) and \(\mathrm{MnO}_{2}\), (b) \(\mathrm{SnO}\) and \(\mathrm{SnO}_{2}\), (c) \(\mathrm{SO}_{2}\) and \(\mathrm{SO}_{3}\), (d) \(\mathrm{SiO}_{2}\) and \(\mathrm{SO}_{2}\), (e) \(\mathrm{Ga}_{2} \mathrm{O}_{3}\) and \(\mathrm{In}_{2} \mathrm{O}_{3},\) (f) \(\mathrm{SO}_{2}\) and \(\mathrm{SeO}_{2}\).

Short Answer

Expert verified
The more acidic members of the given pairs are: (a) \(\mathrm{Mn}_{2} \mathrm{O}_{7}\), (b) \(\mathrm{SnO}_{2}\), (c) \(\mathrm{SO}_{3}\), (d) \(\mathrm{SO}_{2}\), (e) \(\mathrm{Ga}_{2} \mathrm{O}_{3}\), and (f) \(\mathrm{SO}_{2}\).

Step by step solution

01

Pair (a): \(\mathrm{Mn}_{2} \mathrm{O}_{7}\) and \(\mathrm{MnO}_{2}\)

Manganese heptoxide (\(\mathrm{Mn}_{2} \mathrm{O}_{7}\)) is a compound in which manganese has an oxidation state of +7, while manganese dioxide (\(\mathrm{MnO}_{2}\)) has manganese in the +4 oxidation state. Higher oxidation states generally result in a more acidic compound because the central atom is more electronegative and can stabilize the conjugate base better. Therefore, \(\mathrm{Mn}_{2} \mathrm{O}_{7}\) is the more acidic member of this pair.
02

Pair (b): \(\mathrm{SnO}\) and \(\mathrm{SnO}_{2}\)

For tin monoxide (\(\mathrm{SnO}\)), tin has an oxidation state of +2, while for tin dioxide (\(\mathrm{SnO}_{2}\)), the oxidation state is +4. As discussed in the previous pair, compounds with higher oxidation states are generally more acidic. Therefore, \(\mathrm{SnO}_{2}\) is the more acidic member of this pair.
03

Pair (c): \(\mathrm{SO}_{2}\) and \(\mathrm{SO}_{3}\)

Sulfur dioxide (\(\mathrm{SO}_{2}\)) has sulfur in the +4 oxidation state, while sulfur trioxide (\(\mathrm{SO}_{3}\)) has sulfur in the +6 oxidation state. Due to the higher electronegativity and oxidation state in \(\mathrm{SO}_{3}\), it is more acidic than \(\mathrm{SO}_{2}\).
04

Pair (d): \(\mathrm{SiO}_{2}\) and \(\mathrm{SO}_{2}\)

Silicon dioxide (\(\mathrm{SiO}_{2}\)) has silicon in the +4 oxidation state, while sulfur dioxide (\(\mathrm{SO}_{2}\)) has sulfur in the +4 oxidation state. Though both central atoms have the same oxidation state, sulfur is more electronegative than silicon. Thus, \(\mathrm{SO}_{2}\) is more acidic than \(\mathrm{SiO}_{2}\).
05

Pair (e): \(\mathrm{Ga}_{2} \mathrm{O}_{3}\) and \(\mathrm{In}_{2} \mathrm{O}_{3}\)

Gallium oxide (\(\mathrm{Ga}_{2} \mathrm{O}_{3}\)) has gallium in the +3 oxidation state, as does indium oxide (\(\mathrm{In}_{2} \mathrm{O}_{3}\)) for indium. They are in the same group in the periodic table, so we must compare their electronegativities. Gallium is more electronegative than indium, so \(\mathrm{Ga}_{2} \mathrm{O}_{3}\) is the more acidic member of this pair.
06

Pair (f): \(\mathrm{SO}_{2}\) and \(\mathrm{SeO}_{2}\)

Sulfur dioxide (\(\mathrm{SO}_{2}\)) has sulfur in the +4 oxidation state, and selenium dioxide (\(\mathrm{SeO}_{2}\)) has selenium in the +4 oxidation state. Both are in the same group in the periodic table, so we must compare their electronegativities. Sulfur is more electronegative than selenium, so \(\mathrm{SO}_{2}\) is the more acidic member of this pair.

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