Write a balanced net ionic equation for each of the following reactions: (a) Dilute nitric acid reacts with zinc metal with formation of nitrous oxide. (b) Concentrated nitric acid reacts with sulfur with formation of nitrogen dioxide. (c) Concentrated nitric acid oxidizes sulfur dioxide with formation of nitric oxide. (d) Hydrazine is burned in excess fluorine gas, forming \(\mathrm{NF}_{3}\). (e) Hydrazine reduces \(\mathrm{CrO}_{4}^{2-}\) to \(\mathrm{Cr}(\mathrm{OH})_{4}^{-}\) in base (hydrazine is oxidized to \(\mathrm{N}_{2}\) ).

Short Answer

Expert verified
(a) \(Zn + 4H^+ + 4NO^-_2 \rightarrow Zn^{2+} + 2NO + 2NO_2 + 2H_2O\) (b) \(6H^+ + 6NO^-_3 + S \rightarrow 2H^+ + SO^{2-}_4 + 6NO_2 + 2H_2O\) (c) \(2NO^-_3 + SO_2 \rightarrow NO + NO_2 + SO^{2-}_4\) (d) \(2F_2 + N_2H_4 \rightarrow 4NF_3\) (e) \(N_2H_4 + 2Cr^{6+} + 8O^{2-} + OH^- \rightarrow N_2 + 2Cr^{3+} + 8OH^-\)

Step by step solution

01

Reaction (a) - Dilute nitric acid reacts with zinc metal with formation of nitrous oxide

First, write the balanced molecular equation: \(Zn + 4HNO_2 \rightarrow Zn^{2+} + 2NO + 2NO_2 + 2H_2O\) Now, break apart the strong electrolytes into their ions to get the total ionic equation: \(Zn + 4H^+ + 4NO^-_2 \rightarrow Zn^{2+} + 2NO + 2NO_2 + 2H_2O\) Group the same ions on both sides and cross out the spectator ions (none in this case). The remaining equation is the net ionic equation: \(Zn + 4H^+ + 4NO^-_2 \rightarrow Zn^{2+} + 2NO + 2NO_2 + 2H_2O\)
02

Reaction (b) - Concentrated nitric acid reacts with sulfur with formation of nitrogen dioxide

First, write the balanced molecular equation: \(6HNO_3 + S \rightarrow H_2SO_4 + 6NO_2 + 2H_2O\) Next, break apart the strong electrolytes into their ions to get the total ionic equation: \(6H^+ + 6NO^-_3 + S \rightarrow 2H^+ + SO^{2-}_4 + 6NO_2 + 2H_2O\) Group the same ions on both sides and cross out the spectator ions (none in this case). The remaining equation is the net ionic equation: \(6H^+ + 6NO^-_3 + S \rightarrow 2H^+ + SO^{2-}_4 + 6NO_2 + 2H_2O\)
03

Reaction (c) - Concentrated nitric acid oxidizes sulfur dioxide with formation of nitric oxide

First, write the balanced molecular equation: \(2HNO_3 + SO_2 \rightarrow NO + NO_2 + H_2SO_4\) Next, break apart the strong electrolytes into their ions to get the total ionic equation: \(2H^+ + 2NO^-_3 + SO_2 \rightarrow NO + NO_2 + 2H^+ + SO^{2-}_4\) Group the same ions on both sides and cross out the spectator ions (H^+ in this case). The remaining equation is the net ionic equation: \(2NO^-_3 + SO_2 \rightarrow NO + NO_2 + SO^{2-}_4\)
04

Reaction (d) - Hydrazine is burned in excess fluorine gas, forming \(\mathrm{NF}_{3}\)

First, write the balanced molecular equation: \(2F_2 + N_2H_4 \rightarrow 4NF_3\) This reaction does not involve ions, so no further decomposition is needed. The net ionic equation is the same as the molecular equation: \(2F_2 + N_2H_4 \rightarrow 4NF_3\)
05

Reaction (e) - Hydrazine reduces \(\mathrm{CrO}_{4}^{2-}\) to \(\mathrm{Cr}(\mathrm{OH})_{4}^{-}\) in base (hydrazine is oxidized to \(\mathrm{N}_{2}\) )

First, write the balanced molecular equation: \(N_2H_4 + 2CrO^{2-}_4 + OH^- \rightarrow N_2 + 2Cr(OH^-)_4\) Next, break apart the strong electrolytes into their ions to get the total ionic equation: \(N_2H_4 + 2Cr^{6+} + 8O^{2-} + OH^- \rightarrow N_2 + 2Cr^{3+} + 8OH^-\) Group the same ions on both sides and cross out the spectator ions (none in this case). The remaining equation is the net ionic equation: \(N_2H_4 + 2Cr^{6+} + 8O^{2-} + OH^- \rightarrow N_2 + 2Cr^{3+} + 8OH^-\)

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