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Chapter 23: Problem 2

(a) Draw the structure for \(\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2} .\) (b) What is the coordination number for platinum in this complex, and what is the coordination geometry? (c) What is the oxidation state of the platinum? [Section 23.2]

Short Answer

Expert verified
The structure of the complex \(\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2}\) is: ``` Cl en \ / Pt------N | | ------- ``` The coordination number for platinum is 4, and the coordination geometry is square planar. The oxidation state of platinum in this complex is +2.

Step by step solution

01

Draw the structure of the complex

First, let's identify the components of the complex. Pt is the central metal atom, en (ethylenediamine) is the bidentate ligand, and Cl is the monodentate ligand. Ethylenediamine is represented as H2N-CH2-CH2-NH2. In the complex \(\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2}\), the two chlorines and the N atoms from the ethylenediamine molecule form bonds with the central platinum atom. So, the structure of the complex would look like this: ``` Cl en \ / Pt------N | | ------- ```
02

Determine the coordination number and coordination geometry

The coordination number is the number of ligand atoms bonded to the central metal atom. In this complex, we have two Cl atoms, and the ethylenediamine molecule has two N atoms, which are bonded to Pt. So, the coordination number for platinum in this complex is 2 (Cl) + 2 (N) = 4. The coordination geometry is determined by considering how the ligands are arranged around the central metal atom. Since there are four ligands around Pt, the coordination geometry is square planar.
03

Determine the oxidation state of platinum

To calculate the oxidation state of platinum in this complex, we need to determine the charges of all the ligands. Cl has an oxidation state of -1. Since the ethylenediamine molecule is neutral, it contributes no charge to the complex. The sum of charges in the complex is given by the sum of the oxidation state of platinum and the charges of the ligands. Let the oxidation state of platinum (Pt) be x: x + 0 (charge for en) + (-1) (charge for first Cl) + (-1) (charge for second Cl) = 0 x - 2 = 0 x = 2 Hence, the oxidation state of the platinum in the complex \(\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2}\) is +2.

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Most popular questions from this chapter

No compounds are known in which scandium is in the +2 oxidation state. Suggest an explanation.

A classmate says, "A weak-field ligand usually means the complex is high spin." Is your classmate correct? Explain.

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Explain why the \(d_{x y}, d_{x z}\), and \(d_{y z}\) orbitals lie lower in energy than the \(d_{z}^{2}\) and \(d_{x^{2}-y^{2}}\) orbitals in the presence of an octahedral arrangement of ligands about the central metal ion.

For each of the following polydentate ligands, determine (i) the maximum number of coordination sites that the ligand can occupy on a single metal ion and (ii) the number and type of donor atoms in the ligand: (a) ethylenediamine (en), (b) bipyridine (bipy), (c) the oxalate anion \(\left(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\right),(\mathrm{d})\) the \(2-\) ion of the porphine molecule (Figure 23.13 ); (e) [EDTA] \(]\) -
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