(a) What is the difference between Werner's concepts of primary valence and secondary valence? What terms do we now use for these concepts? (b) Why can the \(\mathrm{NH}_{3}\) molecule serve as a ligand but the \(\mathrm{BH}_{3}\) molecule cannot?

Short Answer

Expert verified
(a) Werner's primary valence refers to the oxidation state of a central metal ion, while secondary valence refers to the coordination number, i.e., the number of coordinating ligands. Nowadays, we use the terms oxidation state and coordination number. (b) \(\mathrm{NH}_{3}\) can serve as a ligand because it has a lone pair of electrons on the nitrogen atom, which can form a coordinate covalent bond with a central metal ion. In contrast, \(\mathrm{BH}_{3}\) cannot act as a ligand because boron has no available lone pair of electrons to form such bond.

Step by step solution

01

Understand Primary and Secondary Valences

Werner's coordination theory introduced the concepts of primary valence and secondary valence to explain the behavior of complex compounds. Primary valence refers to the number of negative ions required to satisfy the charge of a central metal ion in a coordination compound, and it represents the oxidation state of the central atom (metal). Secondary valence, on the other hand, refers to the number of ligands (neutral, cationic, or anionic) that coordinate to the central metal ion. It represents the coordination number of the complex.
02

Current Terms for Primary and Secondary Valences

Nowadays, the primary valence concept is usually called ionic or oxidation state, while the secondary valence concept is often referred to as the coordination number, which represents the number of coordinating ligands.
03

Discuss why NH3 can act as a ligand and BH3 can't

A ligand is a molecule or ion that can donate an electron pair to a central metal ion in a coordination compound. In the case of the \(\mathrm{NH}_{3}\) molecule (ammonia), there is a lone pair of electrons on the nitrogen atom which can participate in the formation of a coordinate covalent bond with a central metal ion. This electron donation makes \(\mathrm{NH}_{3}\) a good ligand. As for the \(\mathrm{BH}_{3}\) molecule (borane), there are three single covalent bonds between the boron atom and the three hydrogen atoms. Boron has only three valence electrons, which means all of its valence electrons are shared with the hydrogen atoms in the bonds, and there is no remaining lone pair on the boron atom to participate in the formation of a coordinate covalent bond with a central metal ion. Hence, a \(\mathrm{BH}_{3}\) molecule cannot act as a ligand.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free