If a transition-metal complex has an even number of valence \(\bar{d}\) electrons, does it necessarily mean that the complex is diamagnetic? Explain.

Short Answer

Expert verified
In general, a transition-metal complex with an even number of valence d electrons has the potential to be diamagnetic, as their electron configurations allow for electron pairing in the orbitals. However, the influence of ligands or other factors can alter the electronic structure in specific cases, so it is not a definitive rule that an even number of valence d electrons always result in a diamagnetic complex, but it is more likely than not.

Step by step solution

01

Define Diamagnetic and Paramagnetic

Diamagnetic substances are materials that are not attracted to a magnetic field, while paramagnetic substances are attracted to a magnetic field. The difference between these two types of substances lies in the electron configuration of their atoms or, in this case, the metal ion in a complex. In a diamagnetic substance, all electrons are paired in their respective atomic or molecular orbitals, whereas in a paramagnetic substance, there are one or more unpaired electrons in the atomic or molecular orbitals.
02

Determine Conditions for Diamagnetism

To be diamagnetic, all the electrons in the valence d orbitals must be paired. Now, let's explore the possibility of a metal complex with an even number of valence d electrons being diamagnetic.
03

Consider Electron Configurations

Let's analyze the possible electron configurations for even numbers of valence d electrons: - For 2 valence d electrons, the electron configuration is \(d^2\) (2 electrons paired in a single d orbital). - For 4 valence d electrons, the electron configuration is \(d^4\) (2 electrons paired in two d orbitals). - For 6 valence d electrons, the electron configuration is \(d^6\) (2 electrons paired in three d orbitals). - For 8 valence d electrons, the electron configuration is \(d^8\) (2 electrons paired in four d orbitals). - For 10 valence d electrons, the electron configuration is \(d^{10}\) (2 electrons paired in all five d orbitals).
04

Analyzing Diamagnetism

In all the above electron configurations, electrons are paired in their respective d orbitals, resulting in a diamagnetic substance. However, it is important to note that there may be exceptions in certain cases where the ligands or other factors can affect the electronic structure of the metal ion within the complex.
05

Conclusion

In general, a transition-metal complex with an even number of valence d electrons has the potential to be diamagnetic since all electrons can theoretically be paired in their orbitals. However, it is important to consider the influence of ligands or other factors, as they may alter the electronic structure in specific cases. Overall, it is not a definitive rule that an even number of valence d electrons always result in a diamagnetic complex, but it is more likely than not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding electron configuration is fundamental when studying transition metal complexes. The electron configuration of an atom or ion tells us how electrons are distributed across different orbitals. In transition metals, these configurations play a pivotal role because the metals typically have an incomplete d sub-shell, which can give rise to various oxidation states and coordination configurations.

When it comes to transition-metal complexes, the electron arrangement in the d orbitals becomes a bit complex due to splitting of the d orbitals in the presence of ligands - this is known as crystal field theory. Electrons will fill the lower energy d orbitals first before moving to higher energy ones. This filling can result in all electrons being paired (even number of valence d electrons) or can leave some unpaired. However, the presence of an even number of electrons does not guarantee all electrons will be paired because of factors such as electron-electron repulsions and the geometry of the complex.
Paramagnetism
Paramagnetism is a form of magnetism which occurs only in the presence of an externally applied magnetic field. Paramagnetic materials are attracted to magnetic fields, which can be easily demonstrated with laboratory instruments. The key feature that differentiates a paramagnetic substance from a diamagnetic one is the presence of at least one unpaired electron in the atomic or molecular orbitals of the material.

Atoms, ions, or molecules with unpaired electrons have a net magnetic moment that can align with a magnetic field, making the substance attracted to it. In contrast, diamagnetic substances have all electrons paired and exhibit no net magnetic moment. Paramagnetism is often observed in transition metal complexes because of their frequently encountered unpaired d electrons.
Transition Metal Chemistry
Transition metal chemistry is characterized by the ability of metals to form a wide variety of compounds, often exhibiting colorful and magnetic properties. These metals are defined by their partially filled d or f orbitals and include elements from groups 3 through 12 on the periodic table.

Transition metals can display several oxidation states and typically form coordination complexes with various ligands, which can be neutral, negatively, or positively charged species. The chemistry of these metals is further complicated because these ligands can influence the distribution of electrons in the d orbitals through effects such as crystal field or ligand field stabilization, sometimes leading to unexpected behavior in terms of reactivity and physical properties like color and magnetism.
Magnetic Properties of Complexes
The magnetic properties of complexes are directly tied to their electron configurations. Diamagnetism and paramagnetism are two critical aspects of these properties. A dia-magnetic complex is one that is not attracted to an external magnetic field. This is typically because such a complex has paired electrons in all of its molecular orbitals, resulting in no net magnetic moment. As mentioned, though transition-metal complexes with an even number of valence d electrons are often dia-magnetic, this is not always the case as the magnetism of a complex is not determined solely by the electron count but also by the way those electrons are arranged in orbitals.

Understanding the magnetic behavior of complexes helps in the elucidation of their electron configuration and can inform on the geometry and bonding characteristics of a complex. It's important for students to grasp that while simple counting of electrons provides a useful starting point, the complete magnetic character of a transition-metal complex often requires deeper analysis incorporating both electronic structure and ligand effects.

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Most popular questions from this chapter

Metallic elements are essential components of many important enzymes operating within our bodies. Carbonic anhydrase, which contains \(\mathrm{Zn}^{2+}\) in its active site, is responsible for rapidly interconverting dissolved \(\mathrm{CO}_{2}\) and bicarbonate ion, \(\mathrm{HCO}_{3}^{-}\). The zinc in carbonic anhydrase is tetrahedrally coordinated by three neutral nitrogen- containing groups and a water molecule. The coordinated water molecule has a \(\mathrm{p} K_{a}\) of \(7.5,\) which is crucial for the enzyme's activity. (a) Draw the active site geometry for the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase, just writing \({ }^{4} \mathrm{~N}^{n}\) for the three neutral nitrogen ligands from the protein. (b) Compare the \(\mathrm{p} K_{a}\) of carbonic anhydrase's active site with that of pure water; which species is more acidic? (c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the \(\mathrm{Zn}(\mathrm{II})\) center? Assume the three nitrogen ligands are unaffected. (d) The \(\mathrm{p} K_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is \(10 .\) Suggest an explanation for the difference between this \(\mathrm{p} K_{a}\) and that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a deep color, like hemoglobin and other metal-ion containing proteins do? Explain.

Consider an octahedral complex \(\mathrm{MA}_{3} \mathrm{~B}_{3} .\) How many geometric isomers are expected for this compound? Will any of the isomers be optically active? If so, which ones?

(a) Draw the structure for \(\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_{2} .\) (b) What is the coordination number for platinum in this complex, and what is the coordination geometry? (c) What is the oxidation state of the platinum? [Section 23.2]

Explain the difference between a diamagnetic substance and a paramagnetic substance.

Consider the tetrahedral anions \(\mathrm{VO}_{4}^{3-}\) (orthovanadate ion), \(\mathrm{CrO}_{4}^{2-}(\) chromate ion \(),\) and \(\mathrm{MnO}_{4}^{-}\) (permanganate ion). (a) These anions are isoelectronic. What does this statement mean? (b) Would you expect these anions to exhibit \(d-d\) transitions? Explain. (c) As mentioned in "A Closer Look" on charge-transfer color, the violet color of \(\mathrm{MnO}_{4}^{-}\) is due to a ligand-to-metal charge transfer (LMCT) transition. What is meant by this term? (d) The LMCT transition in \(\mathrm{MnO}_{4}^{-}\) occurs at a wavelength of \(565 \mathrm{nm}\). The \(\mathrm{CrO}_{4}^{2-}\) ion is yellow. Is the wavelength of the LMCT transition for chromate larger or smaller than that for \(\mathrm{MnO}_{4}^{-}\) ? Explain. (e) The \(\mathrm{VO}_{4}{ }^{3-}\) ion is colorless. Do you expect the light absorbed by the LMCT to fall in the UV or the IR region of the electromagnetic spectrum? Explain your reasoning.

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