(a) Sketch a diagram that shows the definition of the crystal-field splitting energy \((\Delta)\) for an octahedral crystal field. (b) What is the relationship between the magnitude of \(\Delta\) and the energy of the d- \(d\) transition for a \(d^{1}\) complex? (c) Calculate \(\Delta\) in \(\mathrm{kJ} / \mathrm{mol}\) if a \(d^{1}\) complex has an absorption maximum at \(545 \mathrm{nm}\).

Short Answer

Expert verified
(a) In an octahedral crystal field, the energy levels of the d orbitals split into two groups - \(t_{2g}\) (having three orbitals) and \(e_{g}\) (having two orbitals), with \(t_{2g}\) orbitals being lower in energy. The crystal-field splitting energy, Δ, is the energy difference between these two groups. (b) The relationship between the magnitude of Δ and the energy of the d-d transition for a d¹ complex is \(E = \Delta\), where E is the energy of the d-d transition. (c) Given an absorption maximum of 545 nm for a d¹ complex, Δ can be calculated using Planck's equation and converting to kJ/mol, resulting in Δ = \(0.606\mathrm{kJ/mol}\).

Step by step solution

01

(a) Sketching the Definition of Crystal-Field Splitting Energy Δ

To sketch a diagram that shows the definition of the crystal field-splitting energy, Δ, for an octahedral crystal field, we'll use the following steps: 1. Draw the energy levels of the d orbitals in a free ion - all five orbitals will be degenerate (have the same energy). 2. Now, place the free ion into the octahedral crystal field. Due to the electrostatic interactions between the central metal ion and the ligands, the energy levels of the d orbitals will split into two groups - \(t_{2g}\) (having three orbitals) and \(e_{g}\) (having two orbitals). \(t_{2g}\) orbitals have lower energy and point away from the ligands, while \(e_{g}\) orbitals have higher energy and point towards the ligands. 3. Label the difference in energy between \(t_{2g}\) and \(e_{g}\) as Δ (crystal field-splitting energy).
02

(b) Relationship between Δ and the Energy of d-d Transition

In a d¹ complex, the single electron is in the lower-energy \(t_{2g}\) orbital. When the complex absorbs light, this electron can undergo a d-d transition to the higher-energy \(e_{g}\) orbital. The relationship between the magnitude of Δ and the energy of the d-d transition for a d¹ complex is as follows: \(E = \Delta\) Here, E is the energy of the d-d transition, and Δ is the crystal-field splitting energy.
03

(c) Calculating Δ in kJ/mol for Given Absorption Maximum

We are given that a d¹ complex has an absorption maximum at 545 nm. Using this information, we'll calculate the energy of this d-d transition and then find Δ in kJ/mol using the relationship established in part (b). First, we need to convert the wavelength (λ) to energy (E) using the Planck's equation: \(E = \dfrac{hc}{\lambda}\) Here, h is the Planck's constant (\(6.63 \times 10^{-34}\mathrm{Js}\)), c is the speed of light (\(3.00 \times 10^8\mathrm{m/s}\)), and λ is the wavelength in meters. Now, let's plug in the given values: \(E = \dfrac{(6.63 \times 10^{-34}\mathrm{Js})(3.00 \times 10^8\mathrm{m/s})}{545 \times 10^{-9}\mathrm{m}}\) \(E = 3.65 \times 10^{-19}\mathrm{J}\) Next, we need to convert the energy from joules to kJ/mol. To do this, we'll divide the energy in joules by the Avogadro's number (\(6.022 \times 10^{23}\mathrm{mol^{-1}}\)) and then multiply by \(10^{3}\) to convert from joules to kilojoules: \(\Delta = \dfrac{3.65 \times 10^{-19}\mathrm{J}}{6.022 \times 10^{23}\mathrm{mol^{-1}}} \times 10^{3}\mathrm{kJ/mol}\) \(\Delta = 0.606\mathrm{kJ/mol}\) Therefore, the crystal-field splitting energy, Δ, for the given d¹ complex is \(0.606\mathrm{kJ/mol}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Octahedral Crystal Field
When delving into the concept of crystal-field theory, an essential model used to understand how metal ions interact with surrounding ligands, we come across the octahedral crystal field. This is a common coordination environment for transition metal complexes where six ligands symmetrically surround a central metal ion, much like the vertices of an octahedron.

In an octahedral field, the energy levels of the five d-orbitals in a free ion split into two distinct groups due to electrostatic interactions with the approaching ligands. Imagine lining up magnets in a specific pattern and observing how a central magnet responds to their placement–similar principles are at work here on a subatomic scale.

The three d-orbitals that become the \(t_{2g}\) set are lower in energy because they are directed between the ligands, resulting in less electrostatic repulsion. Meanwhile, the two d-orbitals that form the \(e_{g}\) set have higher energy as they point directly at the ligands. The energy gap between these two sets of orbitals is termed the crystal-field splitting energy (\(\Delta\)). It's this energy difference that determines many properties of the complex, including its color and magnetic behaviors.
The d-d Transition
Understanding d-d transitions is crucial as they are responsible for the vivid colors often associated with transition metal complexes. A d-d transition involves an electron jumping from a lower-energy \(t_{2g}\) orbital to a higher-energy \(e_{g}\) orbital within the same d-shell of a transition metal ion.

Think of this process as a tiny energetic leap within an atom. It only occurs when the complex absorbs just the right amount of energy, which typically falls in the visible spectrum for many complexes. The precise amount of energy absorbed corresponds to the difference in energy between \(t_{2g}\) and \(e_{g}\), which is the crystal-field splitting energy, \(\Delta\).

For example, in a \(d^1\) complex, where the metal has a single d-electron, this electron resides in the lower energy \(t_{2g}\) set. When the complex absorbs light, this electron absorbs energy and transitions to the vacant \(e_{g}\) set. So, distinctly, the relationship between the energy of the incoming light and the \(\Delta\) is direct–if you know the energy required for the transition, you can deduce the energy gap \(\Delta\), and vice versa.
Applying Planck's Equation
Planck's equation, a cornerstone of quantum mechanics, provides the crucial link between energy and wavelength for electromagnetic radiation. It is articulated through the relationship \(E = \frac{hc}{\lambda}\), where \(E\) is the energy of a photon, \(h\) is Planck's constant, \(c\) is the speed of light, and \(\lambda\) is the wavelength.

This equation allows us to calculate the energy associated with a photon of a specific wavelength. It's this fundamental understanding that permits scientists to derivate characteristics of atoms and molecules just from knowing the spectral lines they emit or absorb. In the context of a \(d^1\) complex where the wavelength of absorbed light is known (say, 545 nm from our exercise), we can use Planck’s equation to calculate the energy of the d-d transition. That energy, converted to appropriate units such as kilojoules per mole, is directly related to the crystal-field splitting energy \(\Delta\). Thus Planck's equation serves as a bridge that relates the observed color of a complex with the microscopic interactions within the atom.

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Most popular questions from this chapter

CC(=O)[O-] can act a… # Many trace metal ions exist in the blood complexed with amino acids or small peptides. The anion of the amino acid glycine (gly), N#CC(=O)[O-] can act as a bidentate ligand, coordinating to the metal through nitrogen and oxygen atoms. How many isomers are possible for (a) \(\left[\mathrm{Zn}(\mathrm{gly})_{2}\right]\) (tetrahedral), (b) \(\left[\mathrm{Pt}(\mathrm{gly})_{2}\right]\) (square planar), (c) \(\left[\mathrm{Co}(\mathrm{gly})_{3}\right]\) (octahedral)? Sketch all possible isomers. Use the symbol \(\mathrm{N}\) O to represent the ligand.

The molecule methylamine \(\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)\) can act as a monodentate ligand. The following are equilibrium reactions and the thermochemical data at \(298 \mathrm{~K}\) for reactions of methylamine and en with \(\mathrm{Cd}^{2+}(a q):\) $$ \begin{array}{c} \mathrm{Cd}^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) \rightleftharpoons\left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q) \\ \Delta H^{\circ}=-57.3 \mathrm{~kJ} ; \quad \Delta S^{\circ}=-67.3 \mathrm{~J} / \mathrm{K} ; \quad \Delta G^{\circ}=-37.2 \mathrm{~kJ} \\\ \mathrm{Cd}^{2+}(a q)+2 \mathrm{en}(a q) \rightleftharpoons\left[\mathrm{Cd}(\mathrm{en})_{2}\right]^{2+}(a q) \\ \Delta H^{\circ}=-56.5 \mathrm{~kJ} ; \quad \Delta S^{\circ}=+14.1 \mathrm{~J} / \mathrm{K} ; \quad \Delta G^{\circ}=-60.7 \mathrm{~kJ} \end{array} $$ (a) Calculate \(\Delta G^{\circ}\) and the equilibrium constant \(K\) for the following ligand exchange reaction: \(\left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q)+2 \operatorname{en}(a q) \rightleftharpoons\) $$ \left[\mathrm{Cd}(\mathrm{en})_{2}\right]^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) $$ Based on the value of \(K\) in part (a), what would you conclude about this reaction? What concept is demonstrated? (b) Determine the magnitudes of the enthalpic \(\left(\Delta H^{\circ}\right)\) and the entropic \(\left(-T \Delta S^{\circ}\right)\) contributions to \(\Delta G^{\circ}\) for the ligand exchange reaction. Explain the relative magnitudes. (c) Based on information in this exercise and in the "A Closer Look" box on the chelate effect, predict the sign of \(\Delta H^{\circ}\) for the following hypothetical reaction: $$ \begin{aligned} \left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q) &+4 \mathrm{NH}_{3}(a q) \rightleftharpoons \\ \left[\mathrm{Cd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) \end{aligned} $$

Write the names of the following compounds, using the standard nomenclature rules for coordination complexes: (a) \(\left[\mathrm{Rh}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) (b) \(\mathrm{K}_{2}\left[\mathrm{TiCl}_{6}\right]\) (c) \(\mathrm{MoOCl}_{4}\) (d) \(\left[\mathrm{Pt}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\right] \mathrm{Br}_{2}\)

By writing formulas or drawing structures related to any one of these three complexes, \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) \(\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{ONO})_{2}\right]\) cis-[ \(\left.\mathrm{V}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+}\) illustrate (a) geometric isomerism, (b) linkage isomerism, (c) optical isomerism, (d) coordination-sphere isomerism.

Consider an octahedral complex \(\mathrm{MA}_{3} \mathrm{~B}_{3} .\) How many geometric isomers are expected for this compound? Will any of the isomers be optically active? If so, which ones?

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