Draw the condensed structural formulas for the cis and trans isomers of 2 -pentene. Can cyclopentene exhibit cis-trans isomerism? Explain.

First, we need to know that 2-pentene has a carbon-carbon double bond at position 2. We can represent the molecule as CH3-CH=CH-CH2-CH3. Now, let's draw the condensed structural formulas of the cis and trans isomers of 2-pentene: Cis isomer: In the cis isomer, the two top groups (attached to the double-bonded carbon atoms) are on the same side of the double bond: CH3-CH=CH-CH2-CH3 | H Trans isomer: In the trans isomer, the two top groups (attached to the double-bonded carbon atoms) are on the opposite sides of the double bond: CH3-CH=CH-CH2-CH3 | H

Cyclopentene is a cyclic alkene with five carbon atoms in a ring and one double bond. Its structure can be represented as a 5-membered ring with a carbon-carbon double bond. To determine if cyclopentene can exhibit cis-trans isomerism, we need to analyze the positions of the groups attached to the carbon atoms of the double bond. For a compound to exhibit cis-trans isomerism, there should be two different groups attached to each of the double-bonded carbon atoms. In cyclopentene, the double bond is located between two carbons in the ring. Although there are two different groups (a hydrogen and another carbon) attached to each of the carbons involved in the double bond, there is a constraint imposed by the cyclic structure. This constraint makes it impossible for the groups to be on opposite sides of the double bond, and hence cyclopentene cannot exhibit cis-trans isomerism.

We have drawn the condensed structural formulas for the cis and trans isomers of 2-pentene and determined that cyclopentene cannot exhibit cis-trans isomerism due to the constraint imposed by its cyclic structure.