A compound whose empirical formula is \(\mathrm{XF}_{3}\) consists of \(65 \%\) F by mass. What is the atomic mass of X?

Short Answer

Expert verified
The atomic mass of element X in the compound \(\mathrm{XF}_{3}\) is approximately 30.54 g/mol.

Step by step solution

01

Calculate the mass of F in \(\mathrm{XF}_{3}\)

Since \(\mathrm{XF}_{3}\) consists of 65% F by mass, it means that the remaining mass (100%-65%=35%) will be element X. We can assume a total mass of 100 grams for the compound, which would give us 65 grams of F and 35 grams of X. Now, we move on to the following steps.
02

Calculate moles of F

To find the moles of F in the compound, we will use the molar mass of F, which is approximately 19 g/mol. Moles of F = Mass of F / Molar mass of F = 65 g / 19 g/mol = \( \frac{65}{19} \) moles.
03

Calculate the ratio of X to F in moles

Since the empirical formula is \(\mathrm{XF}_{3}\), this means there are 3 moles of F per mole of X. We can use this information to find the moles of X in the compound. Moles of X = \( \frac{1}{3} \times \frac{65}{19} \) = \( \frac{65}{57} \) moles.
04

Calculate the atomic mass of X

Now that we have the moles of X and mass of X, we can find the atomic mass of X using the formula: Atomic mass of X = Mass of X / Moles of X Atomic mass of X = \( \frac{35 \text{ g}}{\frac{65}{57} \text{ moles}} \) Atomic mass of X = \( 35 \times \frac{57}{65} \) Atomic mass of X ≈ 30.54 g/mol Thus, the atomic mass of element X is approximately 30.54 g/mol.

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