Why is it essential to use balanced chemical equations when determining the quantity of a product formed from a given quantity of a reactant?

Short Answer

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Using balanced chemical equations is essential for determining the quantity of a product formed from a given quantity of a reactant because it ensures compliance with the law of conservation of mass, provides the correct proportions of reactants and products, and allows for accurate predictions based on stoichiometry. Balanced chemical equations indicate the ratio in which reactants combine and produce products, enabling us to calculate the required or produced quantity of a substance accurately.

Step by step solution

01

Understanding balanced chemical equations

Balanced chemical equations represent chemical reactions in which the number of atoms of each element in the reactants is equal to the number of atoms of that same element in the products. This is in accordance with the law of conservation of mass, which states that matter cannot be created or destroyed, only transformed.
02

Understanding stoichiometry

Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction. In a balanced chemical equation, the coefficients of the reactants and products represent their respective moles. These coefficients indicate the ratio in which the reactants combine and produce the products, making it possible to determine the quantity of one substance required or produced based on the quantity of another.
03

Importance of balanced chemical equations in determining a product's quantity

Using balanced chemical equations is essential for several reasons: 1. It ensures that the reaction follows the law of conservation of mass. 2. It allows us to determine the correct proportions of reactants and products. 3. It helps to predict the quantities of products formed or reactants required based on the stoichiometric relationships in the equation. If we don't use a balanced chemical equation to determine the quantity of a product formed from a given reactant, our results may not be accurate or reliable, leading to incorrect predictions.
04

Example

Let's consider the following unbalanced chemical reaction between hydrogen gas (H₂) and oxygen gas (O₂) to form water (H₂O): H₂ + O₂ → H₂O Now suppose we want to determine how much water is produced from 4 moles of hydrogen gas. We first need to balance the chemical equation: 2H₂ + O₂ → 2H₂O With the balanced equation, we see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. We can use this information as a conversion factor to calculate the quantity of water formed: Quantity of water formed = (4 moles H₂) x (2 moles H₂O / 2 moles H₂) = 4 moles H₂O Thus, using the balanced chemical equation ensures we get the correct quantity of the product (water in this case) formed from the given reactant (hydrogen gas).

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Most popular questions from this chapter

(a) What is the mass, in grams, of a mole of \({ }^{12} \mathrm{C} ?\) (b) How many carbon atoms are present in a mole of \({ }^{12} \mathrm{C} ?\)

Balance the following equations: (a) $\mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Li}_{3} \mathrm{~N}(s)$ (b) $\mathrm{TiCl}_{4}(l)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{TiO}_{2}(s)+\mathrm{HCl}(a q)$ (c) $\mathrm{NH}_{4} \mathrm{NO}_{3}(s) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)$ (d) $\mathrm{AlCl}_{3}(s)+\mathrm{Ca}_{3} \mathrm{~N}_{2}(s) \longrightarrow \mathrm{AlN}(s)+\mathrm{CaCl}_{2}(s)$

What parts of balanced chemical equations give information about the relative numbers of moles of reactants and products involved in a reaction?

Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately \(300 \mathrm{mg}\) HCN per kilogram of air when inhaled. (a) Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring \(12 \times 15 \times 8.0 \mathrm{ft}\). The density of air at \(26^{\circ} \mathrm{C}\) is \(0.00118 \mathrm{~g} / \mathrm{cm}^{3}\). (b) If the \(\mathrm{HCN}\) is formed by reaction of \(\mathrm{NaCN}\) with an acid such as \(\mathrm{H}_{2} \mathrm{SO}_{4}\), what mass of \(\mathrm{NaCN}\) gives the lethal dose in the room? \(2 \mathrm{NaCN}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{HCN}(g)\) (c) HCN forms when synthetic fibers containing Orlon \(^{\oplus}\) or Acrilan \(^{\otimes}\) burn. Acrilan \(^{\oplus}\) has an empirical formula of \(\mathrm{CH}_{2} \mathrm{CHCN},\) so \(\mathrm{HCN}\) is \(50.9 \%\) of the formula by mass. \(\mathrm{A}\) rug measures \(12 \times 15 \mathrm{ft}\) and contains 30 oz of Acrilan \(^{\otimes}\) fibers per square yard of carpet. If the rug burns, will a lethal dose of HCN be generated in the room? Assume that the yield of HCN from the fibers is \(20 \%\) and that the carpet is \(50 \%\) consumed.

A chemical plant uses electrical energy to decompose aqueous solutions of \(\mathrm{NaCl}\) to give \(\mathrm{Cl}_{2}, \mathrm{H}_{2}\), and \(\mathrm{NaOH}\) : $$ \begin{aligned} \mathrm{NaCl}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow & \\ & 2 \mathrm{NaOH}(a q)+\mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) \end{aligned} $$ If the plant produces \(1.5 \times 10^{6} \mathrm{~kg}(1500\) metric tons \()\) of \(\mathrm{Cl}_{2}\) daily, estimate the quantities of \(\mathrm{H}_{2}\) and \(\mathrm{NaOH}\) produced.

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