Write the balanced chemical equations for (a) the complete combustion of acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\), the main active ingredient in vinegar; \((\mathbf{b})\) the decomposition of solid calcium hydroxide into solid calcium(II) oxide (lime) and water vapor; (c) the combination reaction between nickel metal and chlorine gas.

Short Answer

Expert verified
a. \( \text{CH}_{3}\text{COOH} + 2\,\text{O}_{2} \rightarrow 2\,\text{CO}_{2} + 2\,\text{H}_{2}\text{O} \) b. \( \text{Ca}(\text{OH})_{2} \rightarrow \text{CaO} + \text{H}_{2}\text{O} \) c. \( \text{Ni} + 2\,\text{Cl}_{2} \rightarrow \text{NiCl}_{2} \)

Step by step solution

01

(a) Combustion of acetic acid

For a complete combustion reaction, the reactants are the given compound and oxygen gas. The products are generally carbon dioxide and water. The chemical equation for the combustion of acetic acid is: \[ \text{CH}_{3}\text{COOH} + \text{O}_{2} \rightarrow \text{CO}_{2} + \text{H}_{2}\text{O} \] Now, balance the equation: \[ \text{CH}_{3}\text{COOH} + 2\,\text{O}_{2} \rightarrow 2\,\text{CO}_{2} + 2\,\text{H}_{2}\text{O} \]
02

(b) Decomposition of calcium hydroxide

For a decomposition reaction, a compound breaks down into simpler compounds or elements. In this case, calcium hydroxide decomposes into calcium(II) oxide and water vapor. Write the chemical equation for this reaction as: \[ \text{Ca}(\text{OH})_{2} \rightarrow \text{CaO} + \text{H}_{2}\text{O} \] The given equation is already balanced.
03

(c) Nickel and chlorine reaction

The combination reaction between nickel metal and chlorine gas results in a compound consisting of nickel and chlorine. The specific compound formed in this case is nickel(II) chloride. The chemical equation for this reaction is: \[ \text{Ni} + \text{Cl}_{2} \rightarrow \text{NiCl}_{2} \] Now, balance the equation: \[ \text{Ni} + 2\,\text{Cl}_{2} \rightarrow \text{NiCl}_{2} \] In summary, the balanced chemical equations for the given reactions are: a. \( \text{CH}_{3}\text{COOH} + 2\,\text{O}_{2} \rightarrow 2\,\text{CO}_{2} + 2\,\text{H}_{2}\text{O} \) b. \( \text{Ca}(\text{OH})_{2} \rightarrow \text{CaO} + \text{H}_{2}\text{O} \) c. \( \text{Ni} + 2\,\text{Cl}_{2} \rightarrow \text{NiCl}_{2} \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combustion Reaction
Chemical reactions are essential to understanding the world around us, and one of the most fundamental types is the combustion reaction. In its essence, a combustion reaction involves a substance (typically a hydrocarbon) reacting with oxygen to release heat and form new products.
A classic example, as given in the exercise, is the combustion of acetic acid \(\text{CH}_3\text{COOH}\). Here, the acetic acid reacts with oxygen, resulting in carbon dioxide \(\text{CO}_2\) and water \(\text{H}_2\text{O}\). To ensure the reaction accurately represents the law of conservation of mass, a balancing step is crucial, where coefficients are added before reactants and products to balance the number of atoms of each element on both sides of the equation.

Real-World Applications

Combustion reactions are not just academic exercises; they occur in everyday life. For example, burning fossil fuels for energy, operating vehicles, and even cooking on a gas stove all involve combustion reactions. These reactions are also exothermic, which means they release heat, a principle exploited in heaters and internal combustion engines.
Moreover, understanding and correctly balancing combustion reactions is critical for fields such as environmental science, where the focus might be on reducing harmful emissions resulting from these reactions.
Decomposition Reaction
While combustion reactions are marked by the formation of new substances through the combination of reactants, decomposition reactions take the opposite route. They involve the breakdown of a compound into simpler substances or elements. Specifically, it's an important type of chemical reaction where a single compound separates to form two or more simpler substances.
The exercise provided offers the decomposition of calcium hydroxide \(\text{Ca}(\text{OH})_2\) into calcium(II) oxide \(\text{CaO}\) and water vapor \(\text{H}_2\text{O}\) as an example. Notably, the original compound, calcium hydroxide, contains chemical bonds that are broken in this process, thereby creating simpler compounds.

Importance in Various Fields

Decomposition reactions are a cornerstone of understanding chemical processes like the digestion of food in our bodies, the decomposition of organic matter in composting, and even the breakdown of rocks and minerals in geology. In industry, these reactions are pivotal in the production of lime for construction materials and the processing of metals. In environmental contexts, decomposition plays a role in the lifecycle of substances and their eventual return to simpler forms in nature.
Combination Reaction
Opposite to decomposition reactions, combination reactions involve two or more substances coming together to form a single product. These reactions are fundamental to both the formation of compounds and an array of synthesis processes across chemistry.
In the exercise given, nickel metal \(\text{Ni}\) reacts with chlorine gas \(\text{Cl}_2\) to form nickel(II) chloride \(\text{NiCl}_2\). This reaction showcases how elements can combine to form a more complex compound. Similar to other types of reactions, it is paramount to balance the equation to comply with the law of conservation of mass. This is done by adjusting coefficients to equalize the number of atoms participating in the reaction from reactants to products.

Significance in Technology and Industry

Combination reactions have wide-ranging applications, such as in manufacturing processes where new materials are synthesized. They also occur in the human body, where elements like calcium and phosphate combine to form bone. In the production of alloys and compounds crucial for electronics and other advanced technologies, understanding these reactions is essential. Consciously managing these reactions allows scientists to develop new materials and technologies, underlining the importance of combination reactions in innovation and progress.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write balanced chemical equations to correspond to each of the following descriptions: (a) When sulfur trioxide gas reacts with water, a solution of sulfuric acid forms. (b) Boron sulfide, \(\mathrm{B}_{2} \mathrm{~S}_{3}(s),\) reacts violently with water to form dissolved boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3},\) and hydrogen sulfide gas. (c) Phosphine, \(\mathrm{PH}_{3}(g)\), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen. (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.

Determine the empirical formulas of the compounds with the following compositions by mass: (a) \(55.3 \% \mathrm{~K}, 14.6 \% \mathrm{P}\), and \(30.1 \% \mathrm{O}\) (b) \(24.5 \% \mathrm{Na}, 14.9 \% \mathrm{Si},\) and \(60.6 \% \mathrm{~F}\) (c) \(62.1 \% \mathrm{C}, 5.21 \% \mathrm{H}, 12.1 \% \mathrm{~N},\) and the remainder \(\mathrm{O}\)

Copper is an excellent electrical conductor widely used in making electric circuits. In producing a printed circuit board for the electronics industry, a layer of copper is laminated on a plastic board. A circuit pattern is then printed on the board using a chemically resistant polymer. The board is then exposed to a chemical bath that reacts with the exposed copper, leaving the desired copper circuit, which has been protected by the overlaying polymer. Finally, a solvent removes the polymer. One reaction used to remove the exposed copper from the circuit board is $$ \begin{aligned} \mathrm{Cu}(s)+\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q) & \longrightarrow \\ & 2 \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}(a q) \end{aligned} $$ A plant needs to produce 5000 circuit boards, each with a surface area measuring 2.0 in. \(\times 3.0\) in. The boards are covered with a \(0.65-\mathrm{mm}\) layer of copper. In subsequent processing, \(85 \%\) of the copper is removed. Copper has a density of \(8.96 \mathrm{~g} / \mathrm{cm}^{3} .\) Calculate the masses of \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) needed to produce the circuit boards, assuming that the reaction used gives a \(97 \%\) yield.

(a) What is the mass, in grams, of \(1.223 \mathrm{~mol}\) of iron(III) sulfate? (b) How many moles of ammonium ions are in \(6.955 \mathrm{~g}\) of ammonium carbonate? (c) What is the mass, in grams, of \(1.50 \times 10^{21}\) molecules of aspirin, \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4} ?\) (d) What is the molar mass of diazepam (Valium \(^{\circ}\) ) if 0.05570 mol has a mass of \(15.86 \mathrm{~g}\) ?

A sample of glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\) contains \(1.250 \times 10^{21}\) carbon atoms. (a) How many atoms of hydrogen does it contain? (b) How many molecules of glucose does it contain? (c) How many moles of glucose does it contain? (d) What is the mass of this sample in grams?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free