Write balanced molecular and net ionic equations for the reactions of (a) manganese with dilute sulfuric acid, (b) chromium with hydrobromic acid, (c) tin with hydrochloric acid, (d) aluminum with formic acid, HCOOH.

Short Answer

Expert verified
a) Mn (s) + 2H+ (aq) -> Mn2+ (aq) + H2 (g) b) 2Cr (s) + 6H+ (aq) -> 2Cr3+ (aq) + 3H2 (g) c) Sn (s) + 2H+ (aq) -> Sn2+ (aq) + H2 (g) d) 2Al (s) + 6H+ (aq) -> 2Al3+ (aq) + 3H2 (g)

Step by step solution

01

Identify the reactants and their oxidation states

For each reaction, we need to identify the reactants and their possible oxidation states. They are as follows: a) Manganese (Mn): +2 b) Chromium (Cr): +3 c) Tin (Sn): +2 d) Aluminum (Al): +3
02

Write the balanced molecular equations

Now, let's write the balanced molecular equations for each reaction: a) Manganese with sulfuric acid Mn (s) + H2SO4 (aq) -> MnSO4 (aq) + H2 (g) b) Chromium with hydrobromic acid 2Cr (s) + 6HBr (aq) -> 2CrBr3 (aq) + 3H2 (g) c) Tin with hydrochloric acid Sn (s) + 2HCl (aq) -> SnCl2 (aq) + H2 (g) d) Aluminum with formic acid 2Al (s) + 6HCOOH (aq) -> 2Al(HCOO)3 (aq) + 3H2 (g)
03

Write the balanced net ionic equations

Now, we'll eliminate spectator ions from each balanced equation and write the net ionic equations: a) Manganese with sulfuric acid Mn (s) + 2H+ (aq) + SO42- (aq) -> Mn2+ (aq) + SO42- (aq) + H2 (g) Net ionic equation: Mn (s) + 2H+ (aq) -> Mn2+ (aq) + H2 (g) b) Chromium with hydrobromic acid 2Cr (s) + 6H+ (aq) + 6Br- (aq) -> 2Cr3+ (aq) + 6Br- (aq) + 3H2 (g) Net ionic equation: 2Cr (s) + 6H+ (aq) -> 2Cr3+ (aq) + 3H2 (g) c) Tin with hydrochloric acid Sn (s) + 2H+ (aq) + 2Cl- (aq) -> Sn2+ (aq) + 2Cl- (aq) + H2 (g) Net ionic equation: Sn (s) + 2H+ (aq) -> Sn2+ (aq) + H2 (g) d) Aluminum with formic acid 2Al (s) + 6HCOO- (aq) + 6H+ (aq) -> 2Al3+ (aq) + 6HCOO- (aq) + 3H2 (g) Net ionic equation: 2Al (s) + 6H+ (aq) -> 2Al3+ (aq) + 3H2 (g)

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