Using the activity series (Table 4.5 ), write balanced chemical equations for the following reactions. If no reaction occurs, simply write NR. (a) Iron metal is added to a solution of copper(II) nitrate; (b) zinc metal is added to a solution of magnesium sulfate; (c) hydrobromic acid is added to tin metal; (d) hydrogen gas is bubbled through an aqueous solution of nickel(II) chloride; (e) aluminum metal is added to a solution of cobalt(II) sulfate.

Short Answer

Expert verified
(a) Fe(s) + Cu(NO₃)₂(aq) -> Fe(NO₃)₂(aq) + Cu(s) (b) NR (no reaction) (c) NR (no reaction) (d) H₂(g) + 2NiCl₂(aq) -> 2HCl(aq) + 2Ni(s) (e) 2Al(s) + 3CoSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Co(s)

Step by step solution

01

Refer to the activity series

To solve this problem, we will first need to refer to the activity series for metals. The series is given in Table 4.5, but for convenience, here is a list of the metals relevant to this exercise, in decreasing order of reactivity: Aluminum (Al) > Zinc (Zn) > Iron (Fe) > Cobalt (Co) > Nickel (Ni) > Copper (Cu)
02

Determine if a reaction will occur

For each pair of substances given, we have to determine if a reaction occurs. A reaction will occur if the metal in its elemental form is more reactive than the metal cation in the compound. After determining if a reaction will occur or not, we can write balanced chemical equations for the reactions. (a) Iron (Fe) with Copper(II) Nitrate (Cu(NO₃)₂): Iron is more reactive than copper, so a reaction will occur between iron and copper(II) nitrate. (b) Zinc (Zn) with Magnesium Sulfate (MgSO₄): Zinc is less reactive than magnesium, so no reaction will occur between zinc and magnesium sulfate. We will write NR for this case. (c) Hydrobromic Acid (HBr) with Tin (Sn): Comparing tin with hydrogen in the series, tin is less reactive than hydrogen, so no reaction will occur between hydrobromic acid and tin metal. We will write NR for this case. (d) Hydrogen gas (H₂) with Nickel(II) Chloride (NiCl₂): Hydrogen is more reactive than nickel, so a reaction will occur between hydrogen gas and nickel(II) chloride. (e) Aluminum (Al) with Cobalt(II) Sulfate (CoSO₄): Aluminum is more reactive than cobalt, so a reaction will occur between aluminum and cobalt(II) sulfate.
03

Write balanced chemical equations for the reactions

Now, we write balanced chemical equations for the reactions determined in step 2. (a) Iron (Fe) with Copper(II) Nitrate (Cu(NO₃)₂): Fe(s) + Cu(NO₃)₂(aq) -> Fe(NO₃)₂(aq) + Cu(s) (b) Zinc (Zn) with Magnesium Sulfate (MgSO₄): NR (no reaction) (c) Hydrobromic Acid (HBr) with Tin (Sn): NR (no reaction) (d) Hydrogen gas (H₂) with Nickel(II) Chloride (NiCl₂): H₂(g) + 2NiCl₂(aq) -> 2HCl(aq) + 2Ni(s) (e) Aluminum (Al) with Cobalt(II) Sulfate (CoSO₄): 2Al(s) + 3CoSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Co(s)

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Most popular questions from this chapter

Explain how a redox reaction involves electrons in the same way that a neutralization reaction involves protons. [Sections 4.3 and 4.4\(]\)

(a) You have a stock solution of \(14.8 \mathrm{M} \mathrm{NH}_{3}\). How many milliliters of this solution should you dilute to make \(1000.0 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{NH}_{3} ?\) (b) If you take a \(10.0-\mathrm{mL}\) portion of the stock solution and dilute it to a total volume of \(0.500 \mathrm{~L},\) what will be the concentration of the final solution?

(a) Calculate the molarity of a solution that contains \(0.175 \mathrm{~mol}\) \(\mathrm{ZnCl}_{2}\) in exactly \(150 \mathrm{~mL}\) of solution. (b) How many moles of \(\mathrm{HCl}\) are present in \(35.0 \mathrm{~mL}\) of a \(4.50 \mathrm{M}\) solution of nitric acid? (c) How many milliliters of \(6.00 \mathrm{M} \mathrm{NaOH}\) solution are needed to provide \(0.325 \mathrm{~mol}\) of \(\mathrm{NaOH} ?\)

(a) What volume of \(0.115 \mathrm{M} \mathrm{HClO}_{4}\) solution is needed to neutralize \(50.00 \mathrm{~mL}\) of \(0.0875 \mathrm{M} \mathrm{NaOH}\) ? (b) What volume of \(0.128 \mathrm{M} \mathrm{HCl}\) is needed to neutralize \(2.87 \mathrm{~g}\) of \(\mathrm{Mg}(\mathrm{OH})_{2} ?\) (c) If \(25.8 \mathrm{~mL}\) of \(\mathrm{AgNO}_{3}\) is needed to precipitate all the \(\mathrm{Cl}^{-}\) ions in a \(785-\mathrm{mg}\) sample of \(\mathrm{KCl}\) (forming \(\mathrm{AgCl}\) ), what is the molarity of the \(\mathrm{AgNO}_{3}\) solution? (d) If \(45.3 \mathrm{~mL}\) of \(0.108 \mathrm{M} \mathrm{HCl}\) solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution?

Calculate (a) the number of grams of solute in \(0.250 \mathrm{~L}\) of \(0.175 \mathrm{M} \mathrm{KBr},\) (b) the molar concentration of a solution containing \(14.75 \mathrm{~g}\) of \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) in \(1.375 \mathrm{~L},\) (c) the volume of \(1.50 \mathrm{M} \mathrm{Na}_{3} \mathrm{PO}_{4}\) in milliliters that contains \(2.50 \mathrm{~g}\) of solute.

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