An \(8.65-g\) sample of an unknown group 2 A metal hydroxide is dissolved in \(85.0 \mathrm{~mL}\) of water. An acid-base indicator is added and the resulting solution is titrated with \(2.50 \mathrm{M} \mathrm{HCl}(a q)\) solution. The indicator changes color signaling that the equivalence point has been reached after \(56.9 \mathrm{~mL}\) of the hydrochloric acid solution has been added. (a) What is the molar mass of the metal hydroxide? (b) What is the identity of the metal cation: \(\mathrm{Ca}^{2+}, \mathrm{Sr}^{2+}, \mathrm{Ba}^{2+} ?\)

Short Answer

Expert verified
The molar mass of the unknown metal hydroxide is calculated as \(121.6 \,\mathrm{g/mol}\), and the metal cation is identified as \(\mathrm{Sr^{2+}}\), indicating that the metal hydroxide is \(\mathrm{Sr(OH)_2}\).

Step by step solution

01

Calculate the moles of \(\mathrm{HCl}\) used in the titration

We have the volume of the \(\mathrm{HCl}\) solution used in titration and its concentration, so we can calculate the number of moles by using the formula: Moles of \(\mathrm{HCl}=\mathrm{Volume\ of\ HCl\ used} \times \mathrm{Concentration\ of\ HCl}\) Moles of \(\mathrm{HCl} = (56.9 \times 10^{-3} \mathrm{L}) \times (2.50 \mathrm{M})\)
02

Calculate the moles of the unknown metal hydroxide

During titration, the \(\mathrm{HCl}\) reacts with the unknown metal hydroxide (\(\mathrm{M(OH)_2}\)), and the balanced chemical equation is: \(\mathrm{M(OH)_2 + 2HCl \rightarrow MCl_2 + 2H_2O}\) From the balanced equation, 1 mole of the metal hydroxide reacts with 2 moles of \(\mathrm{HCl}\). Applying the stoichiometry principles, we can calculate the moles of the metal hydroxide as follows: Moles of \(\mathrm{M(OH)_2} = \mathrm{\dfrac{moles\ of\ HCl}{2}}\)
03

Determine the molar mass of the metal hydroxide

We have the mass and moles of the metal hydroxide: Mass = \(8.65\,\mathrm{g}\) Moles = Moles of \(\mathrm{M(OH)_2}\) (calculated in Step 2) Molar mass of \(\mathrm{M(OH)_2} = \mathrm{\dfrac{mass}{moles}}\)
04

Identify the metal cation

Based on the molar mass of the metal hydroxide obtained in Step 3, we can compare it with the molar masses of the group 2A metal hydroxides and identify the metal cation. Group 2A metal hydroxides: - \(\mathrm{Ca(OH)_2}\): Molar mass = 74.1 g/mol - \(\mathrm{Sr(OH)_2}\): Molar mass = 121.6 g/mol - \(\mathrm{Ba(OH)_2}\): Molar mass = 171.3 g/mol Compare the molar mass obtained in Step 3 with the above values to determine which metal cation is present in the unknown metal hydroxide.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate (a) the number of grams of solute in \(0.250 \mathrm{~L}\) of \(0.175 \mathrm{M} \mathrm{KBr},\) (b) the molar concentration of a solution containing \(14.75 \mathrm{~g}\) of \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) in \(1.375 \mathrm{~L},\) (c) the volume of \(1.50 \mathrm{M} \mathrm{Na}_{3} \mathrm{PO}_{4}\) in milliliters that contains \(2.50 \mathrm{~g}\) of solute.

Gold is one of the few metals that can be obtained by panning, where a simple pan is used to separate gold from other deposits found in or near a stream bed. What two properties of gold make it possible to find gold, but not metals like copper, silver, lead, and aluminum, by panning?

When methanol, \(\mathrm{CH}_{3} \mathrm{OH},\) is dissolved in water, a nonconducting solution results. When acetic acid, \(\mathrm{CH}_{3} \mathrm{COOH},\) dissolves in water, the solution is weakly conducting and acidic in nature. Describe what happens upon dissolution in the two cases, and account for the different results.

What mass of \(\mathrm{NaOH}\) is needed to precipitate the \(\mathrm{Cd}^{2+}\) ions from \(35.0 \mathrm{~mL}\) of \(0.500 \mathrm{M} \mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2}\) solution?

The mass percentage of chloride ion in a \(25.00-\mathrm{mL}\) sample of seawater was determined by titrating the sample with silver nitrate, precipitating silver chloride. It took \(42.58 \mathrm{~mL}\) of \(0.2997 \mathrm{M}\) silver nitrate solution to reach the equivalence point in the titration. What is the mass percentage of chloride ion in the seawater if its density is \(1.025 \mathrm{~g} / \mathrm{mL} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free