(a) Calculate the energies of an electron in the hydrogen atom for \(n=1\) and for \(n=\infty .\) How much energy does it require to move the electron out of the atom completely (from \(n=1\) to \(n=\infty),\) according to Bohr? Put your answer in \(\mathrm{kJ} / \mathrm{mol}\). (b) The energy for the process \(\mathrm{H}+\) energy \(\rightarrow \mathrm{H}^{+}+\mathrm{e}^{-}\) is called the ionization energy of hydrogen. The experimentally determined value for the ionization energy of hydrogen is \(1310 \mathrm{~kJ} / \mathrm{mol}\). How does this compare to your calculation?

Short Answer

Expert verified
The energy levels of an electron in the hydrogen atom for $n=1$ and $n=\infty$ are -13.6 eV and 0 respectively. The energy required to move the electron out of the atom completely (from $n=1$ to $n=\infty$) is 13.6 eV, which is equivalent to 1310 kJ/mol. This calculated ionization energy of hydrogen matches the given experimental value of 1310 kJ/mol.

Step by step solution

01

Understanding Bohr's formula for energy levels

According to Bohr's model, the energy of an electron in the hydrogen atom at a given energy level (n) can be calculated using the formula: \[E_n=-\frac{2\pi^2e^4m_eZ^2}{h^2n^2}\] Where \(E_n\) is the energy of the electron at level n, e is the elementary charge, \(m_e\) is the mass of electron, Z is the atomic number (1 for hydrogen), h is the Planck's constant, and n is the energy level.
02

Calculate the energy for n=1

We will plug in the known values (elementary charge, Planck's constant, electron mass, and atomic number) into the formula and calculate the energy for n=1: \[E_1=-\frac{2\pi^2e^4m_e(1)^2}{h^2(1)^2}\] \[E_1=-13.6 \text{ eV}\]
03

Calculate the energy for n=∞

Now we calculate the energy for n=∞: \[E_{\infty}=-\frac{2\pi^2e^4m_e(1)^2}{h^2(\infty)^2}\] As n approaches infinity, the energy level will be zero: \[E_{\infty}=0\]
04

Calculate the energy difference between n=1 and n=∞

The energy required to ionize the electron completely (from n=1 to n=∞) is the difference between the energies for n=1 and n=∞: \[\Delta E=E_{\infty} - E_1\] \[\Delta E=0 - (-13.6 \text{ eV})\] \[\Delta E=13.6 \text{ eV}\]
05

Convert energy to kJ/mol

To convert the energy difference to kJ/mol, first, multiply by the electron charge to obtain joules: \[\Delta E=13.6 \text{ eV} * 1.6 \times 10^{-19} \text{ J/eV} = 2.176 \times 10^{-18} \text{ J}\] Next, multiply by Avogadro's number to convert from energy per atom to energy per mol: \[\Delta E=2.176 \times 10^{-18} \text{ J/atom} * 6.022 \times 10^{23} \text{ atoms/mol}=1310 \text{ kJ/mol}\]
06

Compare calculated value with experimental value

According to our calculation, the ionization energy of hydrogen is 1310 kJ/mol, which is the same as the experimental value (1310 kJ/mol) given in the exercise. Therefore, our calculated value of the ionization energy of hydrogen is consistent with the experimental data.

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