What is the maximum number of electrons that can occupy each of the following subshells: (a) \(3 p,\) (b) \(5 d,\) (c) \(2 s\), ( (d) \(4 f ?\)

Short Answer

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The maximum number of electrons that can occupy each of the given subshells are: (a) 3p subshell: \(6\), (b) 5d subshell: \(10\), (c) 2s subshell: \(2\), and (d) 4f subshell: \(14\).

Step by step solution

01

Identify the quantum numbers

For a 3p subshell, the principle quantum number (n) is 3 and the angular momentum quantum number (l) is 1 (since p corresponds to l=1).
02

Calculate the maximum number of electrons

Using the formula 2(2l+1), we can calculate the number of electrons in the 3p subshell: \(2(2(1)+1)=2(3)=6\) Ultimately, the 3p subshell can hold a maximum of 6 electrons. #b) 5d Subshell Maximum Electrons#
03

Identify the quantum numbers

For a 5d subshell, the principle quantum number (n) is 5 and the angular momentum quantum number (l) is 2 (since d corresponds to l=2).
04

Calculate the maximum number of electrons

Using the formula 2(2l+1), we can calculate the number of electrons in the 5d subshell: \(2(2(2)+1)=2(5)=10\) Ultimately, the 5d subshell can hold a maximum of 10 electrons. #c) 2s Subshell Maximum Electrons#
05

Identify the quantum numbers

For a 2s subshell, the principle quantum number (n) is 2 and the angular momentum quantum number (l) is 0 (since s corresponds to l=0).
06

Calculate the maximum number of electrons

Using the formula 2(2l+1), we can calculate the number of electrons in the 2s subshell: \(2(2(0)+1)=2(1)=2\) Ultimately, the 2s subshell can hold a maximum of 2 electrons. #d) 4f Subshell Maximum Electrons#
07

Identify the quantum numbers

For a 4f subshell, the principle quantum number (n) is 4 and the angular momentum quantum number (l) is 3 (since f corresponds to l=3).
08

Calculate the maximum number of electrons

Using the formula 2(2l+1), we can calculate the number of electrons in the 4f subshell: \(2(2(3)+1)=2(7)=14\) Ultimately, the 4f subshell can hold a maximum of 14 electrons.

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