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Chapter 6: Problem 69

Write the condensed electron configurations for the following atoms, using the appropriate noble-gas core abbreviations: (a) \(\mathrm{Cs},(\mathbf{b}) \mathrm{Ni},(\mathrm{c}) \mathrm{Se}\) (d) Cd, (e) \(\mathrm{U},(\mathbf{f}) \mathrm{Pb}\).

Short Answer

Expert verified
The condensed electron configurations using noble-gas core abbreviations for the given atoms are as follows: a) Cs: [\(Xe\)]6s¹ b) Ni: [\(Ar\)]4s²3d⁸ c) Se: [\(Ar\)]4s²3d¹⁰4p⁴ d) Cd: [\(Kr\)]5s²4d¹⁰ e) U: [\(Rn\)]7s²5f³ f) Pb: [\(Xe\)]6s²4f¹⁴5d¹⁰6p²

Step by step solution

01

Identify the nearest noble gas with fewer electrons

For each element, find the noble gas with fewer electrons and atomic number closest to the given atom. Write down their element symbols and atomic numbers for reference. a) Cs (Cesium): Xe, 54 b) Ni (Nickel): Ar, 18 c) Se (Selenium): Ar, 18 d) Cd (Cadmium): Kr, 36 e) U (Uranium): Rn, 86 f) Pb (Lead): Xe, 54
02

Write the electron configuration from the noble gas core to the atom

Write the electron configuration from the atomic number of the noble gas core to the atomic number of the given atom. Use the periodic table to aid you in identifying the orbitals being filled. a) Cs: \(Xe\) -> 6s¹ b) Ni: \(Ar\) -> 4s²3d⁸ c) Se: \(Ar\) -> 4s²3d¹⁰4p⁴ d) Cd: \(Kr\) -> 5s²4d¹⁰ e) U: \(Rn\) -> 7s²5f³ f) Pb: \(Xe\) -> 6s²4f¹⁴5d¹⁰6p²
03

Combine the noble gas core abbreviation with the electron configurations

Replace the noble gas symbols with their electron configuration abbreviations in brackets and combine them with the electron configurations found in Step 2. a) Cs: [\(Xe\)]6s¹ b) Ni: [\(Ar\)]4s²3d⁸ c) Se: [\(Ar\)]4s²3d¹⁰4p⁴ d) Cd: [\(Kr\)]5s²4d¹⁰ e) U: [\(Rn\)]7s²5f³ f) Pb: [\(Xe\)]6s²4f¹⁴5d¹⁰6p²

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Most popular questions from this chapter

A stellar object is emitting radiation at \(3.55 \mathrm{~mm}\). (a) What type of electromagnetic spectrum is this radiation? (b) If a detector is capturing \(3.2 \times 10^{8}\) photons per second at this wavelength, what is the total energy of the photons detected in one hour?

A photocell is a device used to measure the intensity of light. In a certain experiment, when light of wavelength \(630 \mathrm{nm}\) is directed onto the photocell, electrons are emitted at the rate of \(2.6 \times 10^{-12} \mathrm{C} / \mathrm{s}\) (coulombs per second). Assume that each photon that impinges on the photocell emits one electron. How many photons per second are striking the photocell? How much energy per second is the photocell absorbing?

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