Moseley established the concept of atomic number by studying X-rays emitted by the elements. The X-rays emitted by some of the elements have the following wavelengths: $$ \begin{array}{ll} \hline \text { Element } & \text { Wavelength }(\AA) \\\ \hline \mathrm{Ne} & 14.610 \\ \mathrm{Ca} & 3.358 \\ \mathrm{Zn} & 1.435 \\\ \mathrm{Zr} & 0.786 \\ \mathrm{Sn} & 0.491 \\ \hline \end{array} $$

Short Answer

Expert verified
The relationship between the X-ray wavelengths and atomic numbers for the given elements can be represented by the equation: \( A = \frac{k}{Z^2} \), where A is the X-ray wavelength, Z is the atomic number, and k is an approximately constant value.

Step by step solution

01

Write down the given information with the elements' atomic numbers

We have the following information about the elements and their emitted X-ray wavelengths: Element | Atomic Number (Z) | Wavelength (A) (in Å) --- | --- | --- Ne | 10 | 14.610 Ca | 20 | 3.358 Zn | 30 | 1.435 Zr | 40 | 0.786 Sn | 50 | 0.491
02

Study the relationship between the atomic number (Z) and the X-ray wavelengths

To find a pattern between the atomic numbers and the X-ray wavelengths, we can try plotting the wavelength (A) versus atomic number (Z) in a graph and look for a mathematical relationship between them. Remember that we are trying to find a relationship that Moseley established while studying these X-rays.
03

Find a mathematical relationship between the atomic number (Z) and the X-ray wavelengths

If we plot the values, it seems that the X-ray wavelength is inversely proportional to the square of the atomic number (Z) for these elements. We can now try to fit the data to some formula and see if we get an equation that relates these quantities. Let's denote the relationship as: \( A = \frac{k}{Z^2} \) Where: - A is the X-ray wavelength - Z is the atomic number - k is a constant
04

Calculate and verify the constant 'k' for each element

Now, we can calculate the constant 'k' for each element using the formula above and see if its value is consistent for all the elements. Element | Atomic Number (Z) | Wavelength (A) | k (Z^2 * A) --- | --- | --- | --- Ne | 10 | 14.610 | 1461 Ca | 20 | 3.358 | 1343 Zn | 30 | 1.435 | 1289 Zr | 40 | 0.786 | 1256 Sn | 50 | 0.491 | 1227 The values of the constant 'k' are very close to each other, suggesting that Moseley was able to establish the concept of atomic number by studying the X-ray wavelengths and finding a connection between them and the atomic numbers. This relationship can be represented as: \( A = \frac{k}{Z^2} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The concept of atomic number, often denoted as 'Z', is fundamental in understanding the properties of elements and their place in the periodic table. It represents the number of protons in an atom's nucleus, which is unique for each element. It directly determines the element's identity and influences its chemical behavior. For example, Neon (Ne) has an atomic number of 10, indicating it has 10 protons in its nucleus.

From the exercise, when examining the atomic numbers of different elements like Calcium (Ca), Zinc (Zn), Zirconium (Zr), and Tin (Sn), we see that these numbers increase stepwise. Moseley used the atomic number as a pivotal part of his law to establish a firm connection between this numerical identifier of elements and the characteristics of the X-rays they emit.
X-ray Wavelengths
The term X-ray wavelengths describes the distance between successive peaks of an X-ray wave. X-rays themselves are a type of electromagnetic radiation, much like visible light, but with a much shorter wavelength. This characteristic enables them to penetrate substances that light cannot. In the provided exercise, we are given the wavelengths of X-rays emitted by various elements, such as Neon (Ne) at 14.610 Angstroms (Å) and Tin (Sn) at 0.491 Å.

Understanding these wavelengths is critical as they are indicative of the energy levels of electrons within atoms and can be used to identify elements, as per the work of Moseley. The analysis of how X-ray wavelengths vary with atomic numbers leads to insights into the atomic structure and the behavior of electrons within the atom.
Atomic Number and X-ray Relationship
Delving into the relationship between atomic number and X-ray wavelengths, Moseley discovered that there was a predictable pattern to the X-rays emitted by atoms when their inner-shell electrons are excited. This relationship turned out to be key to the development of modern atomic theory. As seen in the exercise, when the atomic numbers scale upwards, the corresponding X-ray wavelengths become shorter. This suggests a specific mathematical relationship between these two variables, which Moseley defined and which we often refer to as Moseley's law.

The investigation into this relationship showcased Moseley's ingenuity in linking a physical property (X-ray wavelength) to a fundamental atomic characteristic (atomic number), thereby allowing for the atomic number to be more precisely determined.
Inversely Proportional Relationship
In an inversely proportional relationship, as one variable increases, the other decreases at a rate that keeps their product constant. Moseley's law hinges on this kind of relationship between the atomic number and the X-ray wavelengths. Our exercise illustrates this through the equation
\[ A = \frac{k}{Z^2} \]
which implies that the wavelength 'A' is inversely proportional to the square of the atomic number 'Z'. The process of plotting the provided values and calculating a consistent 'k' across several elements, as presented in the exercise, reinforces this inverse proportionality. As an educational concept, understanding inverse relationships is crucial in physics and other scientific disciplines, as it describes how quantities counterbalance each other. This concept in X-ray spectroscopy also demonstrates how advancing our understanding of elements' properties often requires a deep dive into the mathematical relationships governing their behavior.

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Most popular questions from this chapter

Find three examples of ions in the periodic table that have an electron configuration of \(n d^{8}(n=3,4,5 \ldots) .\)

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity, (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}\). Write out the process corresponding to the first ionization energy of hydride. (e) How does the process you wrote in part (d) compare to the process for the electron affinity of elemental hydrogen?

Some metal oxides, such as \(\mathrm{Sc}_{2} \mathrm{O}_{3},\) do not react with pure water, but they do react when the solution becomes either acidic or basic. Do you expect \(\mathrm{Sc}_{2} \mathrm{O}_{3}\) to react when the solution becomes acidic or when it becomes basic? Write a balanced chemical equation to support your answer.

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Based on their positions in the periodic table, predict which atom of the following pairs will have the smaller first ionization energy: (a) \(\mathrm{Cl}, \mathrm{Ar} ;\) (b) \(\mathrm{Be}, \mathrm{Ca}\) (c) \(\mathrm{K}\), Co; (d) \(\mathrm{S}, \mathrm{Ge} ;\) (e) Sn. Te.

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