How are metallic character and first ionization energy related?

Short Answer

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Metallic character and first ionization energy are inversely related due to underlying factors such as atomic size, shielding effect, and effective nuclear charge. As metallic character increases, ionization energy decreases, meaning elements with high metallic character can easily lose electrons, whereas elements with low metallic character have high ionization energies, making it more difficult for them to lose electrons.

Step by step solution

01

Define Metallic Character

Metallic character refers to the degree to which an element behaves like a metal. Metals tend to be ductile, malleable, and shine, and good conductors of electricity and heat. Their ability to lose electrons easily is a key aspect of their metallic character, as this explains many of their physical properties, as well as chemical reactivity.
02

Define First Ionization Energy

First ionization energy is the amount of energy required to remove the outermost valence electron from an isolated neutral atom in its gaseous state, forming a positive ion. Ionization energy is a measure of the strength of an atom's hold on its valence electron. It is dependent on factors such as atomic size, shielding effect, and effective nuclear charge.
03

Periodic Trends in Metallic Character and Ionization Energy

As we move across a period (from left to right), the metallic character of elements decreases, and the ionization energy increases. This is because the number of protons in the nucleus also increases, resulting in a stronger attraction to the electrons and a greater difficulty in their removal. As we move down a group, the metallic character increases and ionization energy decreases due to the increase in atomic size and the shielding effect of inner electrons. This results in an overall weakening of the attraction between the nucleus and the valence electrons.
04

Relationship between Metallic Character and First Ionization Energy

The metallic character and first ionization energy of an element are inversely related. Elements with high metallic character possess low ionization energies, which means they can easily lose their valence electrons. Similarly, elements with low metallic character have high ionization energies, making it more difficult for them to lose electrons to form positively charged ions. The relationship between these properties can be attributed to the influence of atomic size, shielding effect, and effective nuclear charge on both metallic character and ionization energy. In conclusion, metallic character and first ionization energy are inversely related due to the same underlying factors, such as atomic size, shielding effect, and effective nuclear charge, that influence both properties. Elements with high metallic character tend to have low ionization energies, while elements with low metallic character tend to have high ionization energies.

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Most popular questions from this chapter

The electron affinities, in \(\mathrm{kJ} / \mathrm{mol}\), for the group \(1 \mathrm{~B}\) and group \(2 \mathrm{~B}\) metals are $$ \begin{array}{|c|c|} \hline \mathrm{Cu} & \mathrm{Zn} \\ -119 & >0 \\\ \hline \mathrm{Ag} & \mathrm{Cd} \\ -126 & >0 \\ \hline \mathrm{Au} & \mathrm{Hg} \\ -223 & >0 \\ \hline \end{array} $$ (a) Why are the electron affinities of the group \(2 \mathrm{~B}\) elements greater than zero? (b) Why do the electron affinities of the group \(1 \mathrm{~B}\) elements become more negative as we move down the group? [Hint: Examine the trends in the electron affinity of other groups as we proceed down the periodic table. \(]\)

(a) One of the alkali metals reacts with oxygen to form a solid white substance. When this substance is dissolved in water, the solution gives a positive test for hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\). When the solution is tested in a burner flame, a lilac-purple flame is produced. What is the likely identity of the metal? (b) Write a balanced chemical equation for reaction of the white substance with water.

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity, (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}\). Write out the process corresponding to the first ionization energy of hydride. (e) How does the process you wrote in part (d) compare to the process for the electron affinity of elemental hydrogen?

Consider the isoelectronic ions \(\mathrm{F}^{-}\) and \(\mathrm{Na}^{+}\). (a) Which ion is smaller? (b) Using Equation 7.1 and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screening constant, \(S,\) calculate \(Z_{\text {eff }}\) for the \(2 p\) electrons in both ions. (c) Repeat this calculation using Slater's rules to estimate the screening constant, \(S\). (d) For isoelectronic ions, how are effective nuclear charge and ionic radius related?

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

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