An \(\mathrm{AB}_{3}\) molecule is described as having a trigonal-bipyramidal electron-domain geometry. How many nonbonding domains are on atom A? Explain.

Short Answer

Expert verified
In an AB3 molecule with a trigonal-bipyramidal electron-domain geometry, the central atom A has 5 electron domains, 3 of which are bonding domains with surrounding B atoms. Therefore, there are \(2\) nonbonding domains on atom A.

Step by step solution

01

Identify the Electron Domains on Atom A

AB3 molecules have the general composition A central atom surrounded by three B atoms. In a trigonal-bipyramidal electron-domain geometry, there are 5 electron domains surrounding the central atom.
02

Determine the Number of Bonding and Nonbonding Domains

With three surrounding B atoms, we can conclude that atom A forms three bonding domains with these B atoms. Since there are 5 electron domains in a trigonal-bipyramidal geometry, we can calculate the number of nonbonding domains by subtracting the bonding domains from the total domains.
03

Calculate the Number of Nonbonding Domains

We know the total number of electron domains (5) and the number of bonding domains (3). Let's use this information to find the number of nonbonding domains: Nonbonding Domains = Total Domains - Bonding Domains = 5 - 3 = 2
04

Conclusion

In an AB3 molecule with a trigonal-bipyramidal electron-domain geometry, the central atom A has 2 nonbonding domains.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry is the three-dimensional arrangement of atoms within a molecule. It's a crucial concept in chemistry that affects how molecules interact with each other and their chemical properties. The geometry is determined by the number of electron domains surrounding the central atom, which includes both bonding and nonbonding electron pairs. For example, when we consider an \textbf{AB}\(_3\) molecule with a trigonal-bipyramidal geometry, the five electron domains are arranged such that three are in equatorial positions forming a triangle in a single plane and two occupy axial positions, above and below the plane. This arrangement minimizes electron repulsion, following the Valence Shell Electron Pair Repulsion (VSEPR) theory.

Molecules with different numbers of bonding and nonbonding electron pairs will have distinct molecular geometries, such as linear, bent, tetrahedral, trigonal-planar and octahedral, among others. Understanding an atom's molecular geometry helps in predicting the molecule's polarity, reactivity, phase of matter, color, magnetism, biological activity, and many other chemical properties.
Nonbonding Electron Pairs
Nonbonding electron pairs, also known as lone pairs, are pairs of valence electrons that are not shared with another atom and do not participate in bonding. These electron domains exert a greater repulsive force than bonding domains because they are localized closer to the central atom. This repulsion affects the molecular geometry of the atom, often reducing the bond angles between the bonding electron pairs.

Let's use the \textbf{AB}\(_3\) molecule as an example. Given that it has five electron domains and only three bonds with surrounding atoms, we can infer that there are two nonbonding electron pairs associated with the central atom. These nonbonding domains can be envisioned as invisible partners that occupy space and can push the bonding domains closer together, altering the ideal bond angles implied by the basic electron-domain geometry.
Trigonal-Bipyramidal Structure
The trigonal-bipyramidal structure is one of the electron-domain geometries explained by the VSEPR theory. It's characterized by a central atom surrounded by five electron domains. These are arranged such that three form an equatorial triangle around the central atom, and two occupy positions above and below this plane, termed the axial positions.

In this geometry, there's angular distinction due to the different positioning of the electron domains. The equatorial-equtorial bond angles are \textbf{120}\(^\text{o}\) and the equatorial-axial bond angles are \textbf{90}\(^\text{o}\). However, if nonbonding electron pairs are present, they will typically occupy the equatorial positions where they are most effective at minimizing electron repulsion, as these positions allow for greater distance between electron pairs. This configuration leads to a less symmetric molecule and can have significant effects on the molecule's physical and chemical properties.

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Most popular questions from this chapter

(a) If the valence atomic orbitals of an atom are sp hybridized, how many unhybridized \(p\) orbitals remain in the valence shell? How many \(\pi\) bonds can the atom form? (b) Imagine that you could hold two atoms that are bonded together, twist them, and not change the bond length. Would it be easier to twist (rotate) around a single \(\sigma\) bond or around a double \((\sigma\) plus \(\pi)\) bond, or would they be the same? Explain.

The lactic acid molecule, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH},\) gives sour milk its unpleasant, sour taste. (a) Draw the Lewis structure for the molecule, assuming that carbon always forms four bonds in its stable compounds. (b) How many \(\pi\) and how many \(\sigma\) bonds are in the molecule? (c) Which CO bond is shortest in the molecule? (d) What is the hybridization of atomic orbitals around the carbon atom associated with that short bond? (e) What are the approximate bond angles around each carbon atom in the molecule?

(a) What is the probability of finding an electron on the internuclear axis if the electron occupies a \(\pi\) molecular orbital? (b) For a homonuclear diatomic molecule, what similarities and differences are there between the \(\pi_{2 p}\) MO made from the \(2 p_{x}\) atomic orbitals and the \(\pi_{2 p}\) MO made from the \(2 p_{y}\) atomic orbitals? (c) How do the \(\pi_{2 p}^{*}\) MOs formed from the \(2 p_{x}\) and \(2 p_{y}\) atomic orbitals differ from the \(\pi_{2 p}\) MOs in terms of energies and electron distributions?

(a) What does the term diamagnetism mean? (b) How does a diamagnetic substance respond to a magnetic field? (c) Which of the following ions would you expect to be diamagnetic: \(\mathrm{N}_{2}^{2-}, \mathrm{O}_{2}^{2-}, \mathrm{Be}_{2}^{2+}, \mathrm{C}_{2}^{-} ?\)

Describe the bond angles to be found in each of the following molecular structures: (a) planar trigonal, (b) tetrahedral, (c) octahedral, (d) linear.

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