What is the number of significant figures in each of the following measured quantities? (a) \(601 \mathrm{kg},\) (b) 0.054 \(\mathrm{s}\) ,(c) \(6.3050 \mathrm{cm},(\mathbf{d}) 0.0105 \mathrm{L},(\mathbf{e}) 7.0500 \times 10^{-3} \mathrm{m}^{3},(\mathbf{f}) 400 \mathrm{g}\)

Short Answer

Expert verified
(a) 3 significant figures (b) 2 significant figures (c) 5 significant figures (d) 3 significant figures (e) 4 significant figures (f) 1 significant figure

Step by step solution

01

(a) 601 kg

This quantity contains non-zero digits only, so all of them are significant. Hence, there are \(\boxed{3}\) significant figures in 601 kg.
02

(b) 0.054 s

Leading zeroes are not significant, so we will ignore 0 before the decimal point. Now, we have two non-zero digits (5 and 4), both of them are significant. The number of significant figures in 0.054 s is \(\boxed{2}\).
03

(c) 6.3050 cm

This quantity has one non-zero digit before the decimal point and four digits after the decimal point. The trailing zero (the last zero) is considered significant because it's after the decimal point. So, there are \(\boxed{5}\) significant figures in 6.3050 cm.
04

(d) 0.0105 L

In this case, leading zeros (0 before the decimal point and 0 after the decimal point) are not significant. Then, we have three digits, where one zero in between significant digits (1 and 5). So, there are \(\boxed{3}\) significant figures in 0.0105 L.
05

(e) 7.0500 x 10^{-3} m^3

Here we have all non-zero digits (7, 5) and two trailing zeroes after the decimal point (zeros are significant because they are after the decimal point). The digit in the exponent of 10 (-3) doesn't count towards the significant figures. So, there are \(\boxed{4}\) significant figures in 7.0500 x 10^{-3} m^3.
06

(f) 400 g

This quantity contains one non-zero digit (4) and two trailing zeroes. However, since there is no decimal point, the trailing zeroes are not significant. Therefore, there is only \(\boxed{1}\) significant figure in 400 g.

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