A number of salts containing the tetrahedral polyatomic anion, \(\mathrm{BF}_{4}^{-}\) , are ionic liquids, whereas salts containing the somewhat larger tetrahedral ion \(\mathrm{SO}_{4}^{2-}\) do not form ionic liquids. Explain this observation.

Short Answer

Expert verified
Salts containing the tetrahedral polyatomic anion \(\mathrm{BF}_{4}^{-}\) form ionic liquids due to their lower lattice energy compared to salts containing the tetrahedral ion \(\mathrm{SO}_{4}^{2-}\). The smaller size and lower charge of the \(\mathrm{BF}_{4}^{-}\) anion result in lower lattice energy, favoring ionic liquid formation, while the larger size and higher charge of the \(\mathrm{SO}_{4}^{2-}\) anion lead to higher lattice energy, making it more difficult for ionic liquids to form.

Step by step solution

01

Understand Ionic Liquids

Ionic liquids are salts that have melting points lower than 100 °C and consist of ions. Their unique properties such as non-volatility, thermal stability, and solvation ability make them widely used in multiple applications. Ionic liquids are usually formed by bulky cations and large anions with low lattice energies.
02

Analyze \(\mathrm{BF}_{4}^{-}\) Anion

The tetrahedral \(\mathrm{BF}_{4}^{-}\) anion consists of a central boron atom surrounded by four fluorine atoms. The ion has a negative charge, and since fluorine is highly electronegative, the electrons are pulled towards the fluorine atoms. The overall ionic radius of \(\mathrm{BF}_{4}^{-}\) is relatively small.
03

Analyze \(\mathrm{SO}_{4}^{2-}\) Anion

The \(\mathrm{SO}_{4}^{2-}\) anion is another tetrahedral anion made up of a central sulfur atom surrounded by four oxygen atoms. Since sulfur is larger than boron, the ionic radius of \(\mathrm{SO}_{4}^{2-}\) is larger than that of \(\mathrm{BF}_{4}^{-}\). Moreover, it has two negative charges, which makes it more negatively charged than the \(\mathrm{BF}_{4}^{-}\) anion.
04

Effects on the Lattice Energy

Ionic liquids have low lattice energies, which result in their low melting points. Lattice energy depends on the charge and size of ions. In general, the lattice energy increases when the ion charges increase, and it decreases with increasing ion size. Therefore, for ionic liquids to form, ions with low lattice energies are preferentially formed.
05

Explain the Difference in Ionic Liquid Formation

The \(\mathrm{BF}_{4}^{-}\) anion's smaller size and lower charge compared to the \(\mathrm{SO}_{4}^{2-}\) anion make the lattice energy lower in salts containing \(\mathrm{BF}_{4}^{-}\). This lower lattice energy favors the formation of ionic liquids when salts containing \(\mathrm{BF}_{4}^{-}\) ions are formed. On the other hand, the greater size and higher charge of the \(\mathrm{SO}_{4}^{2-}\) anion lead to higher lattice energy in salts containing these ions. The higher lattice energy makes it more difficult for ionic liquids to form when salts containing the \(\mathrm{SO}_{4}^{2-}\) anion are produced. In conclusion, salts containing the tetrahedral polyatomic anion \(\mathrm{BF}_{4}^{-}\) form ionic liquids due to their lower lattice energy compared to salts containing the tetrahedral ion \(\mathrm{SO}_{4}^{2-}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how a cholesteric liquid crystal phase differs from a nematic phase.

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{F}, \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{B}\) ?

Propyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and isopropyl alcohol \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\right],\) whose space- filling models are shown, have boiling points of 97.2 and \(82.5^{\circ} \mathrm{C}\) , respectively. Explain why the boiling point of propyl alcohol is higher, even though both have the molecular formula, \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\) .

Ethylene glycol \(\left(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and pentane \(\left(\mathrm{C}_{5} \mathrm{H}_{12}\right)\) are both liquids at room temperature and room pressure, and have about the same molecular weight. (a) One of these liquids is much more viscous than the other. Which one do you predict is more viscous? (b) One of these liquids has a much lower normal boiling point \(\left(36.1^{\circ} \mathrm{C}\right)\) compared to the other one \(\left(198^{\circ} \mathrm{C}\right) .\) Which liquid has the lower normal boiling point? (c) One of these liquids is the major component in antifreeze in automobile engines. Which liquid would you expect to be used as antifreeze? (d) One of these liquids is used as a "blowing agent" in the manufacture of polystyrene foam because it is so volatile. Which liquid would you expect to be used as a blowing agent?

(a) List the following molecules in order of increasing polar-izability: GeCl_ \(_{4}, \mathrm{CH}_{4}, \mathrm{SiCl}_{4}, \mathrm{SiH}_{4},\) and \(\mathrm{GeBr}_{4}\) . (b) Predict the order of boiling points of the substances in part (a).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free