(a) When you exercise vigorously, you sweat. How does this help your body cool? (b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

Short Answer

Expert verified
Sweating helps cool the body during vigorous exercise by evaporating and absorbing heat from the skin, regulating body temperature. In the flask connected to a vacuum pump, the water boils and freezes due to changing pressure conditions. As the pressure inside the flask decreases, the boiling point of the water lowers, causing it to boil. This endothermic process absorbs heat, and as the temperature decreases, the remaining water freezes under the new pressure conditions.

Step by step solution

01

Understanding the cooling effect of sweating

When you exercise vigorously, your body generates heat, which increases the core temperature. Sweating is a natural process that helps regulate body temperature. When sweat is produced, it's released onto the skin's surface. As the sweat evaporates, it absorbs energy (heat) from the skin, which leads to a cooling effect. To summarize the cooling process of sweating: 1. You exercise, generating heat and increasing core body temperature. 2. To avoid overheating, your body produces sweat. 3. Sweat covers the skin surface and absorbs heat from the skin as it evaporates. 4. The skin cools as heat is absorbed by the evaporating sweat, ultimately helping to control body temperature.
02

Understanding the boiling and freezing of water in a flask connected to a vacuum pump

This interesting phenomenon of water boiling and freezing in a flask connected to a vacuum pump can be explained by changing pressure conditions inside the flask and their impact on the water's boiling and freezing points. 1. When the vacuum pump is turned on, it removes air molecules (and hence pressure) from inside the flask. This lowers the boiling point of the water. 2. Due to the lowered pressure, the boiling point of water becomes lower than the temperature of the water, causing the water to start boiling. 3. As the water boils, it changes from a liquid to a gas, which is an endothermic process (absorbs heat). As the boiling process absorbs heat, the temperature of the remaining water starts to decrease. 4. If the vacuum pump continues to lower the pressure inside the flask, the temperature of the remaining water will eventually reach its freezing point under the new pressure conditions, causing the water to freeze.
03

Summary

In this exercise, we explained two thermodynamic processes: the cooling effect of sweating and the boiling and freezing of water in a flask connected to a vacuum pump. Sweating cools the body by evaporating sweat and absorbing heat from the skin, while water boils and freezes in a flask connected to a vacuum pump due to changes in pressure, ultimately resulting in the lowered boiling point of water and heat absorption during the change from liquid to gas, eventually reaching the freezing point at the new pressure conditions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following affects the vapor pressure of a liquid? (a) Volume of the liquid, (b) surface area, (c) intermolecular attractive forces, (d) temperature, (e) density of the liquid.

Ethyl chloride \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right)\) boils at \(12^{\circ} \mathrm{C}\) . When liquid \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\) under pressure is sprayed on a room-temperature \(\left(25^{\circ} \mathrm{C}\right)\) surface in air, the surface is cooled considerably. (a) What does this observation tell us about the specific heat of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g)\) as compared with that of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(l) ?\) Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate the final temperature of the surface?

As a metal such as lead melts, what happens to (a) the average kinetic energy of the atoms and (b) the average distance between the atoms?

Suppose you have two colorless molecular liquids, one boiling at \(-84^{\circ} \mathrm{C},\) the other at \(34^{\circ} \mathrm{C},\) and both at atmospheric pressure. Which of the following statements is correct? For each statement that is not correct, modify the statement so that it is correct. (a) The higher-boiling liquid has greater total intermolecular forces than the lower- boiling liquid. (b) The lower-boiling liquid must consist of nonpolar molecules. (c) The lower- boiling liquid has a lower molecular weight than the higher-boiling liquid. (d) The two liquids have identical vapor pressures at their normal boiling points. (e) At \(-84^{\circ}\) both liquids have vapor pressures of 760 \(\mathrm{mm} \mathrm{Hg}\) .

Ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) melts at \(-114^{\circ} \mathrm{C}\) and boils at \(78^{\circ} \mathrm{C}\) . The enthalpy of fusion of ethanol is \(5.02 \mathrm{kJ} / \mathrm{mol},\) and its enthalpy of vaporization is 38.56 \(\mathrm{kJ} / \mathrm{mol}\) . The specific heats of solid and liquid ethanol are 0.97 and \(2.3 \mathrm{J} / \mathrm{g}-\mathrm{K},\) respectively. (a) How much heat is required to convert 42.0 \(\mathrm{g}\) of ethanol at \(35^{\circ} \mathrm{C}\) to the vapor phase at \(78^{\circ} \mathrm{C} ?(\mathbf{b})\) How much heat is required to convert the same amount of ethanol at \(-155^{\circ} \mathrm{C}\) to the vapor phase at \(78^{\circ} \mathrm{C} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free