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Chapter 12: Problem 65

The coordination number for \(\mathrm{Mg}^{2+}\) ion is usually six. Assuming this assumption holds, determine the anion coordination number in the following compounds: (a) MgS, (b) \(\mathrm{MgF}_{2},(\mathbf{c}) \mathrm{MgO}\)

Short Answer

Expert verified
The anion coordination numbers for the given compounds are: (a) MgS: 6, (b) MgF\(_2\): 12, and (c) MgO: 6.

Step by step solution

01

Identify the compounds and their formulas

We are given three compounds to find the anion coordination numbers for: (a) MgS (b) MgF\(_2\) (c) MgO
02

Determine the anion coordination number for MgS

The compound MgS has a 1:1 ratio of Mg\(^{2+}\) to S\(^{2-}\) ions. Since we know that the coordination number of Mg\(^{2+}\) is 6, the anion coordination number will also be 6. This means that each Mg\(^{2+}\) ion is surrounded by 6 S\(^{2-}\) ions and vice versa.
03

Determine the anion coordination number for MgF\(_2\)

The compound MgF\(_2\) has a 1:2 ratio of Mg\(^{2+}\) to F\(^-\) ions. Since the Mg\(^{2+}\) ion has a coordination number of 6, and there are two F\(^-\) ions for each Mg\(^{2+}\) ion, the anion coordination number will be 2 x 6 = 12. This means that each Mg\(^{2+}\) ion is surrounded by 12 F\(^-\) ions.
04

Determine the anion coordination number for MgO

The compound MgO has a 1:1 ratio of Mg\(^{2+}\) to O\(^{2-}\) ions. Since the Mg\(^{2+}\) ion has a coordination number of 6, the anion coordination number will also be 6. This means that each Mg\(^{2+}\) ion is surrounded by 6 O\(^{2-}\) ions and vice versa. In summary, the anion coordination numbers for the given compounds are: (a) MgS: Anion coordination number = 6 (b) MgF\(_2\): Anion coordination number = 12 (c) MgO: Anion coordination number = 6

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