GaAs and GaP make solid solutions that have the same crystal structure as the parent materials, with As and Prandomly distributed throughout the crystal. GaP As \(_{1-x}\) exists for any value of \(x .\) If we assume that the band gap varies linearly with composition between \(x=0\) and \(x=1,\) estimate the band gap for GaP \(_{0.5} \mathrm{As}_{0.5}\) . (GaAs and GaP band gaps are 1.43 \(\mathrm{eV}\) and 2.26 \(\mathrm{eV}\) , respectively.) What wavelength of light does this correspond to?

Short Answer

Expert verified
The band gap of GaP\(_{0.5}\)As\(_{0.5}\) can be calculated as: $$ \text{Band Gap}_{\text{GaP}_{0.5}\text{As}_{0.5}} = (1-0.5) \times 1.43\,\text{eV} + 0.5 \times 2.26\,\text{eV} = 1.845\,\text{eV} $$ To find the corresponding wavelength of light, we first convert the energy to Joules: $$ E = 1.845\,\text{eV} \times 1.602\times10^{-19}\,\text{J/eV} = 2.958\times10^{-19}\,\text{J} $$ Now, using the energy-wavelength relationship, we can calculate the wavelength: $$ \lambda = \dfrac{hc}{E} = \dfrac{6.626\times10^{-34}\,\text{J s} \times 3\times10^{8}\,\text{m/s}}{2.958\times10^{-19}\,\text{J}} = 6.714\times10^{-7}\,\text{m} $$ Therefore, the band gap of GaP\(_{0.5}\)As\(_{0.5}\) is approximately 1.845 eV, and the corresponding wavelength of light is approximately \(6.714\times10^{-7}\) m, or 671.4 nm.

Step by step solution

01

Calculate GaP\(_{0.5}\)As\(_{0.5}\) band gap

As it is assumed that the band gap varies linearly with composition between \(x=0\) and \(x=1\), we can use the following equation to calculate the band gap of GaP\(_{0.5}\)As\(_{0.5}\): $$ \text{Band Gap}_{\text{GaP}_{0.5}\text{As}_{0.5}} = (1-x) \times \text{Band Gap}_{\text{GaAs}} + x \times \text{Band Gap}_{\text{GaP}} $$ where \(x=0.5\) since we are considering GaP\(_{0.5}\)As\(_{0.5}\). Replacing the given values of the band gaps for GaAs and GaP: $$ \text{Band Gap}_{\text{GaP}_{0.5}\text{As}_{0.5}} = (1-0.5) \times 1.43\,\text{eV} + 0.5 \times 2.26\,\text{eV} $$ By calculating the above expression, we will obtain the band gap of GaP\(_{0.5}\)As\(_{0.5}\).
02

Find the corresponding wavelength of light

We will now calculate the wavelength of light corresponding to the obtained band gap using the energy-wavelength relationship: $$ E = \dfrac{hc}{\lambda} $$ where \(E\) is the energy (band gap), \(h\) is the Planck constant (\(6.626\times10^{-34}\,\text{J s}\)), \(c\) is the speed of light (\(3\times10^{8}\,\text{m/s}\)), and \(\lambda\) is the wavelength of light. We will rearrange the equation to solve for \(\lambda\): $$ \lambda = \dfrac{hc}{E} $$ First, we need to convert the band gap energy from eV to Joules. The conversion factor is \(1.602\times10^{-19}\,\text{J/eV}\). Now, we can substitute the Planck constant, the speed of light, and the energy (in Joules) into the equation and calculate the corresponding wavelength of light.

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