A dilute aqueous solution of an organic compound soluble in water is formed by dissolving 2.35 g of the compound in water to form 0.250 L of solution. The resulting solution has an osmotic pressure of 0.605 atm at \(25^{\circ} \mathrm{C}\) . Assuming that the organic compound is a nonelectrolyte, what is its molar mass?

Short Answer

Expert verified
The molar mass of the organic compound is approximately 378.71 g/mol.

Step by step solution

01

List the given information

We are given the following information: - Mass of organic compound = 2.35 g - Volume of solution = 0.250 L - Osmotic pressure = 0.605 atm - Temperature = 25°C (298.15 K)
02

Write the osmotic pressure formula

The osmotic pressure (π) can be related to the concentration of the solute (moles of solute per liter of solution) using the formula: \(π = MiRT\) where: - π = osmotic pressure (atm) - M = molarity (moles of solute / L of solution) - i = van't Hoff factor (unitless), which is 1 for a nonelectrolyte - R = ideal gas constant = 0.0821 L atm K⁻¹ mol⁻¹ - T = temperature in Kelvin
03

Calculate the molarity M of the solution

By rearranging the formula from step 2, we can calculate the molarity (M) of the solution: \( M = \frac{π}{iRT} \) Since the compound is a nonelectrolyte, the van't Hoff factor i will be 1. Now, we can plug in the given values: \( M = \frac{0.605 \text{ atm}}{1 \times 0.0821 \frac{\text{L atm}}{\text{K mol}} \times 298.15 \text{ K}} \) M = 0.0248 mol/L
04

Calculate the moles of organic compound in the solution

Now that we know the molarity of the solution, we can calculate the number of moles of organic compound present in the solution using the formula: moles of solute = M × volume of solution moles of solute = 0.0248 mol/L × 0.250 L = 0.0062 mol
05

Calculate the molar mass of the organic compound

Finally, we can determine the molar mass of the organic compound using the formula: molar mass = mass of solute / moles of solute molar mass = 2.35 g / 0.0062 mol = 378.71 g/mol So, the molar mass of the organic compound is approximately 378.71 g/mol.

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