For each of the following gas-phase reactions, write the rate expression in terms of the appearance of each product and disappearance of each reactant: \(\begin{array}{l}{\text { (a) } 2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)} \\ {\text { (b) } 2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g)} \\\ {\text { (c) } 2 \mathrm{NO}(g)+2 \mathrm{H}_{2}(g) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)} \\ {\text { (d) } \mathrm{N}_{2}(g)+2 \mathrm{H}_{2}(g) \longrightarrow \mathrm{N}_{2} \mathrm{H}_{4}(g)}\end{array}\)

Short Answer

Expert verified
\(a)\) Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2O\)) = \(\frac{1}{2}\) × (rate of appearance of \(H_2\)) = (rate of appearance of \(O_2\)) \(b)\) Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(SO_2\)) = - (rate of disappearance of \(O_2\)) = \(\frac{1}{2}\) × (rate of appearance of \(SO_3\)) \(c)\) Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(NO\)) = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2\)) = (rate of appearance of \(N_2\)) = \(\frac{1}{2}\) × (rate of appearance of \(H_2O\)) \(d)\) Rate = - (rate of disappearance of \(N_2\)) = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2\)) = (rate of appearance of \(N_2H_4\))

Step by step solution

01

(a) Reaction and rate expression for H2O -> H2 + O2

Given reaction: \(2 H_2O(g) \longrightarrow 2 H_2(g) + O_2(g)\) Rate expression: Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2O\)) = \(\frac{1}{2}\) × (rate of appearance of \(H_2\)) = (rate of appearance of \(O_2\))
02

(b) Reaction and rate expression for SO2 + O2 -> SO3

Given reaction: \(2 SO_2(g) + O_2(g) \longrightarrow 2 SO_3(g)\) Rate expression: Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(SO_2\)) = - (rate of disappearance of \(O_2\)) = \(\frac{1}{2}\) × (rate of appearance of \(SO_3\))
03

(c) Reaction and rate expression for NO + H2 -> N2 + H2O

Given reaction: \(2 NO(g) + 2 H_2(g) \longrightarrow N_2(g) + 2 H_2O(g)\) Rate expression: Rate = -\(\frac{1}{2}\) × (rate of disappearance of \(NO\)) = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2\)) = (rate of appearance of \(N_2\)) = \(\frac{1}{2}\) × (rate of appearance of \(H_2O\))
04

(d) Reaction and rate expression for N2 + H2 -> N2H4

Given reaction: \(N_2(g) + 2 H_2(g) \longrightarrow N_2H_4(g)\) Rate expression: Rate = - (rate of disappearance of \(N_2\)) = -\(\frac{1}{2}\) × (rate of disappearance of \(H_2\)) = (rate of appearance of \(N_2H_4\))

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{S}\right)\) is a common and troublesome pollutant in industrial wastewaters. One way to remove \(\mathrm{H}_{2} \mathrm{S}\) is to treat the water with chlorine, in which case the following reaction occurs: $$ \mathrm{H}_{2} \mathrm{S}(a q)+\mathrm{Cl}_{2}(a q) \longrightarrow \mathrm{S}(s)+2 \mathrm{H}^{+}(a q)+2 \mathrm{Cl}^{-}(a q)$$ The rate of this reaction is first order in each reactant. The rate constant for the disappearance of \(\mathrm{H}_{2} \mathrm{S}\) at \(28^{\circ} \mathrm{C}\) is \(3.5 \times 10^{-2} \mathrm{M}^{-1} \mathrm{s}^{-1}\) . If at a given time the concentration of \(\mathrm{H}_{2} \mathrm{S}\) is \(2.0 \times 10^{-4} \mathrm{M}\) and that of \(\mathrm{Cl}_{2}\) is \(0.025 \mathrm{M},\) what is the rate of formation of \(\mathrm{Cl}^{-} ?\)

Urea \(\left(\mathrm{NH}_{2} \mathrm{CONH}_{2}\right)\) is the end product in protein metabolism in animals. The decomposition of urea in 0.1 \(\mathrm{M} \mathrm{HCl}\) occurs according to the reaction $$\mathrm{NH}_{2} \mathrm{CONH}_{2}(a q)+\mathrm{H}^{+}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NH}_{4}^{+}(a q)+\mathrm{HCO}_{3}^{-}(a q)$$ The reaction is first order in urea and first order overall. When \(\left[\mathrm{NH}_{2} \mathrm{CONH}_{2}\right]=0.200 M,\) the rate at \(61.05^{\circ} \mathrm{C}\) is \(8.56 \times 10^{-5} \mathrm{M} / \mathrm{s}\) , (a) What is the rate constant, \(k ?\) units of \(s^{-1}\) . (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to 0.100\(?\)

The \(\mathrm{NO}_{x}\) waste stream from automobile exhaust includes species such as \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) . Catalysts that convert these species to \(\mathrm{N}_{2}\) are desirable to reduce air pollution. (a) Draw the Lewis dot and VSEPR structures of NO, NO \(_{2}\) and \(\mathrm{N}_{2} .(\mathbf{b})\) Using a resource such as Table \(8.3,\) look up the energies of the bonds in these molecules. In what region of the electromagnetic spectrum are these energies? (c) Design a spectroscopic experiment to monitor the conversion of \(\mathrm{NO}_{x}\) into \(\mathrm{N}_{2},\) describing what wavelengths of light need to be monitored as a function of time.

(a) In which of the following reactions would you expect the orientation factor to be least important in leading to reaction: \(\mathrm{NO}+\mathrm{O} \longrightarrow \mathrm{NO}_{2}\) or \(\mathrm{H}+\mathrm{Cl} \longrightarrow \mathrm{HCl}\) ? (b) Does the orientation factor depend on temperature?

The activation energy of an uncatalyzed reaction is 95 \(\mathrm{kJ} / \mathrm{mol} .\) The addition of a catalyst lowers the activation energy to 55 \(\mathrm{kJ} / \mathrm{mol}\) . Assuming that the collision factor remains the same, by what factor will the catalyst increase the rate of the reaction at (a) \(25^{\circ} \mathrm{C},\) (b) \(125^{\circ} \mathrm{C} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free