(a) Consider the combustion of ethylene, \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+\) \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) .\) If the concentration of \(\mathrm{C}_{2} \mathrm{H}_{4}\) is decreasing at the rate of \(0.036 \mathrm{M} / \mathrm{s},\) what are the rates of change in the concentrations of \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O} ?(\mathbf{b})\) The rate of decrease in \(\mathrm{N}_{2} \mathrm{H}_{4}\) partial pressure in a closed reaction vessel from the reaction \(\mathrm{N}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) is 74 torr per hour. What are the rates of change of \(\mathrm{NH}_{3}\) partial pressure and total pressure in the vessel?

Short Answer

Expert verified
The rates of change in the concentrations of CO₂ and H₂O are both -0.072 M/s. The rate of change of NH₃ partial pressure is -148 torr/h, and the rate of change of total pressure in the vessel is 0 torr/h.

Step by step solution

01

Write down the given rate of change of C₂H₄

The rate of decrease in the concentration of ethylene (C₂H₄) is given as: \(\frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt} = -0.036 \, \mathrm{M/s}\)
02

Use stoichiometry to find the rates of change of CO₂ and H₂O

From the balanced reaction, we can see the stoichiometric ratios of the reactants and products: 1 mol C₂H₄ : 3 mol O₂ : 2 mol CO₂ : 2 mol H₂O Now, we can find the rates of change in the concentrations of CO₂ and H₂O: \(\frac{d[\mathrm{CO}_{2}]}{dt} = 2 \times \frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt}\) \(\frac{d[\mathrm{H}_{2} \mathrm{O}]}{dt} = 2 \times \frac{d[\mathrm{C}_{2} \mathrm{H}_{4}]}{dt}\)
03

Calculate the rates of change of CO₂ and H₂O

Substitute the given rate of decrease in the concentration of ethylene (C₂H₄) into the equations from step 2: \(\frac{d[\mathrm{CO}_{2}]}{dt} = 2 \times (-0.036 \, \mathrm{M/s}) = -0.072 \, \mathrm{M/s}\) \(\frac{d[\mathrm{H}_{2} \mathrm{O}]}{dt} = 2 \times (-0.036 \, \mathrm{M/s}) = -0.072 \, \mathrm{M/s}\) So, the rate of change in the concentrations of CO₂ and H₂O are -0.072 M/s. #b) Finding the rates of change of NH₃ partial pressure and total pressure in the vessel#
04

Write down the given rate of decrease of N₂H₄ partial pressure

The rate of decrease in the partial pressure of N₂H₄ is given as: \(\frac{dP_{\mathrm{N}_{2} \mathrm{H}_{4}}}{dt} = -74 \, \mathrm{torr/h}\)
05

Use stoichiometry to find the rate of change of NH₃ partial pressure

From the balanced reaction, we can see the stoichiometric ratios of the reactants and products: 1 mol N₂H₄ : 1 mol H₂ : 2 mol NH₃ Now, we can find the rate of change in the partial pressure of NH₃: \(\frac{dP_{\mathrm{NH}_{3}}}{dt} = 2 \times \frac{dP_{\mathrm{N}_{2} \mathrm{H}_{4}}}{dt}\)
06

Calculate the rate of change of NH₃ partial pressure

Substitute the given rate of decrease in the partial pressure of N₂H₄ into the equation from step 2: \(\frac{dP_{\mathrm{NH}_{3}}}{dt} = 2 \times (-74 \, \mathrm{torr/h}) = -148 \, \mathrm{torr/h}\) So, the rate of change of NH₃ partial pressure is -148 torr/h.
07

Calculate the rate of change of total pressure in the vessel

Since one mole of reactants produces one mole of products, there is no change in the total pressure in the vessel. Therefore, the rate of change of the total pressure in the vessel is: \(\frac{dP_{\mathrm{total}}}{dt} = 0 \, \mathrm{torr/h}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Stoichiometry
Understanding reaction stoichiometry is pivotal for analyzing most chemical reactions, including the calculation of reaction rates. Stoichiometry involves the quantitative relationship between the amounts of reactants and products in a chemical reaction. It's anchored in the balanced chemical equation which provides the mole ratios of the substances involved.

Consider the combustion of ethylene given in the exercise. The balanced equation, \(\mathrm{C}_{2}\mathrm{H}_{4}(g)+3\mathrm{O}_{2}(g) \longrightarrow 2\mathrm{CO}_{2}(g)+2\mathrm{ H}_{2}\mathrm{O}(g)\),indicates that 1 mole of ethylene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water. These ratios are used to determine how changes in the concentration of one species will affect the concentration of others. For example, if the concentration of ethylene decreases, the concentrations of carbon dioxide and water will increase, which can be expressed with specific rate relationships based on stoichiometry.
Ethylene Combustion
Ethylene combustion is a chemical reaction where ethylene (\(\mathrm{C}_{2}\mathrm{H}_{4}\)) reacts with oxygen (\(\mathrm{O}_{2}\)) to form carbon dioxide (\(\mathrm{CO}_{2}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)). This process is an example of a combustion reaction, a type of exothermic reaction that releases energy, mainly in the form of heat and sometimes light.

In such reactions, it's crucial to monitor the rate at which the reactants are consumed and the products are formed, which not only affects the energy release but also the control of the reaction process. The reaction rate can be manipulated by various factors such as concentration, temperature, and presence of a catalyst. For instance, as the exercise states, the rate at which the concentration of ethylene decreases is -0.036 M/s, which can be used to calculate the rate of formation of the products using the stoichiometry of the balanced equation.
Rate of Reaction
The rate of a reaction refers to the speed at which reactants are converted into products. This rate can be expressed in terms of the change in concentration of a reactant or product over a certain time period. In the exercise, the rate of ethylene concentration decrease is given, and using the stoichiometric coefficients from the balanced equation, the rates of formation for carbon dioxide and water can be deduced.

For a reaction like ethylene combustion, the rate will determine the amount of heat and light energy produced per unit of time, which is essential for safety and efficiency in industrial processes. Understanding the factors that influence the reaction rate, which include the nature of the reactants, surface area, temperature, concentration, and presence of catalysts, is fundamental for controlling and optimizing chemical reactions.
Partial Pressure Changes
In gas-phase reactions, partial pressure is a measure of the pressure contributed by a specific gas in a mixture of gases. Modification in partial pressure reflects changes in gas concentration. When chemical reactions occur in a closed system, like the decomposition of hydrazine (\(\mathrm{N}_{2}\mathrm{H}_{4}\)), as described in the exercise, the rates of partial pressure changes for each gas can be calculated.

The exercise showcases how stoichiometry dictates the change in partial pressure of ammonia (\(\mathrm{NH}_{3}\)) based on the change in partial pressure of hydrazine. Due to the stoichiometric relationship, a 74 torr/h decrease in hydrazine results in a 148 torr/h increase of ammonia. Nonetheless, since the reaction does not result in a net change in the amount of gas (molecules are neither created nor destroyed, only rearranged), the total pressure in the vessel remains unchanged, demonstrating another essential aspect of chemical reactions: conservation of mass in a closed system.

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Most popular questions from this chapter

The reaction between ethyl iodide and hydroxide ion in ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) solution, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{I}^{-}(a l c),\) has an activation energy of 86.8 \(\mathrm{kJ} / \mathrm{mol}\) and a frequency factor of \(2.10 \times 10^{11} \mathrm{M}^{-1} \mathrm{s}^{-1}\) (a) Predict the rate constant for the reaction at \(35^{\circ} \mathrm{C} .\) (b) A g \(\mathrm{KOH}\) in ethanol to form 250.0 \(\mathrm{mL}\) of solution. Similarly, 1.453 \(\mathrm{g}\) of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\) is dissolved in ethanol to form 250.0 \(\mathrm{mL}\) of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reac-solution of \(\mathrm{KOH}\) in ethanol is made up by dissolving 0.335 g KOH in ethanol to form 250.0 \(\mathrm{mL}\) of solution. Similarly, 1.453 \(\mathrm{g}\) of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\) is dissolved in ethanol to form 250.0 \(\mathrm{mL}\) of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reactant, what is the initial rate at \(35^{\circ} \mathrm{C} ?(\mathbf{c})\) Which reagent in the reaction is limiting, assuming the reaction proceeds to completion? Assuming the frequency factor and activation energy do not change as a function of temperature, calculate the rate constant for the reaction at \(50^{\circ} \mathrm{C}\) .

(a) What are the units usually used to express the rates of reactions occurring in solution? (b) As the temperature increases, does the reaction rate increase or decrease? (c) As a reaction proceeds, does the instantaneous reaction rate increase or decrease?

As described in Exercise 14.41 , the decomposition of sulfuryl chloride \(\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)\) is a first-order process. The rate constant for the decomposition at 660 \(\mathrm{K}\) is \(4.5 \times 10^{-2} \mathrm{s}^{-1}\) .half-life for this reaction? (b) If you start with 0.050\(M \mathrm{I}_{2}\) at this temperature, how much will remain after 5.12 s assuming that the iodine atoms do not recombine to form \(\mathrm{I}_{2}\) ?

The rate of a first-order reaction is followed by spectroscopy, monitoring the absorbance of a colored reactant at \(520 \mathrm{nm}\). The reaction occurs in a \(1.00-\mathrm{cm}\) sample cell, and the only colored species in the reaction has an extinction coefficient of \(5.60 \times 10^{3} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at \(520 \mathrm{nm}\). (a) Calculate the initial concentration of the colored reactant if the absorbance is 0.605 at the beginning of the reaction. (b) The absorbance falls to 0.250 at \(30.0 \mathrm{~min}\). Calculate the rate constant in units of \(\mathrm{s}^{-1}\). (c) Calculate the half-life of the reaction. (d) How long does it take for the absorbance to fall to \(0.100 ?\)

The reaction between ethyl bromide \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)\) and hydroxide ion in ethyl alcohol at 330 \(\mathrm{K}\) , \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{Br}^{-}(a l c)\) is first order each in ethyl bromide and hydroxide ion. When \(\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right]\) is 0.0477 \(\mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]\) is \(0.100 \mathrm{M},\) the rate of disappearance of ethyl bromide is \(1.7 \times 10^{-7} \mathrm{M} / \mathrm{s}\) (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) How would the rate of disappearance of ethyl bromide change if the solution were diluted by adding an equal volume of pure ethyl alcohol to the solution?

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