Write the chemical equation and the \(K_{a}\) expression for the ionization of each of the following acids in aqueous solution. First show the reaction with \(\mathrm{H}^{+}(a q)\) as a product and then with the hydronium ion: (a) \(\mathrm{HBrO}_{2},\) (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COOH} .\)

Short Answer

Expert verified
For HBrO2: 1. Chemical equation with H+ as a product: \(\mathrm{HBrO_{2} \rightleftharpoons H^{+} + BrO^{-}_{2}}\) 2. Chemical equation with H3O+ as a product: \(\mathrm{HBrO_{2} + H_{2}O \rightleftharpoons H_{3}O^{+} + BrO^{-}_{2} }\) 3. Ka expression: \( K_a = \frac{[\mathrm{H^{+}}][\mathrm{BrO^{-}_{2}}]}{[\mathrm{HBrO_{2}}]} \) For C2H5COOH: 1. Chemical equation with H+ as a product: \(\mathrm{C_{2}H_{5}COOH \rightleftharpoons H^{+} + C_{2}H_{5}COO^{-}} \) 2. Chemical equation with H3O+ as a product: \(\mathrm{C_{2}H_{5}COOH + H_{2}O \rightleftharpoons H_{3}O^{+} + C_{2}H_{5}COO^{-}} \) 3. Ka expression: \( K_a = \frac{[\mathrm{H^{+}}][\mathrm{C_{2}H_{5}COO^{-}}]}{[\mathrm{C_{2}H_{5}COOH}]} \)

Step by step solution

01

a. HBrO2 Ionization & Ka expression

1. Write the chemical equation for the ionization of HBrO2 with H+ as a product: \[ \mathrm{HBrO_{2} \rightleftharpoons H^{+} + BrO^{-}_{2}}\] 2. Write the chemical equation for the ionization of HBrO2 with the hydronium ion (H3O+) as a product: \[ \mathrm{HBrO_{2} + H_{2}O \rightleftharpoons H_{3}O^{+} + BrO^{-}_{2} }\] 3. Write the expression for the acid dissociation constant (\(K_a\)) for HBrO2: \[ K_a = \frac{[\mathrm{H^{+}}][\mathrm{BrO^{-}_{2}}]}{[\mathrm{HBrO_{2}}]} \]
02

b. C2H5COOH Ionization & Ka expression

1. Write the chemical equation for the ionization of C2H5COOH with H+ as a product: \[ \mathrm{C_{2}H_{5}COOH \rightleftharpoons H^{+} + C_{2}H_{5}COO^{-}} \] 2. Write the chemical equation for the ionization of C2H5COOH with the hydronium ion (H3O+) as a product: \[ \mathrm{C_{2}H_{5}COOH + H_{2}O \rightleftharpoons H_{3}O^{+} + C_{2}H_{5}COO^{-}} \] 3. Write the expression for the acid dissociation constant (\(K_a\)) for C2H5COOH: \[ K_a = \frac{[\mathrm{H^{+}}][\mathrm{C_{2}H_{5}COO^{-}}]}{[\mathrm{C_{2}H_{5}COOH}]} \]

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Most popular questions from this chapter

(a) Give the conjugate base of the following Bronsted-Lowry acids: (i) \(\mathrm{HIO}_{3},(\mathbf{i} \mathbf{i}) \mathrm{NH}_{4}^{+} .(\mathbf{b})\) Give the conjugate acid of the following Bronsted-Lowry bases: (i) \(\mathrm{O}^{2-},(\mathbf{i} \mathbf{i}) \mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)

Determine whether each of the following is true or false: (a) All strong bases are salts of the hydroxide ion. (b) The addition of a strong base to water produces a solution of \(\mathrm{pH}>\)7.0 .(c) Because \(\mathrm{Mg}(\mathrm{OH})_{2}\) is not very soluble, it cannot be a strong base.

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