Identify the Lewis acid and Lewis base in each of the following reactions: (a) \(\mathrm{HNO}_{2}(a q)+\mathrm{OH}^{-}(a q) \rightleftharpoons \mathrm{NO}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) (b) \(\mathrm{FeBr}_{3}(s)+\mathrm{Br}^{-}(a q) \rightleftharpoons \mathrm{FeBr}_{4}^{-}(a q)\) (c) \(\mathrm{Zn}^{2+}(a q)+4 \mathrm{NH}_{3}(a q) \rightleftharpoons \mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}^{2+}(a q)\) (d) \(\mathrm{SO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}_{3}(a q)\)

Short Answer

Expert verified
In the given reactions: (a) Lewis base: OH⁻; Lewis acid: HNO₂ (b) Lewis base: Br⁻; Lewis acid: FeBr₃ (c) Lewis base: NH₃; Lewis acid: Zn²⁺ (d) Lewis base: H₂O; Lewis acid: SO₂

Step by step solution

01

Reaction (a)

In this reaction, the OH⁻ ion donates a pair of electrons to the hydrogen in HNO₂, forming a bond and creating H₂O. The HNO₂ molecule accepts the electron pair. Thus, OH⁻ is the Lewis base, and HNO₂ is the Lewis acid: Lewis base: OH⁻ Lewis acid: HNO₂
02

Reaction (b)

In this reaction, the Br⁻ ion donates a pair of electrons to the FeBr₃ molecule, creating a bond and forming FeBr₄⁻. The FeBr₃ molecule accepts the electron pair. Thus, Br⁻ is the Lewis base, and FeBr₃ is the Lewis acid: Lewis base: Br⁻ Lewis acid: FeBr₃
03

Reaction (c)

In this reaction, the NH₃ molecules each donate a pair of electrons to the Zn²⁺ ion, creating bonds and forming Zn(NH₃)₄²⁺. The Zn²⁺ ion accepts the electron pairs. Thus, NH₃ is the Lewis base, and Zn²⁺ is the Lewis acid: Lewis base: NH₃ Lewis acid: Zn²⁺
04

Reaction (d)

In this reaction, the H₂O molecule donates a pair of electrons to the sulfur atom in the SO₂ molecule, creating a bond and forming H₂O₃. The SO₂ molecule accepts the electron pair. Thus, H₂O is the Lewis base, and SO₂ is the Lewis acid: Lewis base: H₂O Lewis acid: SO₂

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