(a) What is the primary basis for the division of the atmosphere into different regions? (b) Name the regions of the atmosphere, indicating the altitude interval for each one.

Short Answer

Expert verified
(a) The primary basis for the division of the atmosphere into different regions is the temperature gradient or temperature changes with altitude. (b) The atmosphere is divided into five major regions: 1. Troposphere: from Earth's surface up to approximately 8-14.5 km altitude. 2. Stratosphere: from around 8-14.5 km to approximately 50 km altitude. 3. Mesosphere: from about 50 km to roughly 85 km altitude. 4. Thermosphere: from around 85 km to approximately 600 km altitude. 5. Exosphere: from around 600 km to about 10,000 km altitude.

Step by step solution

01

(a) Primary basis for division of the atmosphere

The primary basis for the division of the atmosphere into different regions is the temperature gradient or temperature changes with altitude. Different layers of the atmosphere exhibit different temperature characteristics, which is the main reason for their categorization.
02

(b) Regions of the atmosphere and their altitude intervals

The atmosphere is divided into five major regions, based on temperature characteristics and altitude: 1. Troposphere: The troposphere is the lowest layer of the atmosphere, extending from the Earth's surface up to an altitude of approximately 8-14.5 km, depending on the location (higher at the equator and lower at the poles). The temperature in this region decreases with increasing altitude. 2. Stratosphere: The stratosphere lies above the troposphere, with its lower boundary starting at around 8-14.5 km, and extending to approximately 50 km. The temperature in this region increases with altitude due to the presence of the ozone layer, which absorbs ultraviolet radiation from the Sun. 3. Mesosphere: The mesosphere is located above the stratosphere, with its base at about 50 km and extending up to roughly 85 km. The temperature in this region decreases with altitude, with the top of the mesosphere being the coldest part of the atmosphere. 4. Thermosphere: The thermosphere starts at around 85 km and extends up to approximately 600 km. This layer experiences a significant increase in temperature with altitude due to the absorption of highly energetic solar radiation by its sparse gas molecules. 5. Exosphere: The exosphere is the outermost region of the atmosphere, starting at around 600 km and extending up to about 10,000 km. This is the transition region between Earth's atmosphere and outer space. The temperature in this region is highly variable, depending primarily on solar activity. Note that the boundaries between these regions are not sharp, and there are transition zones called "pauses" between these layers.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The wavelength at which the \(\mathrm{O}_{2}\) molecule most strongly absorbs light is approximately 145 \(\mathrm{nm}\) . (a) In which region of the electromagnetic spectrum does this light fall? (b) Would a photon whose wavelength is 145 nm have enough energy to photodissociate \(\mathrm{O}_{2}\) whose bond energy is 495 \(\mathrm{kJ} / \mathrm{mol} ?\) Would it have enough energy to photoionize \(\mathrm{O}_{2} ?\)

The average daily mass of \(\mathrm{O}_{2}\) taken up by sewage discharged in the United States is 59 \(\mathrm{g}\) per person. How many liters of water at 9 ppm \(\mathrm{O}_{2}\) are 50\(\%\) depleted of oxygen in 1 day by a population of \(1,200,000\) people?

The following data were collected for the destruction of \(\mathrm{O}_{3}\) by \(\mathrm{H}\left(\mathrm{O}_{3}+\mathrm{H} \longrightarrow \mathrm{O}_{2}+\mathrm{OH}\right)\) at very low concentrations: $$\begin{array}{lll}{\text { Trial }} & {\left[0_{3}\right](M)} & {[\mathrm{H}](M)} & {\text { Initial Rate }(M / s)} \\ \hline 1 & {5.17 \times 10^{-33}} & {3.22 \times 10^{-26}} & {1.88 \times 10^{-14}} \\ {2} & {2.59 \times 10^{-33}} & {3.25 \times 10^{-26}} & {9.44 \times 10^{-15}} \\\ {3} & {5.19 \times 10^{-33}} & {6.46 \times 10^{-26}} & {3.77 \times 10^{-14}}\end{array}$$ \begin{equation}\begin{array}{l}{\text { (a) Write the rate law for the reaction. }} \\ {\text { (b) Calculate the rate constant. }}\end{array}\end{equation}

Nitrogen oxides like \(\mathrm{NO}_{2}\) and \(\mathrm{NO}\) are a significant source of acid rain. For each of these molecules write an equation that shows how an acid is formed from the reaction with water.

Magnesium ions are removed in water treatment by the addition of slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}\). Write a balanced chemical equation to describe what occurs in this process.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free