If an average \(\mathrm{O}_{3}\) molecule "lives" only \(100-200\) seconds in the stratosphere before undergoing dissociation, how can \(\mathrm{O}_{3}\) offer any protection from ultraviolet radiation?

Short Answer

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Even though individual ozone molecules have a short lifetime of 100-200 seconds in the stratosphere, the ozone layer still effectively protects Earth from harmful ultraviolet (UV) radiation because the formation and dissociation of ozone occur simultaneously. The absorption of UV-C and UV-B radiation by ozone filters out most of the dangerous wavelengths from reaching the Earth's surface and maintains the ozone layer through a continuous process of ozone molecule formation and dissociation. This ensures the ozone layer remains dense enough to shield life on Earth from damaging UV radiation.

Step by step solution

01

Understand ozone formation and dissociation

Ozone is formed in the stratosphere as a result of the interactions between oxygen molecules (O2) and ultraviolet (UV) radiation from the Sun. When high-energy UV-C radiation (100-280 nm) encounters O2, it causes the O2 molecule to dissociate into two separate oxygen atoms (O). These oxygen atoms can then react with other O2 molecules to form ozone (O3). This process can be represented by the following equations: 1. \(O_2 + UV-C \rightarrow 2O\) 2. \(O + O_2 \rightarrow O_3\) Ozone can also dissociate back into oxygen molecules and atoms when it absorbs UV-C or UV-B radiation (280-320 nm), as shown in the following reaction: 3. \(O_3 + UV-C / UV-B \rightarrow O_2 + O\)
02

Explain the protective role of ozone

Ozone in the stratosphere is crucial for life on Earth, as it plays a major role in protecting living organisms from the harmful effects of ultraviolet radiation. The absorption of UV-C and UV-B radiation by ozone effectively filters out most of these dangerous wavelengths from reaching the Earth's surface. When an ozone molecule absorbs UV-C or UV-B radiation, it undergoes dissociation, as described in reaction 3 above. This process not only helps reduce the amount of harmful UV radiation that reaches the Earth, but also releases an oxygen atom, which can then go on to react with other O2 molecules to create more O3, thus maintaining the ozone layer.
03

Discuss how ozone's short lifetime doesn't hinder its protective function

While it's true that individual ozone molecules have a relatively short lifetime in the stratosphere (100-200 seconds), this does not imply that the ozone layer as a whole is ineffective in providing protection from UV radiation. The continuous formation and dissociation of ozone occur simultaneously in the stratosphere. While individual ozone molecules may have a short lifetime, new ozone molecules are constantly being formed as a result of reactions between oxygen atoms and O2 molecules, enabled by the absorption of UV-C radiation. This ongoing process ensures that the ozone layer remains sufficiently dense to absorb and filter out harmful UV radiation, providing crucial protection for life on Earth. In summary, even though individual ozone molecules have short lifetimes, the ozone layer as a whole continues to serve as an effective shield against harmful ultraviolet radiation. The ongoing formation and dissociation of ozone molecules in the stratosphere ensures that the ozone layer remains intact and able to protect living organisms from the damaging effects of UV radiation.

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Most popular questions from this chapter

Draw the Lewis structure for the chlorofluorocarbon \(\mathrm{CFC}-11, \mathrm{CFCl}_{3}\) . What chemical characteristics of this substance allow it to effectively deplete stratospheric ozone?

Alcohol-based fuels for automobiles lead to the production of formaldehyde (CH \(_{2} \mathrm{O} )\) in exhaust gases. Formaldehyde undergoes photodissociation, which contributes to photo-chemical smog: $$\mathrm{CH}_{2} \mathrm{O}+h v \longrightarrow \mathrm{CHO}+\mathrm{H}$$ The maximum wavelength of light that can cause this reaction is 335 \(\mathrm{nm}\) . (a) In what part of the electromagnetic spectrum is light with this wavelength found? (b) What is the maximum strength of a bond, in \(\mathrm{kJ} / \mathrm{mol},\) that can be broken by absorption of a photon of 335 -nm light? (c) Compare your answer from part (b) to the appropriate value from Table \(8.3 .\) What do you conclude about \(\mathrm{C}-\mathrm{H}\) bond energy in formaldehyde? (d) Write out the formaldehyde photodissociation reaction, showing Lewis-dot structures.

Air pollution in the Mexico City metropolitan area is among the worst in the world. The concentration of ozone in Mexico City has been measured at 441 ppb (0.441 ppm). Mexico City sits at an altitude of 7400 feet, which means its atmospheric pressure is only 0.67 atm. (a) Calculate the partial pressure of ozone at 441 ppb if the atmospheric pressure is 0.67 atm. (b) How many ozone molecules are in 1.0 L of air in Mexico City? Assume \(T=25^{\circ} \mathrm{C}\) .

An important reaction in the formation of photochemical smog is the photodissociation of \(\mathrm{NO}_{2} :\) $$\mathrm{NO}_{2}+h \nu \longrightarrow \mathrm{NO}(g)+\mathrm{O}(g)$$ The maximum wavelength of light that can cause this reaction is 420 \(\mathrm{nm}\) . (a) In what part of the electromagnetic spectrum is light with this wavelength found? (b) What is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of \(420-\mathrm{nm}\) light? (c) Write out the photodissociation reaction showing Lewis-dot structures.

The organic anion is found in most detergents. Assume that the anion undergoes aerobic decomposition in the following manner: $$\begin{aligned} 2 \mathrm{C}_{18} \mathrm{H}_{29} \mathrm{SO}_{3}^{-}(a q)+51 \mathrm{O}_{2}(a q) & \longrightarrow \\ & 36 \mathrm{CO}_{2}(a q)+28 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{H}^{+}(a q)+2 \mathrm{SO}_{4}^{2-}(a q) \end{aligned}$$ What is the total mass of \(\mathrm{O}_{2}\) required to biodegrade 10.0 \(\mathrm{g}\) of this substance?

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