Explain, using Le Chatelier's principle, why the equilibrium constant for the formation of NO from \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) increases with increasing temperature, whereas the equilibrium constant for the formation of \(\mathrm{NO}_{2}\) from \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) decreases with increasing temperature.

Short Answer

Expert verified
In summary, the equilibrium constant for the formation of NO from N₂ and O₂ increases with increasing temperature because the reaction is endothermic, and increasing the temperature favors the forward reaction to absorb the added heat. Conversely, the equilibrium constant for the formation of NO₂ from NO and O₂ decreases with increasing temperature because the reaction is exothermic, and increasing the temperature favors the reverse reaction to release heat. This can be understood using Le Chatelier's principle, which states that a system at equilibrium will shift to counteract changes in temperature, pressure, or concentration of reactants or products.

Step by step solution

01

Le Chatelier's Principle

Le Chatelier's principle states that if a system at equilibrium is subjected to a change in temperature, pressure, or concentration of reactants or products, the equilibrium will shift to counteract that change. In the context of temperature, if a reaction is endothermic (requiring heat), increasing the temperature will favor the forward reaction and increase the equilibrium constant. If the reaction is exothermic (releasing heat), increasing the temperature will favor the reverse reaction and decrease the equilibrium constant.
02

Formation of NO (N₂ + O₂ ⇌ 2NO)

Let's analyze the first reaction, the formation of NO from N₂ and O₂: \[N_{2}(g) + O_{2}(g) \rightleftharpoons 2NO(g)\] This reaction is endothermic, which means that it absorbs heat energy from the surroundings. It might be helpful to remember the reaction as: \[N_{2}(g) + O_{2}(g) + heat \rightleftharpoons 2NO(g)\] Now, if we increase the temperature, according to Le Chatelier's principle, the equilibrium will shift to favor the forward reaction to absorb the added heat. As a result, the equilibrium constant (K) for this reaction will increase.
03

Formation of NO₂ (2NO + O₂ ⇌ 2NO₂)

Now let's analyze the second reaction, the formation of NO₂ from NO and O₂: \[2NO(g) + O_{2}(g) \rightleftharpoons 2NO_{2}(g)\] This reaction is exothermic, which means that it releases heat energy to the surroundings. It might be helpful to remember the reaction as: \[2NO(g) + O_{2}(g) \rightleftharpoons 2NO_{2}(g) + heat\] If we increase the temperature in this case, according to Le Chatelier's principle, the equilibrium will shift to favor the reverse reaction in order to release heat. As a result, the equilibrium constant (K) for this reaction will decrease.
04

Conclusion

Based on our analysis, we can conclude that: 1. The equilibrium constant for the formation of NO from N₂ and O₂ increases with increasing temperature because it is an endothermic reaction, and increasing the temperature favors the forward reaction. 2. The equilibrium constant for the formation of NO₂ from NO and O₂ decreases with increasing temperature because it is an exothermic reaction, and increasing the temperature favors the reverse reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant, represented as K, is a numerical value that characterizes the ratio of concentrations of products to reactants at chemical equilibrium for a reversible reaction. It is a specific value at a given temperature and remains constant unless the temperature changes. For example, in the formation of nitrogen monoxide (NO), the equilibrium constant increases with temperature because the reaction is endothermic; it absorbs heat, shifting the equilibrium towards the products.

Similarly, for energy-releasing (exothermic) reactions, such as the formation of nitrogen dioxide (NO2), the equilibrium constant decreases with an increase in temperature. This relationship between the equilibrium constant and temperature is a direct consequence of Le Chatelier's principle.
Endothermic Reactions
Endothermic reactions are chemical processes which absorb thermal energy from their surroundings, causing the surrounding temperature to decrease. These reactions require heat as a reactant, and as per Le Chatelier's principle, when the temperature is increased, the system adjusts by shifting the equilibrium to the right (toward the products) to consume the excess heat. This shift results in a higher yield of products and, consequently, an increase in the equilibrium constant (K).

Practical Application

Understanding endothermic reactions is essential, not just for predicting the effects of temperature changes in chemical processes, but also for practical applications such as cooling systems and thermal energy storage.
Exothermic Reactions
Exothermic reactions are the opposite of endothermic reactions; they release heat into the environment, which often results in an increase in the surrounding temperature. Heat is a product of these reactions, and an increase in temperature causes the equilibrium to shift to the left (toward the reactants), according to Le Chatelier's principle, in order to absorb the added heat. This shift decreases the amount of products formed and lowers the equilibrium constant (K).

Practical Application

Exothermic reactions are fundamental in everyday life, powering everything from internal combustion engines to heat generation in our homes.
Chemical Equilibrium
Chemical equilibrium occurs in a reversible reaction when the rates of the forward and reverse reactions are equal, leading to no net change in the concentrations of reactants and products over time. At equilibrium, the chemical system is stable, but it's not static. It dynamically responds to changes in conditions such as temperature, pressure, and concentration. The concept of chemical equilibrium is pivotal to understanding how reactions can be shifted to favor the formation of products or reactants, which is particularly useful in industrial chemical processes.

However, remember that reaching equilibrium doesn't mean the reactants and products are present in equal amounts, but that their ratios are fixed and defined by the equilibrium constant for the reaction at a specific temperature.
Temperature Effects on Equilibrium
Temperature can significantly impact chemical equilibrium. An increase in temperature shifts the equilibrium position of an endothermic reaction to the right, favoring product formation and resulting in a higher equilibrium constant. Conversely, for exothermic reactions, an increase in temperature shifts the equilibrium to the left, favoring the reactants and leading to a lower equilibrium constant. These temperature-related shifts are a direct application of Le Chatelier's principle, which is essential for controlling and optimizing industrial chemical processes, including energy production and manufacturing of materials.

In summary, understanding how temperature influences chemical equilibrium is crucial for predicting the behavior of reactions and for the safe and efficient operation of chemical systems.

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Most popular questions from this chapter

One mystery in environmental science is the imbalance in the "carbon dioxide budget." Considering only human activities, scientists have estimated that 1.6 billion metric tons of \(\mathrm{CO}_{2}\) is added to the atmosphere every year because of deforestation (plants use \(\mathrm{CO}_{2},\) and fewer plants will leave more \(\mathrm{CO}_{2}\) in the atmosphere). Another 5.5 billion tons per year is put into the atmosphere because of burning fossil fuels. It is further estimated (again, considering only human activities) that the atmosphere actually takes up about 3.3 billion tons of this \(\mathrm{CO}_{2}\) per year, while the oceans take up 2 billion tons per year, leaving about 1.8 billion tons of \(\mathrm{CO}_{2}\) per year unaccounted for. Describe a mechanism by which \(\mathrm{CO}_{2}\) is removed from the atmosphere and ultimately ends up below the surface (Hint: What is the source of the fossil fuels?) [Sections \(18.1-18.3 ]\)

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